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Collision Theory, Energy of Activation - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Collision Theory, Energy of Activation (20 Questions)

You can prepare effectively for JEE Chemistry for JEE Main & Advanced with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Collision Theory, Energy of Activation". These 20 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 20

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Test: Collision Theory, Energy of Activation - Question 1

A first order reaction is half-completed in 45 minutes. How long does it need for of the reaction to be completed?

Detailed Solution: Question 1

further

hours.

Test: Collision Theory, Energy of Activation - Question 2

 At a certain temperature, the first order rate constant k1 is found to be smaller than the second order rate constant k2. If the energy of activation E1 of the first order reaction is greater than energy of activation E2 of the second order reaction, then with increase in temperature.

Detailed Solution: Question 2

Test: Collision Theory, Energy of Activation - Question 3

A reaction which is of first order w.r.t. reactant , has a rate constant . If we start with , when would [A] reach the value of

Detailed Solution: Question 3


Test: Collision Theory, Energy of Activation - Question 4

The rate of a first order reaction is at concentration of the reactant. The halflife of the reaction is

Detailed Solution: Question 4

For a first order reaction, Products
or

Further,

Test: Collision Theory, Energy of Activation - Question 5

For a first order reaction the reaction rate at reactant concentration of is found to be . The half life period of the reaction is

Detailed Solution: Question 5

Given
Rate
For a first order reaction Rate

Test: Collision Theory, Energy of Activation - Question 6

A reaction proceeds by first order, of this reaction was completed in 32 min. The time required for completion is

Detailed Solution: Question 6

Given: reaction gets completed in 32
Thus,


Now we can use this value of to get the value of time required for completion of reaction

Test: Collision Theory, Energy of Activation - Question 7

In the reaction , rate constant is . If we start with of A then conc. of and B after 10 minuter are respectively.

Detailed Solution: Question 7



Test: Collision Theory, Energy of Activation - Question 8

The half life for the virus inactivation if in the beginning of the virus is inactivated per minute is (Given: The reaction is of first order)

Detailed Solution: Question 8

For the first order reaction for small finite change


Test: Collision Theory, Energy of Activation - Question 9

At , if the rate constant of a first order reaction is , the time to reduce the initial concentration of the reactant to in seconds is :

Detailed Solution: Question 9

To find the time taken for the concentration of the reactant to reduce to th, we use the formula:

Given , we have:

Solving for , we get approximately 500 seconds.

Test: Collision Theory, Energy of Activation - Question 10

The rate constant of a reaction with a virus is . Time required for the virus to become inactivated is

Detailed Solution: Question 10


Test: Collision Theory, Energy of Activation - Question 11

A Geigger Muller counter is used to study the radioactive process. In the absence of radioactive substance , it counts 3 disintegration per second (dps). At the start in the presence of , it records 23 dps; and after 10 min 13 dps,
(i) What does it count after
(ii) What is the halflife of A?

Detailed Solution: Question 11

In the absence of dps is zero error, hence
Initial count
After
After
recorded
(50\% fall in

Test: Collision Theory, Energy of Activation - Question 12

The rate equation for a reaction,

is Rate . If the initial concentration of the reactant is mol , the half-life period of the reaction is

Detailed Solution: Question 12

For a zero order reaction

Test: Collision Theory, Energy of Activation - Question 13

Half-lives of first-order and zeroth order reactions are same. Ratio of rates at the start of nreaction is

Detailed Solution: Question 13

zeroth
first


Test: Collision Theory, Energy of Activation - Question 14

The plot of concentration of the reactant Vs time for a reaction is a straight line with a negative slope. The reaction follows a rate equation of

Detailed Solution: Question 14

Plots of conc. [A] Vs time, t

Test: Collision Theory, Energy of Activation - Question 15

The reaction is started with of L. After 30 and 90 minutes and of respectively are left. The order of the reaction is

Detailed Solution: Question 15

After every 30 minutes the amount is reduced to therefore is 30 minutes. In 90 minutes the amount is reduced to i.e. Here True for 1st order reaction.

Test: Collision Theory, Energy of Activation - Question 16

The plot that represents the zero order reaction is:

Detailed Solution: Question 16

For a zero order, rate of reaction does not change with time.

Test: Collision Theory, Energy of Activation - Question 17

For a first order reaction, a plot of log(a−x) against time is a straight line with a negative slope equal to

Detailed Solution: Question 17


or

Test: Collision Theory, Energy of Activation - Question 18

In the presence of an acid, the initial concentration of cane sugar was reduced from to in 5 hours and from to in 10 hours. The reaction is of :

Detailed Solution: Question 18

Test: Collision Theory, Energy of Activation - Question 19

For the decomposition of at , the following data were obtained

The order of reaction is :

Detailed Solution: Question 19




Dividing eq. (i) by eq. (ii),

Test: Collision Theory, Energy of Activation - Question 20

The hypothetical reaction follows the following mechanism , The order of the overall reaction is

Detailed Solution: Question 20

;
(Fast);
(Slow)
Rate law put value of from Ist reaction since is intermediate

Rate law equation
Order

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