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CTET & State TET Exam  >  CTET & State TET Tests  >  Mathematics & Pedagogy Paper 2 for CTET & TET Exams  >  Test: Construction Of Triangles - CTET & State TET MCQ

Test: Construction Of Triangles - CTET & State TET MCQ


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10 Questions MCQ Test Mathematics & Pedagogy Paper 2 for CTET & TET Exams - Test: Construction Of Triangles

Test: Construction Of Triangles for CTET & State TET 2024 is part of Mathematics & Pedagogy Paper 2 for CTET & TET Exams preparation. The Test: Construction Of Triangles questions and answers have been prepared according to the CTET & State TET exam syllabus.The Test: Construction Of Triangles MCQs are made for CTET & State TET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Construction Of Triangles below.
Solutions of Test: Construction Of Triangles questions in English are available as part of our Mathematics & Pedagogy Paper 2 for CTET & TET Exams for CTET & State TET & Test: Construction Of Triangles solutions in Hindi for Mathematics & Pedagogy Paper 2 for CTET & TET Exams course. Download more important topics, notes, lectures and mock test series for CTET & State TET Exam by signing up for free. Attempt Test: Construction Of Triangles | 10 questions in 10 minutes | Mock test for CTET & State TET preparation | Free important questions MCQ to study Mathematics & Pedagogy Paper 2 for CTET & TET Exams for CTET & State TET Exam | Download free PDF with solutions
Test: Construction Of Triangles - Question 1
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In triangle ABC, altitude BE = altitude CF. Then triangle ABC is

Test: Construction Of Triangles - Question 2
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To construct a ΔABC in which BC = 10 cm and ∠B= 60 degrees and AB + AC = 14 cm, then the length of BD used for construction.

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Test: Construction Of Triangles - Question 3
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Which of these triangles are possible to construct by knowing only its altitude?

Test: Construction Of Triangles - Question 4
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The construction of a triangle ABC, given that BC = 6 cm, B = ∠45° is not possible when difference of AB and AC is equal to :​
Detailed Solution for Test: Construction Of Triangles - Question 4

Given, BC = 6 cm and ∠B= 45°
We know that, the construction of a triangle is not possible, if sum of two sides is less than or equal to the third side of the triangle.
i.e., AB + BC < AC
⇒ BC < AC – AB
⇒  6 < AC-AB
So, if AC – AB= 6.9 cm, then construction of ΔABC with given conditions is not possible.

Test: Construction Of Triangles - Question 5
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Choose the correct statement
Test: Construction Of Triangles - Question 6
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The point of concurrence of the three angle bisectors of a triangle, is called
Detailed Solution for Test: Construction Of Triangles - Question 6
The point of interection of
medians - centroid
altitude - orthocentre
angle bisector - incentre
perpendicular bisectors - circumcentre
Test: Construction Of Triangles - Question 7
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In triangle ABC, side AB is produced to D so that BD = BC. If angle B = 60° and angle A = 70°, then
Detailed Solution for Test: Construction Of Triangles - Question 7
in this particular given problem angle 
corresponding to the sides 
ad : angle A
CDcd : angle CAB
as, angle ACD > angle CAB, So
ad>cd
Test: Construction Of Triangles - Question 8
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The point of intersection of the perpendicular bisectors of the sides of a triangle is called
Detailed Solution for Test: Construction Of Triangles - Question 8
The perpendicular bisectors of the sides of a triangle intersect at a point called the circumcenter of the triangle, which is equidistant from the vertices of the triangle.
Test: Construction Of Triangles - Question 9
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To construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. We draw line segment AB of 12 cm. Draw a ray AX making 90° with AB. The next step is:
Detailed Solution for Test: Construction Of Triangles - Question 9

The below given steps will be followed to construct the required triangle.

Step I:
Draw line segment AB of 12 cm. Draw a ray AX making 90deg with AB.
Step II:
Cut a line segment AD of 18 cm (as the sum of the other two sides is 18) from ray AX.
Step III:
Join DB and make an angle DBY equal to ADB.
Step IV:
Let BY intersect AX at C. Join AC, BC.

ΔABC is the required triangle.

Test: Construction Of Triangles - Question 10
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The lengths of the sides of some triangles are given, which of them is not a right angled triangle?
Detailed Solution for Test: Construction Of Triangles - Question 10
If a triangle is right angle then it must satisfy Pythagoras theorem

Now let us check whether all options satisfy it or not....

a) 5^2+12^2=169

5^2+12^2=13^2


b) 5^2+8^2 is not equal to 10^2


c) 3^2+4^2=5^2

d) 7^2+24^2=25^2


It is clear that 2nd option doesn't satisfy Pythagoras theorem...soo option 2 is the answer
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