Decimals- 2 - Free MCQ Practice Test with solutions, Class 5 Mathematics

A fraction and a decimal for the part of the school that consists of boys are

To divide a decimal by 100, move the decimal point two places to the left.

Moving the decimal in 929.5 one place left gives 92.95; moving it a second place left gives 9.295.

Written as fractions: 929.5 = 9295/10, so 929.5 ÷ 100 = 9295/10 ÷ 100 = 9295/1000 = 9.295.

Hence the value is 9.295, so the correct option is D.

Multiplying a number by 10 shifts the decimal point one place to the right.
So, 2.1143 × 10 = 21.143.
Therefore the value is 21.143, option B.

Given expression:

2000 + 200 + 20 + 2 + ²⁄₁₀ + ²⁄₁₀₀ + ²⁄₁₀₀₀ + ²⁄₁₀₀₀₀

Step 1: Add the whole numbers first:

2000 + 200 + 20 + 2 = 2222

Step 2: Convert the fractional parts into decimal form:

• ²⁄₁₀ = 0.2
• ²⁄₁₀₀ = 0.02
• ²⁄₁₀₀₀ = 0.002
• ²⁄₁₀₀₀₀ = 0.0002

Step 3: Sum the decimal parts:

0.2 + 0.02 + 0.002 + 0.0002 = 0.2222

Step 4: Add this to the sum of whole numbers:

2222 + 0.2222 = 2222.2222

Therefore, the value of the expression is 2222.2222, which corresponds to option B.

Required number

We need a number x such that 727.111 ÷ x = 7.27111.

Dividing by 10 moves the decimal point one place to the left; dividing by 100 moves it two places to the left and so on.

If we divide 727.111 by 100, the decimal point moves two places left: 727.111 ÷ 100 = 7.27111.

Hence x = 100.

Correct Option: B

Given:
Flour bought = 5 kg
Flour used = 2.25 kg
Amount of flour left = 5 − 2.25 = 2.75 kg

Sugar bought = 3.5 kg
Sugar used = 0.75 kg
Amount of sugar left = 3.5 − 0.75 = 2.75 kg

The total rainfall over the first five days was calculated by adding the daily rainfall:

• Day 1: 1.27 cm
• Day 2: 3.25 cm
• Day 3: 2.79 cm
• Day 4: 2.57 cm
• Day 5: 1.37 cm

Adding these values gives a total (1.27 + 3.25 + 2.79 + 2.57 + 1.37) cm = 11.25 cm of rain.

Solution:

• Each curtain requires 2.5 m of cloth.
• Mrs. Radha Puri ordered 25 curtains.
• Total cloth needed = 2.5 m x 25 = 62.5 m.

1m = 1000 km
∴