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Test: Digital Logic - 2 - Computer Science Engineering (CSE) MCQ


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10 Questions MCQ Test GATE Computer Science Engineering(CSE) 2025 Mock Test Series - Test: Digital Logic - 2

Test: Digital Logic - 2 for Computer Science Engineering (CSE) 2024 is part of GATE Computer Science Engineering(CSE) 2025 Mock Test Series preparation. The Test: Digital Logic - 2 questions and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus.The Test: Digital Logic - 2 MCQs are made for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Digital Logic - 2 below.
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Test: Digital Logic - 2 - Question 1

Which number system has a base 16

Detailed Solution for Test: Digital Logic - 2 - Question 1

Hexadecimal is a number system with a base 16. We can divide the word HEXA+DECIMAL for better understanding; it means 6 and 10 make 16.
It is the easiest way to write and count numbers represented in terms of base 16.
There are sixteen distinct digits in the hexadecimal system, it starts from 0, 1,2,3,4,5,6,7,8,9, A, B, C, D, E and end to F.
Where A= 10, B=11, C=12, D=13, E=14, F=15.
It is usually represented by 4 bits in binary number system by 8421 code.

Test: Digital Logic - 2 - Question 2

The following hexadecimal number (1E.43)16 is equivalent to

Detailed Solution for Test: Digital Logic - 2 - Question 2

If you want to convert a hexadecimal number into an octal number, the first thing you need to do is convert a hexadecimal number into binary form by writing the binary equivalent of each digit in the form of 4 bits. Once you write the number into binary form, you need to group the binary equivalent in 3 bits, then for each of the three bits, the respective digit is written.

(1E.43)16 = (0001 1110.0100 0011)2

= (00011110.01000011)2

= (011110.010000110)2

= (011 110.010 000 110)2

= (36.206)8

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Test: Digital Logic - 2 - Question 3

How many bits are needed to store one BCD digit?

Detailed Solution for Test: Digital Logic - 2 - Question 3

BCD stands for Binary Coded Decimal. It is a type of binary encoding where each decimal digit is represented by a fixed number of bits, usually 4. It is also called 8421 code to represent the maximum number 15. BCD can encode only from 0-9. For example, Decimal number 456, its equivalent BCD code is 0100 0101 0110

Test: Digital Logic - 2 - Question 4

A SCR (Silicon Controlled Rectifier) is a

Detailed Solution for Test: Digital Logic - 2 - Question 4

SCR stands for Silicon Controlled Rectifier; it is a family of thyristors with the same property as thyristors. It is a semiconductor device with three junctions. They are of two types: npnp and pnpn. For the pnpn type, the inner player has a gate terminal, the outer player has an anode terminal, and the outer n layer has a cathode terminal. The SCR controls the flow of anode current once the gate is triggered.

Test: Digital Logic - 2 - Question 5

Which of these sets of logic gates are known as universal gates?

Detailed Solution for Test: Digital Logic - 2 - Question 5

NAND or NOR gates are used to design all other logic gates, so; they are termed universal gates.

Test: Digital Logic - 2 - Question 6

In the toggle mode, a JK flip-flop has

Detailed Solution for Test: Digital Logic - 2 - Question 6

Toggling means switching between the two states when output changes to its complement on applying clock signal. For example, suppose you assume the initial output to be X (1 or 0), then after toggling, the output state will be X' (0 or 1, respectively). Both j and k should be 1 for toggle in JK flip flop.

Test: Digital Logic - 2 - Question 7

A classification of integrated circuits with complexities of 30 to 300 equivalent gates on a single chip is known as?

Detailed Solution for Test: Digital Logic - 2 - Question 7

The terminologies like MSI, SSI, LSI and VLSI came out from the complexity of the integrated circuit. It means the total number of transistors are fabricated on a single chip. Jack Kilby invented the first integrated circuit in 1959, so, after that, the Integrated circuit has emerged like SSI, LSI, MSI and VLSI.

In MSI (Medium Scale Integration) = 30 - 300 gates /chip (counters, multiplexers, registers)

In LSI (Large Scale Integration) = 300 - 3000 gates /chip (8-bit processors)

In SSI (Small-Scale Integration) = 3 - 30 gates /chip (logic gates, flip flops)

In VLSI (Very Large-Scale Integration) = >3000 gates / chip (16 bit and 32- bit processors)

Test: Digital Logic - 2 - Question 8

In an 8 -bit Johnson counter sequence, how many states orbit patterns are possible?

Detailed Solution for Test: Digital Logic - 2 - Question 8

As we know, the total number of states in the Jhonson counter is determined by the given formula

2N = 2 8= 256

Now,

the total number of used states = 2N = 2* 8 = 16

therefore, the total number of unused states = 256-16 = 240

Test: Digital Logic - 2 - Question 9

If a transistor has IC = 110 mA and IE = 55 mA, find the value of β?

Detailed Solution for Test: Digital Logic - 2 - Question 9

In common emitter, the term β stands for current gain. Current gain refers to the ratio between collector current and base current at a constant VCE.

β = IC/IB

In the common base, DC gain α refers to the ratio of the collector current IC and the emitter current IE.

The equation of dc current gain

α = IC/IE

Now, we can establish the relationship between α and β

β = α/ (1 - α)

Given

Emitter current I= 55 mA

Collector current IC = 110 mA

α = IC/I= 110/55 = 2

β = α/ (1 - α) = 2/ (1 - 2)

β = -2

Here the negative value of β indicates its direction, because by convention positive current is always termed as flowing into the device. So, the current gain is negative.

Test: Digital Logic - 2 - Question 10

At which frequency the digital data can be applied to a gate?

Detailed Solution for Test: Digital Logic - 2 - Question 10

The operating frequency refers to the frequency at which the communications are being made with the total bandwidth occupied by the carrier signal with modulation.

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