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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Electromagnetic Fields Theory (EMFT)  >  Test: Electric Potential - Electrical Engineering (EE) MCQ

Test: Electric Potential - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) - Test: Electric Potential

Test: Electric Potential for Electrical Engineering (EE) 2024 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Electric Potential questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Electric Potential MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Electric Potential below.
Solutions of Test: Electric Potential questions in English are available as part of our Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) & Test: Electric Potential solutions in Hindi for Electromagnetic Fields Theory (EMFT) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Electric Potential | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Electric Potential - Question 1
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Potential difference is the work done in moving a unit positive charge from one point to another in an electric field. State True/False.

Detailed Solution for Test: Electric Potential - Question 1

Answer: a
Explanation: The electric potential is the ratio of work done to the charge. Also it is the work done in moving a unit positive charge from infinity to a point in an electric field.

Test: Electric Potential - Question 2
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A point charge 2nC is located at origin. What is the potential at (1,0,0)?

Detailed Solution for Test: Electric Potential - Question 2

Answer: d
Explanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9)/(4πε x 1) = 18 volts

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Test: Electric Potential - Question 3
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Six equal point charges Q = 10nC are located at 2,3,4,5,6,7m. Find the potential at origin.

Detailed Solution for Test: Electric Potential - Question 3

Answer: d
Explanation: V = (1/4πεo) ∑Q/r = (10 X 10-9/4πεo)
(0.5 + 0.33 + 0.25 + 0.2 + 0.166 + 0.142) = 143.35 volts.

Test: Electric Potential - Question 4
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A point charge 0.4nC is located at (2, 3, 3). Find the potential differences between (2, 3, 3)m and (-2, 3, 3)m due to the charge.
Detailed Solution for Test: Electric Potential - Question 4

Answer: c
Explanation: Vab = (Q/4πεo)(1/rA) + (1/rB), where rA and rB are position vectors rA = 1m and rB = 4m. Thus Vab = 2.7 volts.

Test: Electric Potential - Question 5
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Find the potential of V = 60sin θ/r2 at P(3,60,25)
Detailed Solution for Test: Electric Potential - Question 5

Answer: a
Explanation: V = 60sin θ/r2, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.

Test: Electric Potential - Question 6
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Given E = 40xyi + 20x2j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3).
Detailed Solution for Test: Electric Potential - Question 6

Answer: b
Explanation: V = -∫ E.dl = -∫ (40xy dx + 20x2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get Vpq on integrating from Q to P. Vpq = 106 volts.

Test: Electric Potential - Question 7
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The potential difference in an open circuit is
Detailed Solution for Test: Electric Potential - Question 7

Answer: c
Explanation: In an open circuit no current exists due to non-existence of loops. Also voltage/potential will be infinity in an open circuit.

Test: Electric Potential - Question 8
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The potential taken between two points across a resistor will be
Detailed Solution for Test: Electric Potential - Question 8

Answer: b
Explanation: The resistor will absorb power and dissipate it in the form of heat energy. The potential between two points across a resistor will be negative.

Test: Electric Potential - Question 9
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What is the potential difference between 10sinθcosφ/r2 at A(1,30,20) and B(4,90,60)?
Detailed Solution for Test: Electric Potential - Question 9

Answer: c
Explanation: Potential at A, Va = 10sin30cos20/12 = 4.6985 and Potential at B, Vb = 10sin90cos60/42 = 0.3125. Potential difference between A and B is, Vab = 4.6985 – 0.3125 = 4.386 volts.

Test: Electric Potential - Question 10
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The voltage at any point in an ac circuit will be
Detailed Solution for Test: Electric Potential - Question 10

Answer: b
Explanation: In any ac circuit, the voltage measured will not be exact maximum. In order to normalise, we assume the instantaneous voltage at any point be 70.7% of the peak value, which is called the root mean square (RMS)voltage.

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