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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - JEE MCQ
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15 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 1
A device that converts energy of combustion of fuels like hydrogen and methane, directly into electrical energy is known as:
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 2
Schematic diagram of an electrolytic cell is
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 3
The metal that can not be obtained by electrolysis of an aqueous solution of its salt is
[JEE Main 2014]
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 4
A concentration cell is a galvanic cell in which
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 5
How long a current of 3 amperes has to be passed through a solution of 
to coat a metal surface of 
and 
thick layer. Density of 
is 
to coat a metal surface of and thick layer. Density of is
Detailed Solution for Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 5
Area 
thickness
Volume 
density
Mass of 
to be deposited
seconds
Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 6
In which of the following cells, the space between cathode and anode is filled by a moist mixture of ammonium choride and zinc chloride?
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 7
Which colourless gas evolves, when 
reacts with zinc in a dry cell battery
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 8
The e.m.f. of a Daniell cell at 298 K is 
When the concentration of ZnSO4 is 1.0M and that of CuSO4 is 0.01M, the e.m.f. changed to E2. What is the relationship between E1 and E2 ?
Detailed Solution for Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 8
, less is the EMF Hence 
Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 9
of pure silver was converted into silver nitrate and its solution was taken in a beaker. It was electrolysed using platinum cathode and silver anode. 
Faraday of electricity was passed using 
volt above the decomposition potential of silver. The silver content of the beaker after the above shall be
Detailed Solution for Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 9
mole of electrons 
left 
Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 10
The 
acts as sacrificial or cathodic protection to prevent rusting of iron because :
acts as sacrificial or cathodic protection to prevent rusting of iron because :
Detailed Solution for Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 10
of 
of 
Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 11
Two half cells have reduction potentials 
and 
respectively. A galvanic cell is made from these two half cells. Which of the following statements is correct?
and respectively. A galvanic cell is made from these two half cells. Which of the following statements is correct?
Detailed Solution for Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 11
Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 12
Aqueous solution of which of the following compounds is the best conductor of electric current?
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completely dissociates to give 
and 
ions, hence act as very good electrolyte. While others are non- electrolytes.
Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 13
A hydrogen gas electrode is made by dipping platinum wire in a solution of 
of 
and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be ?
of and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be ?
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Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 15
In the silver plating of copper, 
is used instead of 
. The reason is
is used instead of . The reason is
Detailed Solution for Test: Electrolysis & Faraday's Laws, Kohlrausch’s Law - Question 15
is used instead of 
. Copper being more electropositive readily precipitate silver from their salt solution
solution a complex anion 
is formed and hence 
are less available in the solution and therefore copper cannot displace Ag from its complex ion.|
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