Test: Electronic configuration, Quantum Mechanical Model - JEE MCQ

to , through zero thus for values of will be
Therefore for cannot have the value

The greater is the value of , the greater is the energy of orbitals.
(a) n = 4, l = 1 ⇒ 4p orbital
(b) n = 4, l = 0 ⇒ 4 s orbital
(c) n = 3, l = 2 ⇒ 3d orbital
(d) n = 3, l = 1 ⇒ 3p orbital
According to the Aufbau principle, energies of above-mentioned orbitals are in the order of-
The increasing order of energy (d) 3p < (b) 4 s < (c) 3 d < (a) 4p
So, (d) < (b) < (c) < (a) is correct order.

waves shown in figure has higher wavelength in comparison to waves shown in figure .
Thus these waves also differ in frequency and energy. 

represent orbital for which

Possible values of and depend upon the value of
to
to through zero
and
Thus for
may be 0,1 or but not 3
m may be or
may or

has 14 protons, i.e.,
also has 14 protons and therefore 14 electrons.

electrons

For 4p electron n = 4,1 = 1, m = −1,0+1 and S = +1/2 or −1/2

According to Aufbau principle electron are filled in various atomic orbitals in the increasing order of energy:
1 s < 2 s < 2p < 3 s < 3p < 4 s < 3 d < 4p < 5 s < 4 d < 5p < 6 s < 4f < 5 d < 6p < 7 s

Electronic configuration of
So number of unpaired elctrons is
Hence, 
Now,
Electronic configuration of
So number of unpaired electros is
Hence, 
So, Ratio of Magnetic moments of and is: 

The function R depends on the quantum numbers n and l, the function Θ depends on l and |m| and the function Φ depends on m.

The next electron will enter into 5d subshell
whose (n+l) value is equal to 7.