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Test: General Frequency Consideration - Electronics and Communication Engineering (ECE) MCQ


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11 Questions MCQ Test Analog Circuits - Test: General Frequency Consideration

Test: General Frequency Consideration for Electronics and Communication Engineering (ECE) 2024 is part of Analog Circuits preparation. The Test: General Frequency Consideration questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: General Frequency Consideration MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: General Frequency Consideration below.
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Test: General Frequency Consideration - Question 1

The frequency f1 and f2 from the below picture are respectively called​

Detailed Solution for Test: General Frequency Consideration - Question 1

 The frequencies are called lower cut-off frequency and upper cut-off frequency because at these frequencies power of the signal becomes half of its original value. So they are also called 3dB cut-off frequencies.

Test: General Frequency Consideration - Question 2

 Bandwidth of amplifier is

Detailed Solution for Test: General Frequency Consideration - Question 2

3dB bandwidth of an amplifier is the difference between upper cut-off frequency and lower cut-off frequency. The unity gain bandwidth is the difference between frequencies were gain is 1.

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Test: General Frequency Consideration - Question 3

At 3dB cut-off frequency the voltage gain will be

Detailed Solution for Test: General Frequency Consideration - Question 3

3dB cut-off frequency is the frequency at which the power becomes half of its maximum value. That is the voltage gain becomes 0.707 times maximum voltage gain.

Test: General Frequency Consideration - Question 4

At 3dB cut-off frequencies power will be

Detailed Solution for Test: General Frequency Consideration - Question 4

 3dB cut-off frequency is the frequency at which the power becomes half of its maximum value. That is the voltage gain becomes 0.707 times maximum voltage gain. The importance of 3dB points is that for a human ear, it will not notice the fall in power of the signal up to 50% of maximum power.

Test: General Frequency Consideration - Question 5

A voltage amplifier has a voltage gain of 100.What will be gain at 3dB cut-off frequencies

Detailed Solution for Test: General Frequency Consideration - Question 5

3dB cut-off frequency is the frequency at which the power becomes half of its maximum value. That is the voltage gain becomes 0.707 times maximum voltage gain. Therefore if voltage gain is 100 then gain at 3dB frequencies will be
100 x 0.707 = 70.7.

Test: General Frequency Consideration - Question 6

What is the roll-off rate of single order filter

Detailed Solution for Test: General Frequency Consideration - Question 6

 At lower and higher frequencies the gain is decreasing. This fall or decrease in gain is known as roll-off rate. It is commonly specified in dB/octave or dB/decade. For a single order filter the roll-off rate is 6dB/octave or 20dB/decade.

Test: General Frequency Consideration - Question 7

 -6dB is equivalent to __________ power gain

Detailed Solution for Test: General Frequency Consideration - Question 7

The relation between dB and power gain is
dB = 10 log(power gain)
That is power gain for -6dB is
10(-6 /10) = 0.251.

Test: General Frequency Consideration - Question 8

Voltage gain of 1,00,000 is equivalent to

Detailed Solution for Test: General Frequency Consideration - Question 8

dB = 20 log(voltage gain)
Therefor 100000 voltage gain is equivalent to
20 log(1,00,000)dB = 100 dB.

Test: General Frequency Consideration - Question 9

If the output power from an audio amplifier is measured at 100W when the signal frequency is 1kHz, and 1W when the signal frequency is 10kHz. Calculate the dB change in power.

Detailed Solution for Test: General Frequency Consideration - Question 9

The initial power gain in dB = 10 log (output power)
= 10 log(100) = 20dB
The final power gain in dB = 10 log(output power)
= 10 log(1) = 0 dB
So change in power = final power – initial power
= 0-20 = -20dB.

Test: General Frequency Consideration - Question 10

If the output power from an audio amplifier is measured at 100W when the signal frequency is 1kHz, and 1W when the signal frequency is 10kHz. Calculate the dB change in power.

Detailed Solution for Test: General Frequency Consideration - Question 10

The initial power gain in dB = 10 log (output power)
= 10 log(100) = 20dB
The final power gain in dB = 10 log(output power)
= 10 log(1) = 0 dB
So change in power = final power – initial power
= 0-20 = -20dB.

Test: General Frequency Consideration - Question 11

 If an electronic system produces a 48mV output voltage when a 12mV signal is applied, calculate the decibel value of the systems output voltage gain

Detailed Solution for Test: General Frequency Consideration - Question 11

Gain of the system is = output voltage/input voltage
= 48/12 = 4
Gain in dB = 20 log(voltage gain)
= 20 log(4) = 12.04 dB.

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