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Heat Exchanger Level - 2 - Free MCQ Practice Test with solutions, GATE


MCQ Practice Test & Solutions: Test: Heat Exchanger Level - 2 (10 Questions)

You can prepare effectively for Mechanical Engineering Heat Transfer with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Heat Exchanger Level - 2". These 10 questions have been designed by the experts with the latest curriculum of Mechanical Engineering 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Heat Exchanger Level - 2 - Question 1

In a counter flow heat exchanger, the working parameters for hot fluid are as follows: heat capacity = 2 kJ/kg K, mass flow inlet temperature 150oC , outlet temperature 100oC. For the cold fluid, the parameters are: heat capacity = 4 kJ/kg K, - mass flow rate 10 kg/s, and inlet temperature is = 20oC. The outlet temperature of the cold fluid in oC is

Detailed Solution: Question 1

From steady state flow energy equation

mhcph(Thi - The) = mccpc(Tce - Tci)

∴ 5 x 2000(150 -100) = 10 x 4000(Tce - 20)

Tce = 32.5oC

Test: Heat Exchanger Level - 2 - Question 2

Cold water at 10oC enters a counter flow heat exchanger at a rate of 8 kg/s , where it is heated by a hot water that enters the heat exchanger at 70oC and flows at a rate of 2kh/s . Assume specific heat of water to be cp = 4.18 kJ/kgoC . Determine the maximum theoretical heat transfer rate?

Detailed Solution: Question 2

Given mh = 2 kg/s

Mc = 8 kg/s

cph = cpc = 4.18kj/kgo-C

∴ mhcph 2 x 4.18 = 8.36 kW/oC

mhcph 8 x 4.18 = 33.4 kW/oC

∴ mhcph <>ccpc

For maximum heat exchanger rate,

Qmax = (mcp)min(Thi - Tci)

⇒ Qmax = 8.36(70-10)

⇒ Qmax = 501.6 kW

Test: Heat Exchanger Level - 2 - Question 3

A cross flow type air heater has an area of 50 m2. The overall transfer coefficient 100 W/m2 -and heat capacity of both hot and cold streams is 1000 W/K. The value of NTU is

Detailed Solution: Question 3

By definition

NTU = UA/(mcp)min

In the given situation, both capacity rate (mcp) of both hot and cold fluid are equal

∴ NTU = 100 x 50/1000 = 5

Test: Heat Exchanger Level - 2 - Question 4

The overall heat transfer coefficient for a shell and tube heat exchanger for clean surfaces is Uo = 400 W/m2- K. The fouling factor after one year of operation is found to be hfo = 200 W/m2 -K. The overall heat transfer coefficient at this time is

Detailed Solution: Question 4

Given Uo = 400 W/m2- K

Fouling factor, hFO = 200 W/m2-K

∴ New overall heat transfer coefficient can be predicted as follows

1/U = 1/U+1/hFO

1/U = 1/400 + 1/200

U = 33.33 W/m2-K

Test: Heat Exchanger Level - 2 - Question 5

In a solar assisted air conditioning system, 1 kg/sec of ambient air is to be preheated by the same amount of air leaving the system. A counter-flow heat exchanger having an area of 60m2 with overall heat transfer coefficient of 25 W/m2 - K is used for this purpose. Assuming for air is 1kJ/kg K. The effectiveness of the heat exchanger is

Detailed Solution: Question 5

This is the case of a balanced counter flow heat exchanger.

∴ ε = NTU/1+NTU

Where NTU = UA/(mcp)min

For balanced heat exchanger,

(mcp)h = (mcp)c

∴ NTU = 60 x 25 / 1000 = 1.5

∴ ε = 1.5/1+1.5 = 0.6

Test: Heat Exchanger Level - 2 - Question 6

In a double-pipe heat exchanger, the cold fluid is water with inlet temperature of 20oC and mass flow rate of 20 kg/s and the hot fluid which also has water inlet temperature of 80oC and mass flow rate of 10 kg/s. For water cp = 4.2kj/kg oC.

. What is the maximum temperature to which the cold fluid can be heated in a parallel flow and in a counter flow heat exchanger?

Detailed Solution: Question 6

For parallel flow heat exchanger maximum temperature of cold fluid will be reached when both hot and cold fluid exit at the same temperature.

Thus by steady state flow energy equation

⇒ 20 x 4.2 x (T - 20) = 10 x 4.2 (80-T)

∴ T = 40oC

For counter flow heat exchanger, maximum exit temperature of cold fluid is achieved when effectiveness of the heat exchanger is 1

i.e.

ε = 1

i.e.

(mccpc)(Tco - Tci)/(mccpc)(Thi - Tci) =1

1 = 20 x 4.2 x [T - 20]/10 x 4.2 x [80 - 20]

T = 50oC

Test: Heat Exchanger Level - 2 - Question 7

In a double-pipe counter flow heat exchanger 1000kh/h, oil having a specific heat 20 j/kg -K is cooled from 150oC to 125oC by 1250 kg/h of fluid having specific heat 16j/kg-K. The cold fluid leaves the heat exchanger at 75oC . In this case, the temperature at which the cooling fluid enters the heat exchanger and LMTD are __________

Detailed Solution: Question 7

x = 0 x x = l

mhcph = 1000 x 20 = 20,000j/hr-K

mccph = 1200 x 16 = 20,000j/hr-K

mhcph = mccph

Hence for a balanced Counter flow heat exchangers

ΔTm = ΔTi =ΔTe

∴ ΔTm = 150 -75 - 75oC

Thi - Tce = The - Tci

Tci - The = Tce - Thi

Tci = 50oC

*Answer can only contain numeric values
Test: Heat Exchanger Level - 2 - Question 8

A counter flow shell and tube type heat exchanger is used to heat water with hot exhaust gases. The water (c = 4180 j/kg-K ) flows at the rate of 2 kg/s and the exhaust gases (c = 1000 j/kg - K) flow at the rate of 5 kg/s. If the heat transfer surface area is 32 m2 and the overall heat transfer coefficient is 200 W/m2 -K , the effectiveness of the heat exchanger is __________.


Detailed Solution: Question 8

Hot fluid [Exhaust gases]

CH = mHcH

∴ CH = 1000 x 5 = 5000 Watt/ ...①

Cold fluid [Water]

Cc = mccc

∴ Cc = 4180 x = 8360 Watt/K ...②

From ① & ②

CH < />c

∴ Cmin = CH = 5000 Watt/K

By definition,

C = Cmin/Cmax,

C = C CH/CC

C = 5000/8360

= 0.598

& NTU = UA/min

∴ NTU = 32 x 200/ 5000

= 1.28

For counterflow heat exchanger

∴ ε = 0.626

Test: Heat Exchanger Level - 2 - Question 9

In a counterflow heat exchanger, hot gases enter the system at 200°C and leave at 80°C. the temperature of the outside air entering the unit is 35°C. Its temperature at the exit 90°C. the heat exchanger has an effectiveness of

Detailed Solution: Question 9

By steady state flow equation

Ch(Thi - The) = Cc(Tce - The)

Ch/Cc = Tce - Tci/Thi - The

Ch/Cc = 90-35/200-80 = 55/120

Ch < />C

∴ ε = Ch(Thi - The)/Ch(Thi - Tci)

ε = 200-80/200-35

ε = 0.7272

Test: Heat Exchanger Level - 2 - Question 10

A counter flow shell and tube heat exchanger is used to heat water with hot exhaust gases. The water (C = 4180 J/kg K) flows at the rate of 2 kg/s and the exhaust gases (c = 1000 J/kg K) flow at the rate of 5 kg/s. If the heat transfer surface area is 32 m2 and the overall heat transfer coefficient is 200 W/m2K, the NTU of the heat exchanger i

Detailed Solution: Question 10

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