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CAT Exam  >  CAT Tests  >  Daily Test for CAT Preparation  >  Test Level 1: Speed, Time and Distance (September 2) - CAT MCQ

Test Level 1: Speed, Time and Distance (September 2) - CAT MCQ


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10 Questions MCQ Test Daily Test for CAT Preparation - Test Level 1: Speed, Time and Distance (September 2)

Test Level 1: Speed, Time and Distance (September 2) for CAT 2024 is part of Daily Test for CAT Preparation preparation. The Test Level 1: Speed, Time and Distance (September 2) questions and answers have been prepared according to the CAT exam syllabus.The Test Level 1: Speed, Time and Distance (September 2) MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test Level 1: Speed, Time and Distance (September 2) below.
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Test Level 1: Speed, Time and Distance (September 2) - Question 1
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What is the time taken by Chandu to cover a distance of 360 km by a motorcycle moving at a speed of 10m/s?

Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 1

Since Chandu is moving at a speed of 10 m/s and he has to cover 360 km or 360000 meters,
the time taken would be given by 360000/10 seconds = 36000 seconds = 36000/60 minutes = 600 minutes = 10 hours.

Test Level 1: Speed, Time and Distance (September 2) - Question 2
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Rajdhani Express travels 650 km in 5 h and another 940 km in 10 h. What is the average speed of train?

Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 2

Total distance/Total time = 1590/15 = 106 kmph. 

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Test Level 1: Speed, Time and Distance (September 2) - Question 3
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Rishikant, during his journey, travels for 20 minutes at a speed of 30 km/h, another 30 minutes at a speed of 50 km/h, and 1 hour at a speed of 50 km/h and 1 hour at a speed of 60 km/h. What is the average velocity?

Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 3

The distance covered in the various phases of his travel would be: 10 km + 25 km + 50 km + 60 km.
Thus the total distance covered = 145 km in 2 hours 50 minutes → 145 km in 2.8333 hours → 51.18 kmph

Test Level 1: Speed, Time and Distance (September 2) - Question 4
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Narayan Murthy walking at a speed of 20 km/h reaches his college 10 minutes late. Next time he increases his speed by 5 km/h, but finds that he is still late by 4 minutes. What is the distance of his college from his house?
Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 4

By increasing his speed by 25%, he will reduce his time by 20%.
(This corresponds to a 6 minute drop in his time for travel—since he goes from being 10 minutes late to only 4 minutes late.)
Hence, his time originally must have been 30 minutes.
Hence, the required distance is 20 kmph × 0.5 hours = 10 km.

Test Level 1: Speed, Time and Distance (September 2) - Question 5
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A motor car does a journey in 17.5 hours, covering the first half at 30 km/h and the second half at 40 km/h. Find the distance of the journey.
Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 5

If the car does half the journey @ 30 kmph and the other half at 40 kmph it’s average speed can be estimated using weighted averages.
Since, the distance traveled in each part of the journey is equal, the ratio of time for which the car would travel would be inverse to the ratio of speeds.
Since, the speed ratio is 3:4, the time ratio for the two halves of the journey would be 4:3.
The average speed of the car would be: (30 × 4 + 40 × 3)/7 = 240/7 kmph. It is further known that the car traveled for 17.5 hours (which is also equal to 35/2 hours).
Thus, total distance = average speed × total time = (240 × 35)/(2 × 7) = 120 × 5 = 600 km

Test Level 1: Speed, Time and Distance (September 2) - Question 6
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Manish travels a certain distance by car at the rate of 12 km/h and walks back at the rate of 3 km/h. The whole journey took 5 hours. What is the distance he covered on the car?
Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 6

You can solve this question using the options. Option (a) fits the given situation best as if we take the distance as 12 km he would have taken 1 hour to go by car and 4 hours to come back walking—a total of 5 hours as given in the problem.

Test Level 1: Speed, Time and Distance (September 2) - Question 7
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A car driver, driving in a fog, passes a pedestrian who was walking at the rate of 2 km/h in the same direction. The pedestrian could see the car for 6 minutes and it was visible to him up to a distance of 0.6 km. What was the speed of the car?
Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 7

In 6 minutes, the car goes ahead by 0.6 km.
Hence, the relative speed of the car with respect to the pedestrian is equal to 6 kmph, since, the pedestrian is walking at 2 kmph, hence, the net speed is 8 kmph.

Test Level 1: Speed, Time and Distance (September 2) - Question 8
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Harsh and Vijay move towards Hosur starting from IIM, Bangalore, at a speed of 40 km/h and 60 km/h respectively. If Vijay reaches Hosur 200 minutes earlier then Harsh, what is the distance between IIM, Bangalore, and Hosur?
Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 8

At 40 kmph, Harsh would cover (200/60) × 40 km. = 400/3 km. = 133.33 km.
This represents the distance by which Vijay would be ahead of Harsh, when Vijay reaches the endpoint means in essence that Vijay must have travelled for 133.33/20 hours → 6.66 hours Hence, the distance is 60 × 6.66 = 400 km.

Test Level 1: Speed, Time and Distance (September 2) - Question 9
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A passenger train takes 2 h less for a journey of 300 kilometres if its speed is increased by 5 kmph over its usual speed. Find the usual speed.
Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 9

The required speed s would be satisfying the equation:
300/s – 300/(s + 5) = 2
Solving for s from the options it is clear that s = 25.

Test Level 1: Speed, Time and Distance (September 2) - Question 10
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A plane left half an hour later than the scheduled time and in order to reach its destination 1500 kilometre away in time, it had to increase its speed by 33.33 per cent over its usual speed. Find its increased speed.
Detailed Solution for Test Level 1: Speed, Time and Distance (September 2) - Question 10

 

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