Commerce Exam  >  Commerce Test  >  Mathematics (Maths) Class 11  >  Test: Linear Inequalities- Case Based Type Questions - Commerce MCQ

Linear Inequalities- Case Based Type Questions - Free with solutions Commerce


MCQ Practice Test & Solutions: Test: Linear Inequalities- Case Based Type Questions (10 Questions)

You can prepare effectively for Commerce Mathematics (Maths) Class 11 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Linear Inequalities- Case Based Type Questions". These 10 questions have been designed by the experts with the latest curriculum of Commerce 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: Linear Inequalities- Case Based Type Questions - Question 1

A beaker contains 640 litres of 8% solution of Boric acid. This is to be diluted by adding a 2% Boric acid solution to it.

Based on the above data, answer the following question.

Q. If x litres of 2% Boric acid solution is added to the beaker, the amount of acid becomes ........... litres.

Detailed Solution: Question 1

Total acid =

Test: Linear Inequalities- Case Based Type Questions - Question 2

A beaker contains 640 litres of 8% solution of Boric acid. This is to be diluted by adding a 2% Boric acid solution to it.

Based on the above data, answer the following question.

Q. If the resulting mixture is to be more than 4% but less than 6% boric acid, then the range of x is ..........

Detailed Solution: Question 2

4(640 + x) ≤ 8 × 640 + 2x ≤ 6(640 + x)

2560 + 4x ≤ 5120 + 2x ≤ 3840 + 6x

2560 + 4x ≤ 5120 + 2x

⇒ 2x ≤ 2560

⇒ x ≤ 1280 ...(i)

5120 + 2x ≤ 3840 + 6x

⇒ – 4x ≤ –1280

⇒ 320 ≤ x ...(ii)

From (i) and (ii),

320 ≤ x ≤ 1280

Test: Linear Inequalities- Case Based Type Questions - Question 3

A beaker contains 640 litres of 8% solution of Boric acid. This is to be diluted by adding a 2% Boric acid solution to it.

Based on the above data, answer the following question.

Q. The initial quantity of water in the beaker is ........... litres.

Detailed Solution: Question 3

Amount of water = 640 – 51.2 = 588.8 litres

Test: Linear Inequalities- Case Based Type Questions - Question 4

A beaker contains 640 litres of 8% solution of Boric acid. This is to be diluted by adding a 2% Boric acid solution to it.

Based on the above data, answer the following question.

Q. The amount of water after the mixing is .......... litres.

Detailed Solution: Question 4

Total water =

=

Test: Linear Inequalities- Case Based Type Questions - Question 5

A beaker contains 640 litres of 8% solution of Boric acid. This is to be diluted by adding a 2% Boric acid solution to it.

Based on the above data, answer the following question.

Q. The initial amount of acid in the beaker is ........... litres.

Detailed Solution: Question 5

Amount of acid =

= 51.2 litres

Test: Linear Inequalities- Case Based Type Questions - Question 6

Kelvin(K), degree Celsius(°C) and degree Fahrenheit(°F) are three units of temperature. The conversion formula for them is as follows:

F = 9 / 5C + 32 and K = C + 273.15

Based on the above data, answer the following question.

Q. When F = 68°F, C = ..............

Detailed Solution: Question 6

F = 68°F

C = 5 / 9 (F – 32)

= 5 / 9 (68 – 32) = 20°C

Test: Linear Inequalities- Case Based Type Questions - Question 7

Kelvin(K), degree Celsius(°C) and degree Fahrenheit(°F) are three units of temperature. The conversion formula for them is as follows:

F = 9 / 5C + 32 and K = C + 273.15

Based on the above data, answer the following question.

Q. For part (iv), the range of temperature in Kelvin(K) is ................

Detailed Solution: Question 7

20° < c=""><>

20 + 273.15 < k="">< 25="" +="">

⇒ 293.15 < k=""><>

Test: Linear Inequalities- Case Based Type Questions - Question 8

Kelvin(K), degree Celsius(°C) and degree Fahrenheit(°F) are three units of temperature. The conversion formula for them is as follows:

F = 9 / 5C + 32 and K = C + 273.15

Based on the above data, answer the following question.

Q. When C = 120° F = .................

Detailed Solution: Question 8

C = 120° F

= 9 / 5 × 120+ 32 = 248°F

Test: Linear Inequalities- Case Based Type Questions - Question 9

Kelvin(K), degree Celsius(°C) and degree Fahrenheit(°F) are three units of temperature. The conversion formula for them is as follows:

F = 9 / 5C + 32 and K = C + 273.15

Based on the above data, answer the following question.

Q. A solution is kept between 68°F and 77°F. What is the range in degree Celsius(C)?

Detailed Solution: Question 9

Given 68° < f="">< 77="">

i.e; 68° < 9/5c="" +="" 32=""><>

36° < 9/5c=""><>

20° < c=""><>

Test: Linear Inequalities- Case Based Type Questions - Question 10

Kelvin(K), degree Celsius(°C) and degree Fahrenheit(°F) are three units of temperature. The conversion formula for them is as follows:

F = 9 / 5C + 32 and K = C + 273.15

Based on the above data, answer the following question.

Q. The formula for C in terms of F is C = ...............

Detailed Solution: Question 10

Given F = 9 /5C + 32

9/5 C = F – 32

C = 5/9 (F – 32)

61 videos|221 docs|54 tests
Information about Test: Linear Inequalities- Case Based Type Questions Page
In this test you can find the Exam questions for Test: Linear Inequalities- Case Based Type Questions solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Linear Inequalities- Case Based Type Questions, EduRev gives you an ample number of Online tests for practice
61 videos|221 docs|54 tests
Download as PDF