Test: Lines And Angles- 1 - Class 9 MCQ

Let the ∠x be the required angle
Thus, according to the question
    180−x=3(90−x)
=>180−x=270−3x
=>2x=90
=>x=45

• A triangle cannot have two right angles because the sum of angles in a triangle is always 180 degrees. Two right angles alone would already total 180 degrees, leaving no room for a third angle.
• A triangle can have all angles less than 60 degrees; this is possible and results in an acute triangle.
• A triangle must have at least two acute angles; the third angle could be acute, right, or obtuse.

(1). If a triangle has all the angles greater than 60∘, the sum of angles of the triangle will be more than 180∘
Only (2). is correct because if all the angles are equal, triangle will be an equilateral triangle and sum of all the angles of the triangle will be 180∘.

If two parallel lines are cut by a transversal, the corresponding angles are congruent. If two lines are cut by a transversal and the corresponding angles are congruent, the lines are parallel.

If two angles are complementary, their measures add up to 90 degrees.

• For two angles to sum to 90 degrees, each must be less than 90 degrees.


• An obtuse angle is greater than 90 degrees, so it can't be complementary.


• A right angle is exactly 90 degrees, so it can't pair with another angle to make 90 degrees.


• An acute angle is less than 90 degrees, making it possible to pair with another acute angle to sum to 90 degrees.


 

Therefore, each angle must be an acute angle. Answer: C

The correct option is Option B.

Infinite number of lines can pass through one point.

Let the angle be x
Then the complement angle will be 90^∘ −x

Given x is 14^∘ more than 90^∘ −x
⟹ x = 14^∘ + 90^∘ −x
⟹ 2x = 104^∘
⟹ x = 52^∘
The measure of the angle is 52^∘

Correct option is C
In the above figure straight lines PQ and RS intersect at O.
It is given that θ=3ϕ  .....(1)
∠POR and ∠QOR form linear pair of angles
Also ∠POR=ϕ and ∠QOR=θ 
∠POR+∠QOR=180
ϕ+θ=180
ϕ+3ϕ=180 .....(From 1)
4ϕ=180
ϕ= 180/4 =45
Hence, ∠ϕ=45.

All are incorrect as it is not given that the lines are parallel. Hence, D option.

Draw a line l and a point P not lying on l.

Now, we can draw a straight line parallel to l which passes through P.

Clearly from the figure, only one line can be drawn which is parallel to l and passes through P.

Let, One angle be 2x and another angle be 7x.
Now, 2x+7x=180
9x =180
x =180/9=20
Therefore, one angle = 2*20 = 40
Another angle = 7*20 = 140.

For POQ=straight line →∠ POQ=180^o

2x+30+4x=180

6x+30=180

6x=150

x=25^o.