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Test: Mensuration- 1 - Class 8 MCQ


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30 Questions MCQ Test Mathematics (Maths) Class 8 - Test: Mensuration- 1

Test: Mensuration- 1 for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation. The Test: Mensuration- 1 questions and answers have been prepared according to the Class 8 exam syllabus.The Test: Mensuration- 1 MCQs are made for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mensuration- 1 below.
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Test: Mensuration- 1 - Question 1

In fig., a square of side 5 cm, the area of shaded portion is

Detailed Solution for Test: Mensuration- 1 - Question 1

Area of square having sides 5 cm = 52 = 25 cm2

Area of smaller square having sides 1 cm = 12 = 1 cm2

Then area of 4 squares will be 4 cm2

Area of shaded portion will be =  Area of square having sides 5 cm - area of 4  smaller squares (Unshaded portion)

 Area of shaded portion = 25 cm- 4 cm2

 Area of shaded portion = 21 cm2

 

 

 

Test: Mensuration- 1 - Question 2

Find the area of adjoining figure is

Detailed Solution for Test: Mensuration- 1 - Question 2

Base and height of ΔABF and ΔCED are same. Thus their respective areas will be same.

Total area = (Area of △ABF)×2+Area of rectangle BCEF

Total area = (1/2×10×6)×2+(10×20) = 60+200

Total area = 260cm2

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Test: Mensuration- 1 - Question 3

The area of a trapezium is  

Detailed Solution for Test: Mensuration- 1 - Question 3

Area of Trapezium Derivation Using a Parallelogram: 
To derive the formula for the area of a trapezium using parallelogram, we will consider two identical trapeziums, each with bases a and b and height h. Let A be the area of each trapezium. Assume that the second trapezium is turned upside down as shown in the figure below.

We can see that the new figure obtained by joining the two trapeziums is a parallelogram whose base is a + b and whose height is h. We know that

  • the area of a parallelogram is base × height = (a + b) h.
  • the area of the above parallelogram in terms of 'A' is, A + A = 2A.

Thus, 2A = (a + b) h

⇒ A = (a+b)h/2

Thus, the formula for the area of a trapezium is derived. where a and b are parallel sides and h is height.

Test: Mensuration- 1 - Question 4

In a quadrilateral, half of the product of the sum of the lengths of parallel sides  and the parallel distance between them gives the area of

Detailed Solution for Test: Mensuration- 1 - Question 4

Area of Rectangle = product of length and breadth (L * B)
Area of Parallelogram = A = ½ × d1 × d2 sin (y) where d1 & d2 are diagonal and y is the angle of intersection of diagonal.
 
Area of Trapezium = 1/2(sum of parallel sides)*height. 

Test: Mensuration- 1 - Question 5

The area of rhombus is

Detailed Solution for Test: Mensuration- 1 - Question 5
D1 , D2 stands for the two diagonal in a rhombus, so we 1/2*d1*d2
Test: Mensuration- 1 - Question 6

Which of the following has the formula ½ (sum of parallel sides)×h

Detailed Solution for Test: Mensuration- 1 - Question 6

Area of Rectangle = Length * Breadth.
Area of Rhombus Using DiagonalsA = ½ × d1 × d2
Area of quadrilateral willl be calculated based on which type of quadriateral it is-
Area of trapezium willl be 1/2 (sum of Parallel sides )*height.

Test: Mensuration- 1 - Question 7

The length of parallel sides of trapezium is 14 cm and 6 cm and its height is 5 cm. Its area will be

Detailed Solution for Test: Mensuration- 1 - Question 7

Given that, the length of one side of the trapezium b1 = 6cm and another is b2 =14cm.
The height of the trapezium h = 5cm.
Drawing the figure from the given data.

Test: Mensuration- 1 - Question 8

The area of trapezium in the adjoining figure is  

Detailed Solution for Test: Mensuration- 1 - Question 8

Area of Trapezium  = 1/2 (sum of Parallel sides ) * height
let a and b are the parallel sides:
a= 4cm
b= 6 cm
h= 3cm
according to formula -> 1/2(4+6)*(3)
=>1/2(10)(3)
=>30/2
=>15 cm2

Test: Mensuration- 1 - Question 9

Which of the following is an example of two dimensions  

Detailed Solution for Test: Mensuration- 1 - Question 9

2D definition - A two-dimensional (2D) object is an object that only has two dimensions, such as a length and a width, and no thickness or height. 
3D definition- A three-dimensional (3D) object is an object with three dimensions: a length, a width, and a height. The flat sides of three-dimensional objects are two-dimensional shapes.
Cuboid has length and width as well as thickness or height.

A cone is a three-dimensional figure which has a circular base and a curved surface.

A Sphere is three dimensional figure because it has volume.

Circle is the 2D figure because it does not have thickness
circle image from in.pinterest.com
So the correct option will be D

Test: Mensuration- 1 - Question 10

Which of the following shape has two dimensions

Detailed Solution for Test: Mensuration- 1 - Question 10

Chalk box and soap have breadth,length and height . Cylinder has 2 radii and height. A ring (here) is made up of two concentric circles which is a 2d figure. Hence ring is 2 dimensional

Test: Mensuration- 1 - Question 11

Two dimensional figure is a  

Detailed Solution for Test: Mensuration- 1 - Question 11
A two-dimensional figure, also called a plane or planar figure, is a set of line segments or sides and curve segments or arcs, all lying in a single plane. The sides and arcs are called the edges of the figure. The edges are one-dimensional, but they lie in the plane, which is two-dimensional.
Test: Mensuration- 1 - Question 12

Plane figures are

Detailed Solution for Test: Mensuration- 1 - Question 12

2D definition - A two-dimensional (2D) object is an object that only has two dimensions, such as a length and a width, and no thickness or height.  Since the plane figure has no thickness or height so it will be 2d figure.

Test: Mensuration- 1 - Question 13

Solid figures are

Detailed Solution for Test: Mensuration- 1 - Question 13

3D definition- A three-dimensional (3D) object is an object with three dimensions: a length, a width, and a height
Since solid figure has length breadth as well as thickness or height so sthe solid figure will be 3d. hence option B is correct.

Test: Mensuration- 1 - Question 14

Which of the following is an example of 3 D

Detailed Solution for Test: Mensuration- 1 - Question 14

3D figures appear in space. Since square,triangle and rectangle appear on plain, that is, paper, sphere is the only 3D object.

Test: Mensuration- 1 - Question 15

Pyramid is an example of

Detailed Solution for Test: Mensuration- 1 - Question 15

Since pyramid has length ,width and height so it will be 3D

Test: Mensuration- 1 - Question 16

In a right circular cylinder, the line segments joining the centre of circular faces is ________  to the base

Detailed Solution for Test: Mensuration- 1 - Question 16


From the above figure we can see that the line segments joining the centre of circular faces is perpendicular to the base.

Test: Mensuration- 1 - Question 17

The amount of space occupied by a three dimensional objects is called its

Detailed Solution for Test: Mensuration- 1 - Question 17

Definition of Area : The space enclosed by the boundary of a plane figure.
Surface area: It is same as area in simple we can say that the amount of space enclosed by the surface.
Voume : It is defined as the amount of Space occupied by any three dimensional object.
Lateral surface area: it is defined as the space enclosed by any lateral surfaces.
So the option C is correct

Test: Mensuration- 1 - Question 18

The standard unit of volume is  

Detailed Solution for Test: Mensuration- 1 - Question 18

Volume is nothing but multiplication of Length breadth and height:
V = L * B * H
SI unit of Length is m (Meter)
so as the breadth and height.
SI unit of Volume =  m * m * m
=> m.
Hence option c is correct.

Test: Mensuration- 1 - Question 19

The formula for finding the surface area of cube is

Detailed Solution for Test: Mensuration- 1 - Question 19

Total surface area of cube = 6a2

Curved surface area of cube = 4a

Volume of cube = a3

Test: Mensuration- 1 - Question 20

If the side of the cube is 2 m, then the surface area of the cube is  

Detailed Solution for Test: Mensuration- 1 - Question 20

Surface area of cube = 6 * Side of cube2  
Let a = side of cube.
a = 2m.
Surface area of cube = 6 * 2 * 2
     => 24 m2 .
Hence option C is correct.

Test: Mensuration- 1 - Question 21

The formula for finding total surface area of cuboid is  

Detailed Solution for Test: Mensuration- 1 - Question 21

What is the lateral surface area of a cuboid of length l ...
Lets break the figure -
It has 6 surfaces.
Area of bottom surface = L * B
Area of Top Surface = L * B
Area of Right side surface = B * H
Area of Left Side surface  = B * H
Area of front Surface = H * L
Area of Back surface = H * L 
Total surface area of Cuboid = sum of all the surfaces.
=> (Bottom surface area + Top surface area + Right side surface area + Left side surface area + front side surface area
back side surface area)
=> (LB + LB + BH + BH + HL + HL)
=> (2LB + 2BH + 2HL)
=> 2(LB + BH + HL)
hence option B is correct.

Test: Mensuration- 1 - Question 22

The formula for lateral surface area of cuboid is  

Detailed Solution for Test: Mensuration- 1 - Question 22

What is the lateral surface area of a cuboid of length l ...
Lateral surface area -> Total Surface area of cuboid - surface area of Top and Bottom Surfaces.
=> 2LB + 2BH + 2HL - LB - LB
=> 2BH + 2HL
=> 2H(L + B)
hence option A is correct 

Test: Mensuration- 1 - Question 23

The area of four walls of the room is  

Detailed Solution for Test: Mensuration- 1 - Question 23

Since we have area of wall as b*h and h*l .So area of 4 walls is 2h*b+2h*l=2h(b+l)

Test: Mensuration- 1 - Question 24

The formula for volume of cube is  

Detailed Solution for Test: Mensuration- 1 - Question 24

Cube Photos, Download The BEST Free Cube Stock Photos & HD ...
Since all side is cube is same 
so the volume of cube is = side of cube * side of Cube * side of cube
lets take side of cube = l 
=> l*l*l
=> l
Hence the correct option is A

Test: Mensuration- 1 - Question 25

The quantity that a container holds is called its  

Detailed Solution for Test: Mensuration- 1 - Question 25

The quantity that a container holds is called its "capacity" or "volume."

Hence option C is correct.

Test: Mensuration- 1 - Question 26

1 m3 is  ______________ .

Detailed Solution for Test: Mensuration- 1 - Question 26

The conversion from cubic meters (m³) to liters (L) is based on the fact that 1 liter is equal to 1 cubic decimeter (dm³). Since 1 meter is equal to 10 decimeters, the conversion factor from cubic meters to liters is 103

Therefore, to convert cubic meters to liters, you multiply the volume in cubic meters by 103.

For a 1 cubic meter container:

1 m3×103 L/m3=1000 L

So, 1 cubic meter is indeed equal to 1000 liters.

Test: Mensuration- 1 - Question 27

The height of cuboid  whose volume is 200 cm3 and base  area is 20 cm2 is

Detailed Solution for Test: Mensuration- 1 - Question 27

Base area = length * breadth = 20 sq.cm
Now,
Volume of cuboid = length * breadth * height
Volume = 20 * height
200 = 20 * height
Height = 200 / 20 = 10 cm.

Test: Mensuration- 1 - Question 28

1 m l = ___________ .

Detailed Solution for Test: Mensuration- 1 - Question 28

1m= 1000 L and 1m3=1000000cmand 1000L= 1000000ml
So 1000000cm= 1000000ml which is 1ml = 1cm3

Test: Mensuration- 1 - Question 29

If each edge of a cube is doubled, its surface are will increase

Detailed Solution for Test: Mensuration- 1 - Question 29

Lets  take the original side of cube be S, and final side be 2S.
Orginal surface area will be => 6 * S * S
Final surface area will be => 6 * 2S * 2S
=> 4 * (6 * S * S)
=> 4 times orginal surface area.
Hence the option C is correct.

Test: Mensuration- 1 - Question 30

The formula for finding total surface area of cylinder is 

Detailed Solution for Test: Mensuration- 1 - Question 30

Total surface area of a cylinder = πr2+2πrh+πr2=2πr(r+h)

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