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SSC MTS / SSC GD Exam  >  SSC MTS / SSC GD Test  >  Quantitative Aptitude for Competitive Exams  >  Test: Mensuration- 5 - SSC MTS / SSC GD MCQ

Mensuration- 5 - Free MCQ Practice Test with solutions, SSC MTS/GD Quant


MCQ Practice Test & Solutions: Test: Mensuration- 5 (15 Questions)

You can prepare effectively for SSC MTS / SSC GD Quantitative Aptitude for Competitive Exams with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Mensuration- 5". These 15 questions have been designed by the experts with the latest curriculum of SSC MTS / SSC GD 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

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Test: Mensuration- 5 - Question 1
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The radii of two spheres are in the ratio of 1 : 2. Find the ratio of their surface areas.

Detailed Solution: Question 1

Test: Mensuration- 5 - Question 2
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Find the number of bricks, each measuring 25 cm × 12.5 cm × 7.5 cm, required to construct a wall 12 m long, 5 m high and 0.25 m thick, while the sand and cement mixture occupies 5% of the totalvolume of wall.

Detailed Solution: Question 2

Volume of wall = 1200 × 500 × 25 = 15000000 cm3
Volume of cement = 5% of 15000000 = 750000 cm3
Remaining volume = 15000000 – 750000 = 14250000 cm3
Volume of a brick = 25 × 12.5 × 7.5 = 2343.75 cm3

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Test: Mensuration- 5 - Question 3
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In a shower, 10 cm of rain falls. What will be the volume of water that falls on 1 hectare area ofground?

Detailed Solution: Question 3

Test: Mensuration- 5 - Question 4
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In a swimming pool measuring 90 m by 40 m, 150 men take a dip. If the average displacement ofwater by a man is 8 cubic metres, what will be rise in water level?

Detailed Solution: Question 4

Let the rise in height be = h
Then, as per the question, the volume of water should be equal in both the cases.
Now, 90 × 40 × h = 150 × 8

Test: Mensuration- 5 - Question 5
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Two cones have their heights in the ratio 1 : 2 and the diameters of their bases are in the ratio 2 :1. What will be the ratio of their volumes?

Detailed Solution: Question 5

If the ratio of their diameters = 2 : 1, then the ratio of their radii will also be = 2 : 1
Let the radii of the broader cone = 2 and height be = 1
Then the radii of the smaller cone = 1 and height be = 2

Test: Mensuration- 5 - Question 6
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A closed wooden box measures externally 10 cm long, 8 cm broad and 6 cm high. Thickness ofwood is 0.5 cm. Find the volume of wood used.

Detailed Solution: Question 6

Volume of wood used = External volume – Outer Volume
fi (10 × 8 × 6) – (10 – 1) × (8 – 1) × (6 – 1)
fi 480 – (9 × 7 × 5) = 165 cm2

Test: Mensuration- 5 - Question 7
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Three cubes each of volume of 216 m3 are joined end to end. Find the surface area of the resultingfigure.

Detailed Solution: Question 7

Let one side of the cube = a
Then a3 = 216 fi a = 6 m
Area of the resultant figure
= Area of all 3 cubes – Area of covered figure
fi 216 × 3 – (4 × a2) fi 648 – 144 fi 504 m2

Test: Mensuration- 5 - Question 8
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The largest cone is formed at the base of a cube of side measuring 7 cm. Find the ratio of volumeof cone to cube.

Detailed Solution: Question 8

Test: Mensuration- 5 - Question 9
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Find the radius of the circle inscribed in a triangle whose sides are 8 cm, 15 cm and 17 cm.

Detailed Solution: Question 9

Test: Mensuration- 5 - Question 10
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A cube whose edge is 20 cm long has circle on each of its faces painted black. What is the totalarea of the unpainted surface of the cube if the circles are of the largest area possible?

Detailed Solution: Question 10

Surface area of the cube = 6a2 = 6 × (20)2
= 2400
Area of 6 circles of radius 10 cm = 6pr2
= 6 × p × 100
= 1885.71
Remaining area = 2400 – 1884 = 514.28

Test: Mensuration- 5 - Question 11
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In the adjacent figure, find the area of the shaded region. (Use = 22/7)

Detailed Solution: Question 11

Test: Mensuration- 5 - Question 12
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The perimeter of a sector of a circle of radius 5.7 m is 27.2 m. Find the area of the sector.

Detailed Solution: Question 12

Let the angle subtended by the sector at the centre be = q
Then,

Test: Mensuration- 5 - Question 13
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A circular tent is cylindrical to a height of 3 metres and conical above it. If its diameter is 105 mand the slant height of the conical portion is 53 m, calculate the length of the canvas 5 m wide tomake the required tent.

Detailed Solution: Question 13

Test: Mensuration- 5 - Question 14
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If the curved surface area of a cone is thrice that of another cone and slant height of the secondcone is thrice that of the first, find the ratio of the area of their base.

Detailed Solution: Question 14

Test: Mensuration- 5 - Question 15
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Two circles touch internally. The sum of their areas is 116p cm2 and distance between theircentres is 6 cm. Find the radii of the circles.

Detailed Solution: Question 15

Let the radius of the bigger circle = R
Let the radius of the smaller circle = r
Then as per question; R – r = 6
Solving through options; only option (a) satisfies this condition.

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About this SSC MTS / SSC GD Practice Test

This test contains 15 MCQs on Mensuration- 5 with detailed solutions for each question. It is part of the Quantitative Aptitude for Competitive Exams course on EduRev, designed to align with the current SSC MTS / SSC GD syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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