Test: Miscellaneous (NCERT) - NEET MCQ

As u ≫ f₀ , v = f₀ = 19 m.
Now u = -3.8 × 10⁸ m. Therefore, magnification produced by the objective is

∴ Diameter of the image of moon is 3.5 × 10⁶ × 0.5 × 10^-7 = 0.175 m = 17.5 cm

Let θ be angle between the given rays.

Angle of incidence, 

The number of capital letters which are not laterally inverted by a plane mirror are A, H, I, M, O, T, U, V, W, X, Y.
∴ Total = 11

Number of images = , where θ is in degrees

New angle, θ' = θ - 30^∘ =  60^∘ - 30^∘ = 30^∘ 
Number of images = 

Here, the walls will act as two plane mirrors inclined'to each other at 90^∘(i.e. θ = 90^∘).
The number of images formed is 

Different angles are as shown in figure.

 

In triangle ABC, θ + θ + θ = 180^∘, θ = 60^∘

Given:
- Two plane mirrors placed parallel to each other at a distance L apart.
- A point object O placed between them, at a distance L/3 from one mirror.
- Both mirrors form multiple images.
We need to find the distance between any two images.
To solve this problem, let's analyze the formation of multiple images:
1. Image Formation:
- When a point object is placed between two parallel mirrors, multiple reflections occur.
- Each mirror produces its own set of images, and the final set of images is formed by the combination of both mirror reflections.
- The number of images formed depends on the distance of the object from each mirror.
2. Distance between Images:
- The distance between any two images formed by the two mirrors can be calculated by considering the path traveled by light rays.
- Let's consider the first mirror reflection and the subsequent reflection from the second mirror.
3. First Mirror Reflection:
- The distance between the object O and the first image formed by the first mirror is L/3.
- The distance between the first image and the second mirror is L - L/3 = 2L/3.
4. Second Mirror Reflection:
- The distance between the second mirror and the first image formed by the first mirror is 2L/3.
- The distance between the second image formed by the second mirror and the second mirror is 2L/3.
5. Total Distance between Images:
- The total distance between any two images formed by the two mirrors is the sum of the distances calculated in the previous steps.
- Total distance = L/3 + 2L/3 + 2L/3 = L + 2L = 3L.
6. Conclusion:
- The distance between any two images formed by the two mirrors is 3L.
- Therefore, the distance between any two images cannot be 3L/2.
- Hence, the answer is A: 3L/2.

The ray starting from point M at an angle θ reaches the corner D at the right along a parallel path. Let a be the length of the side.

From figure,

From (i) and (ii), we get

From (ii) and (iii), we get

⇒ 3xy = 2ay (Using (iv))
x = 2a/3
Substituting this value of x in equation (i), we get

or θ = cot⁻¹(0.75)

Angle of deflection is θ = 3.5^∘, Distance, between the screen and the mirror is = 2.0m
The reflected rays get deflected by an amount twice the angle of deflection, i.e., 2θ = 7.0^∘ ∴ tan 2θ = d/2
⇒ d = 2 × tan 7^∘
= 2 × 0.1227
= 0.245m
= 24.5cm

Velocity of object, 
Velocity of image, 

Relative velocity of image with respect to its object