Test: Mole concept - JEE MCQ
15 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: Mole concept
1.44 g of titanium (At. mass = 48) reacted with excess of O2 and produce 
of non stoichiometric compound 
. The value of 
is:
of non stoichiometric compound . The value of is:
The mass of 
produced by the reaction of 
of 
and 
of 
is 
. What is the per cent yield?
produced by the reaction of of and of is . What is the per cent yield?
formed by 
formed by 
will be limiting and actual amount of product is 
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The impure 
of 
is dissolved in water and then treated with excess of silver nitrate solution. The mass of precipitate of silver chloride is found to be 
. The 
purity of 
solution would be:
of is dissolved in water and then treated with excess of silver nitrate solution. The mass of precipitate of silver chloride is found to be . The purity of solution would be:
is produced from 
will be produced from
in common salt:
purity 
ions are in 20 ml of 0.4 M 
?
What is the empirical formula of vanadium oxide, if 2.74 g of the metal oxide contains 1.53 g of metal?
Mass of metal 
Mass of oxygen
of ferrous ammonium sulphate crystals are dissolved in 
of water. 
of this solution requires 
of potassium permaganate during titration for complete oxidation. The weight of 
present in one litre of the solution of
Eq. wt of FAS is 392
ev. of 
.Specific volume of cylindrical virus particle is 
. whose radius and length are 
respectively.
If 
, find molecular weight of virus
) of cylindrical virus particle 
Wt. of 
particle
10 moles 
and 15 moles 
were allowed to react over a suitable catalyst. 8 moles of 
were formed. The remaining moles of 
and 
respectively are -
On reduction with hydrogen 
of an oxide of metal leaves 
of metallic residue. If the atomic mass of metal is 64 , the formula of metal oxide is
of oxygen combines with metal 
of oxygen combines with metal 
.Vapour density of a metal chloride is 83. If equivalent weight of the metal is 6, its atomic weight will be ____.
formed upon mixing 
of 
solution with 50 
of 
solution will be:(Given that molecular weight of
and 
of 
solution 
.
of 
solution 
.
is the limiting reagent, only 
moles of 
will form.
of 
is formed.9 moles of "D" and 14 moles of E are allowed to react in a closed vessel according to given reactions. Calculate number of moles of B formed in the end of reaction, if 4 moles of G are present in reaction vessel. (Percentage yield of reaction is mentioned in the reaction)
Step-1 
Step-2 
mole
formed 
A mixture of 
and 
contain 
mass per cent of nitrogen. What is the mass ratio of the two components in the mixture?
and 
are 
and y gram respectively 
of 
on heating gave 
of 
and 
of 
. This is in accordance with
A gaseous mixture contains oxygen and nitrogen in the ratio of 1: 4 by weight. Therefore, the ratio of their number of molecules is
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