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Chemical Engineering Exam  >  Chemical Engineering Tests  >  Mass Transfer  >  Test: Molecular Diffusion In Liquids - Chemical Engineering MCQ

Test: Molecular Diffusion In Liquids - Chemical Engineering MCQ


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10 Questions MCQ Test Mass Transfer - Test: Molecular Diffusion In Liquids

Test: Molecular Diffusion In Liquids for Chemical Engineering 2024 is part of Mass Transfer preparation. The Test: Molecular Diffusion In Liquids questions and answers have been prepared according to the Chemical Engineering exam syllabus.The Test: Molecular Diffusion In Liquids MCQs are made for Chemical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Molecular Diffusion In Liquids below.
Solutions of Test: Molecular Diffusion In Liquids questions in English are available as part of our Mass Transfer for Chemical Engineering & Test: Molecular Diffusion In Liquids solutions in Hindi for Mass Transfer course. Download more important topics, notes, lectures and mock test series for Chemical Engineering Exam by signing up for free. Attempt Test: Molecular Diffusion In Liquids | 10 questions in 20 minutes | Mock test for Chemical Engineering preparation | Free important questions MCQ to study Mass Transfer for Chemical Engineering Exam | Download free PDF with solutions
Test: Molecular Diffusion In Liquids - Question 1
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Before collision, the distance between the two particles is mean free path.

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Explanation: The mean free path can be found after collision.

Test: Molecular Diffusion In Liquids - Question 2
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Diffusion co-efficient in molecular diffusion is estimated by _________

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Explanation: Ficks law is the ratio of J-flux to the concentration gradient.

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Test: Molecular Diffusion In Liquids - Question 3
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Find the total flux for a particle A and B in a steady state if flux of A and B is 2.44 and 4.44 mol/sq.m sec.

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Explanation: Total flux= flux A+ flux B= 6.88.

Test: Molecular Diffusion In Liquids - Question 4
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Find the flux of A ( xA= 0.2) if Total flux is 5 mol/sq.m sec and J flux of A is 2 mol/sq.m sec.
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Explanation: N flux of A = J flux of A + Total flux N * xA
= 2+ 0.5*2 = 3.

Test: Molecular Diffusion In Liquids - Question 5
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 Find J flux of A ( xA = 0.5) if the total N flux is 6 mol/sq.m sec and N flux of A is 3 mol/sq.m sec.
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Explanation: N flux of A = J flux of A + Total flux N * xA
3= J flux of A + 6 * 0.5
J flux = 0.

Test: Molecular Diffusion In Liquids - Question 6
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 Diffusivity of the liquids can be determined by
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Explanation: Wilke- Chan derived an equation for diffusivity of liquids.

Test: Molecular Diffusion In Liquids - Question 7
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For the molecular diffusion of liquids, if the diffusing molecules having criteria of steady state diffusion of B over non diffusing A then the N flux of A is
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Explanation: For non-diffusing A then N flux of B is zero.

Test: Molecular Diffusion In Liquids - Question 8
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 For liquid molecular diffusion of A and B, steady state equimolar counter diffusion the N flux of A is negative of N flux of B.
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Explanation: For equimolar counter diffusion, the one component flux is negative of other.

Test: Molecular Diffusion In Liquids - Question 9
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Find the change in concentration for a steady state equimolar counter diffusion if D(AB)= 6 sq.m/sec, the change in distance is 2 m and the N flux of A is 5 mol/sq.m sec.
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Explanation: N flux of A = D(AB)/z * (Concentration difference)
Concentration difference = 5/3 =1.67.

Test: Molecular Diffusion In Liquids - Question 10
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Find the diffusivity of AB in sq.m/sec if N flux of A 5 mol/sq.m sec, concentration difference is 2mol/cu.m and distance is 3 m.
Detailed Solution for Test: Molecular Diffusion In Liquids - Question 10

Explanation: N flux of A= D(AB)/z * concentration difference
D(AB) = 7.5 sq.m/sec.

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