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Oxidation and Reduction Reactions, number - Free MCQ Practice Test


MCQ Practice Test & Solutions: Test: Oxidation and Reduction Reactions, Oxidation number (10 Questions)

You can prepare effectively for JEE Chemistry for JEE Main & Advanced with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Oxidation and Reduction Reactions, Oxidation number". These 10 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Test: Oxidation and Reduction Reactions, Oxidation number - Question 1

Which one of the following cannot function as an oxidising agent?

Detailed Solution: Question 1

If an electronegative element is in its lowest possible oxidation state in a compound or in free state. It can function as a powerful reducing agent. e.g. I-

Test: Oxidation and Reduction Reactions, Oxidation number - Question 2

Which of the following chemical reactions depict the oxidizing beahviour of ?

Detailed Solution: Question 2


In thisreaction oxidation number of is decreasing from to hence undergoing reduction and for HI oxidation Number of I is increasing from to 0 hence underegoing oxidation therefore is acting as oxidising agent.

Test: Oxidation and Reduction Reactions, Oxidation number - Question 3

Which reaction involves neither oxidation nor reduction?

Detailed Solution: Question 3

. . of on both sides is .

Test: Oxidation and Reduction Reactions, Oxidation number - Question 4

One gas bleaches the colour of flowers by reduction, while the other by oxidation

Detailed Solution: Question 4

bleaches by reduction, while chlorine bleaches colour of flowers by oxidation.

Test: Oxidation and Reduction Reactions, Oxidation number - Question 5

In how many of the following species, an element has fractional oxidation state?







 

Detailed Solution: Question 5

In species i, ii, vi, vii and viii, an element has fractional oxidation state.

Test: Oxidation and Reduction Reactions, Oxidation number - Question 6

The most powerful reducing agent is:

Detailed Solution: Question 6

oxidation state of P is+3 , which can further be oxidized to a higher oxidation state. So they can act as reducing agents. In oxidation state of P is +5, which is highest for P. Hence cannot serve as a reducing agent.

Test: Oxidation and Reduction Reactions, Oxidation number - Question 7

 On balancing the above equation in basic solution, using integral coefficient, which of the following whole numbers will be the coefficient of ?

Detailed Solution: Question 7


Coefficient of

Test: Oxidation and Reduction Reactions, Oxidation number - Question 8

In  the oxidation states respectively for  and oxygen may be:

Detailed Solution: Question 8

Let  be the oxidation state of in

 contains a peroxide linkage in which has an

oxidation state of

 or  or 

Thus, the oxidation state of sodium in is

Test: Oxidation and Reduction Reactions, Oxidation number - Question 9



Role of hydrogen peroxide in the above reactions is respectively

Detailed Solution: Question 9

In both these reactions hydrogen peroxide acts as a reducing agent, as and are reduced.

Test: Oxidation and Reduction Reactions, Oxidation number - Question 10

Oxidation number of potassium in  and , respectively:

Detailed Solution: Question 10

Alkali metals always possess +1 oxidation state, whereas oxidation state for oxygen present in (oxide) is -2, and in (peroxide) is -1 and in (superoxide) is

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