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Test: PH of Solutions - JEE MCQ


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15 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: PH of Solutions

Test: PH of Solutions for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Test: PH of Solutions questions and answers have been prepared according to the JEE exam syllabus.The Test: PH of Solutions MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: PH of Solutions below.
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Test: PH of Solutions - Question 1

The pH of a 0.1 molar solution of the acid HQ is 3. The value of the ionization constant, Ka of this acid is -

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Test: PH of Solutions - Question 2

How many litres of water must be added to litre of an aqueous solution of HCl with a pH of 1 to create an aqueous solution with pH of 2? 

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Detailed Solution for Test: PH of Solutions - Question 2

Volume of the original solution = 1 L

pH of the new solution = 2

Volume of the new solution = ?
As per volumetric principle

That means the volume of water added to the original solution of 1 L = 10 −1 = 9 L

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Test: PH of Solutions - Question 3

If the of a weak acid is and the of a weak base is Then, the of an aqueous solution of the corresponding salt, will be

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Test: PH of Solutions - Question 4

The equlibrium constant of the reaction of a weak acid (HA) with a strong base ) is at . Hence for will be equal to

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so

Test: PH of Solutions - Question 5

of HA is titrated with strong base (NaOH). The minimum value of equilibriwn constant (k) so that when of titrant has been added, the reaction between is essentially complete and the changes by units on addition of two more drops of titrant is

Detailed Solution for Test: PH of Solutions - Question 5

The beyond the equivalence point can be calculated as follows

before
If units, the before the equivalence point must be At this point if the
reaction is complete, we have only m,mol of HA unreacted,
Hence

Test: PH of Solutions - Question 6

Calculate the ratio of of a solution containing of of per liter and of other solution containing lmol NaCN + lmol of HCN per liter
Given of is the order of 10-10.

Detailed Solution for Test: PH of Solutions - Question 6

Ka of HCN is the order of 10−10 so at this concentration, a of HCN will be negligible.

Test: PH of Solutions - Question 7
The of solution of acetic acid is 5.0. What are the values of and respectively?
Detailed Solution for Test: PH of Solutions - Question 7
Given, of solution

Concentration, of the solution


Since, acetic acid is a weak acid and for weak acid,




Test: PH of Solutions - Question 8

Which of the following is strongest acid

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 which is higher than and
∴ Options , and are wrong.

Test: PH of Solutions - Question 9

What volume of NaOH must be added to solution of , a weak acid for and so as to adjust the of the mixture at ?

Detailed Solution for Test: PH of Solutions - Question 9

Let, v of NaOH be added then
No. of mole of salt NaA formed
No. of mole of acid remaining unreacted
for


So

Test: PH of Solutions - Question 10

If a solution of HCN is ionised, the ioniation constant for is

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Test: PH of Solutions - Question 11

The of a weak acid, benzoic acid and of a weak base, ammonium hydroxide are 4.25 and 4.75 respectively. Then the of solution of ammonium benzoate will be

Detailed Solution for Test: PH of Solutions - Question 11

Ammonium benzoate (C6H5COONH4) is the salt weak benzoic acid (C6H5COOH,pKa = 4.25) and weak ammonium hydroxide (NH4OH, pKb = 4.75).
So, pH of the solution of C6H5COONH4 will be,

Test: PH of Solutions - Question 12

A solution contains and of this solution is :

Detailed Solution for Test: PH of Solutions - Question 12

As we know, pH = −log[H+]
For neutral solution, pH = 7
For acidic solution, pH < 7
For basic solution, pH > 7
Here due to strong base and neutral salt, it's a basic solution. So its pH will be greater than 7.

Test: PH of Solutions - Question 13
Which of the following statements about and ion concentration is incorrect?
Detailed Solution for Test: PH of Solutions - Question 13
is weak acid while is strong base, so one equivalent of can not be neutralized with one equivalent of . Hence the solution of one equivalent of each does not have value as 7 . Its will be towards basic side as is a strong base hence conc. of will be more than the conc. of
Test: PH of Solutions - Question 14

If the reaction between and is
If escapes from the system

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If escapes, the equilibrium will shift to LHS and concentration will decrease

Test: PH of Solutions - Question 15

Calculate the of a solution containing and  and

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