Searching and Sorting - 1 - Free MCQ Practice Test with solutions, Software
MCQ Practice Test & Solutions: Test: Searching and Sorting - 1 (10 Questions)
You can prepare effectively for Software Development DSA in C++ with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Searching and Sorting - 1". These 10 questions have been designed by the experts with the latest curriculum of Software Development 2026, to help you master the concept.
Test Highlights:
- - Format: Multiple Choice Questions (MCQ)
- - Duration: 20 minutes
- - Number of Questions: 10
Sign up on EduRev for free to attempt this test and track your preparation progress.
Which of the following is an example of a linear search algorithm?
Detailed Solution: Question 1
Which sorting algorithm has the best average-case time complexity?
Detailed Solution: Question 2
Which of the following is an example of an in-place sorting algorithm?
Detailed Solution: Question 3
Which of the following is an advantage of quick sort over merge sort?
Detailed Solution: Question 4
Which sorting algorithm is preferred when the data is already partially sorted?
Detailed Solution: Question 5
Which sorting algorithm has the worst-case time complexity of O(n2)?
Detailed Solution: Question 6
What is the time complexity of merge sort in the worst case scenario?
Detailed Solution: Question 7
Which of the following is an example of an unstable sorting algorithm?
Detailed Solution: Question 8
Detailed Solution: Question 9
What will be the output of the following code?
#include <iostream>
using namespace std;
void insertionSort(int arr[], int n) {
for (int i = 1; i < n; i++) {
int key = arr[i];
int j = i - 1;
while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j--;
}
arr[j + 1] = key;
}
}
int main() {
int arr[] = {5, 2, 4, 6, 1, 3};
int n = sizeof(arr) / sizeof(arr[0]);
insertionSort(arr, n);
for (int i = 0; i < n; i++) {
cout << arr[i] << " ";
}
return 0;
}
#include <iostream>
using namespace std;
for (int i = 1; i < n; i++) {
int key = arr[i];
int j = i - 1;
while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j--;
}
arr[j + 1] = key;
}
}
int arr[] = {5, 2, 4, 6, 1, 3};
int n = sizeof(arr) / sizeof(arr[0]);
insertionSort(arr, n);
for (int i = 0; i < n; i++) {
cout << arr[i] << " ";
}
return 0;
}
Detailed Solution: Question 10
152 videos|118 docs|24 tests |
