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Stability of complex ion, Crystal Field Theory - Free MCQ Practice Test


MCQ Practice Test & Solutions: Test: Stability of complex ion, Crystal Field Theory (20 Questions)

You can prepare effectively for JEE Chemistry for JEE Main & Advanced with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Stability of complex ion, Crystal Field Theory". These 20 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 20

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Test: Stability of complex ion, Crystal Field Theory - Question 1

, find the value of ?

Detailed Solution: Question 1

Here, has zero oxidation state, as has zero oxidation state in the compound.
So, at zero oxidation state the electronic configuration of is
that means has 6 valencies, as in this state is stable due to half-filled orbitals. Now, for 6 valencies, is required. Therefore, The compound is .
Hence, the correct option is (2).

Test: Stability of complex ion, Crystal Field Theory - Question 2

Statement Type

Direction (Q. No. 25) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q. 

Statement I : Mn(π— C3H5)(CO)4, obey effective atomic number rule.

Statement II : π-allyl ligand act as a 3e- donor.

Detailed Solution: Question 2

In Mn(π -C3H5) (CO)4
Mn= 25
π-C3H5 = 3
4 (CO) = 8
Hence, EAN = 36
Hence, π-C3H5 ligand acts as a 3-electron donor and complex obey effective atomic number rule.

*Answer can only contain numeric values
Test: Stability of complex ion, Crystal Field Theory - Question 3

In Mn2(CO)10, the number of CO molecules in between the metal atoms are


Detailed Solution: Question 3

Mn(CO)5 is radical with 17-electron configuration. Therefore, it undergoes dimerisation through the formation of M—M single bonds and complex their valence shells to avoid ligand-ligand repulsion the Mn(CO)5 units acquire staggered configuration.

Test: Stability of complex ion, Crystal Field Theory - Question 4

The correct order for wavelengths of absorption in the visible region for the following complexes will be

Detailed Solution: Question 4

Complexes, (I) ,
(II) and (III) are made of and ligands and respectively. The field strength order of the ligands is

So, the order CFSE values:
We know, or
So, the order of wavelength of absorption in visible region will be,

Test: Stability of complex ion, Crystal Field Theory - Question 5

Which will give a white precipitate with in aqueous solution

Detailed Solution: Question 5


Test: Stability of complex ion, Crystal Field Theory - Question 6

For the reaction of the type

Detailed Solution: Question 6

For the reaction of the type
, larger the stability
constant, the higher the proportion of that exists in solution.

Test: Stability of complex ion, Crystal Field Theory - Question 7

Amongst and , which are the colourless species?
(atomic number of Ti = 22, Co = 27, Cu = 29, Ni = 28)

Detailed Solution: Question 7

and and
Both ion do not have any unpaired electron in d orbital to (promote) transition. Hence no absorption of energy is there.
So they are colorless species.

Test: Stability of complex ion, Crystal Field Theory - Question 8

InFe(CO)s, the Fe-C bond possesses

Detailed Solution: Question 8

there is metal to ligand back bonding in Fe-C bond of the organometallic compound
So it possesses both and characters.

Test: Stability of complex ion, Crystal Field Theory - Question 9

The crystal field splitting energy for octahedral and tetrahedral complexes is related as

Detailed Solution: Question 9

The crystal field splitting in tetrahedral complexes is lower than that in octahedral complexes, and

Test: Stability of complex ion, Crystal Field Theory - Question 10

Calculate the magnetic moment of ion .

Detailed Solution: Question 10

Test: Stability of complex ion, Crystal Field Theory - Question 11

For octahedral complex, which of the following configurations of metal cation cannot exist in high spin and low spin forms?

Detailed Solution: Question 11

In and octahedral complexes number of unpaired at central metal atom/ion never changes, therefore for such octahedral complexes terms high spin and low spin not used.

Test: Stability of complex ion, Crystal Field Theory - Question 12

Which of the following complex ions has electrons that are symmetrically filled in both and orbitals ?

Detailed Solution: Question 12

Symmetrically filled t2 g and eg are those, which contain equal distribution of electrons. 

Test: Stability of complex ion, Crystal Field Theory - Question 13

Which of the following statements related to crystal field splitting in octahedral coordination entities is incorrect?

Detailed Solution: Question 13

is a strong field ligand and form low spin complexes thus

Test: Stability of complex ion, Crystal Field Theory - Question 14

Among the following species the one which causes the highest as a ligand is:

Detailed Solution: Question 14

Following is the order of increasing value of for the ligands.

Test: Stability of complex ion, Crystal Field Theory - Question 15

The increasing order of crystal field splitting strength of the given ligands is

Detailed Solution: Question 15

In general, the ligands can be arranged in a series in the order of increasing field strength as

Test: Stability of complex ion, Crystal Field Theory - Question 16

Incorrect match is :

Detailed Solution: Question 16

Hybridization High or
low spin is not defined because is an example of system of configuration.

Test: Stability of complex ion, Crystal Field Theory - Question 17

Which of the following carbonyls will have the strongest bond ?

Detailed Solution: Question 17

As positive charge on the central metal atom increases, the less readily the metal can donate electron density into the orbitals of CO ligand (donation of electron density into orbitals of result in weakening of bond ). Hence, the bond would be strongest in

Test: Stability of complex ion, Crystal Field Theory - Question 18

Which of the following does not have a metal carbon bond?

Detailed Solution: Question 18

Triethoxyaluminium has no Al-C linkage

Test: Stability of complex ion, Crystal Field Theory - Question 19

If the crystal field splitting energy of a tetrahedral complex of the type is , what is the crystal field splitting energy with respect to an octahedral complex, ?

Detailed Solution: Question 19

The crystal field splitting in the tetrahedral field is smaller than in the octahedral field.
For most purposes the relationship between tetrahedral and octahedral crystral field splitting may be represented as :

If the CFSE of tetrahedral complex of is , the CFSE of octahedral complex will be .

Test: Stability of complex ion, Crystal Field Theory - Question 20

The for complex is . The for will be:

Detailed Solution: Question 20

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