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Test: Stokes Theorem - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) - Test: Stokes Theorem

Test: Stokes Theorem for Electrical Engineering (EE) 2024 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Stokes Theorem questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Stokes Theorem MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Stokes Theorem below.
Solutions of Test: Stokes Theorem questions in English are available as part of our Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) & Test: Stokes Theorem solutions in Hindi for Electromagnetic Fields Theory (EMFT) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Stokes Theorem | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Stokes Theorem - Question 1

Find the value of Stoke’s theorem for y i + z j + x k.

Detailed Solution for Test: Stokes Theorem - Question 1

Answer: d
Explanation: The curl of y i + z j + x k is i(0-1) – j(1-0) + k(0-1) =
-i –j –k. Since the curl is zero, the value of Stoke’s theorem is zero. The function is said to be irrotational.

Test: Stokes Theorem - Question 2

The Stoke’s theorem uses which of the following operation?

Detailed Solution for Test: Stokes Theorem - Question 2

Answer: c
Explanation: ∫A.dl = ∫∫ Curl (A).ds is the expression for Stoke’s theorem. It is clear that the theorem uses curl operation.

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Test: Stokes Theorem - Question 3

Which of the following theorem convert line integral to surface integral?

Detailed Solution for Test: Stokes Theorem - Question 3

Answer: d
Explanation: The Stoke’s theorem is given by ∫A.dl = ∫∫ Curl (A).ds. Green’s theorem is given by, ∫ F dx + G dy = ∫∫ (dG/dx – dF/dy) dx dy. It is clear that both the theorems convert line to surface integral.

Test: Stokes Theorem - Question 4

Find the value of Stoke’s theorem for A = x i + y j + z k. The state of the function will be

Detailed Solution for Test: Stokes Theorem - Question 4

Answer: Since curl is required, we need not bother about divergence property. The curl of the function will be i(0-0) – j(0-0) + k(0-0) = 0. The curl is zero, thus the function is said to be irrotational or curl free.

Test: Stokes Theorem - Question 5

The Stoke’s theorem can be used to find which of the following?

Detailed Solution for Test: Stokes Theorem - Question 5

Answer: a
Explanation: It states that the line integral of a function gives the surface area of the function enclosed by the given region. This is computed using the double integral of the curl of the function.

Test: Stokes Theorem - Question 6

he energy stored in an inductor 2H and current 4A is

Detailed Solution for Test: Stokes Theorem - Question 6

Answer: d
Explanation: From Stoke’s theorem, we can calculate energy stored in an inductor as 0.5Li2. E = 0.5 X 2 X 42 = 16 units.

Test: Stokes Theorem - Question 7

The voltage of a capacitor 12F with a rating of 2J energy is

Detailed Solution for Test: Stokes Theorem - Question 7

Answer: a
Explanation: We can compute the energy stored in a capacitor from Stoke’s theorem as 0.5Cv2. Thus given energy is 0.5 X 12 X v2. We get v = 0.57 volts.

Test: Stokes Theorem - Question 8

Find the power, given energy E = 2J and current density J = x2 varies from x = 0 and x = 1.

Detailed Solution for Test: Stokes Theorem - Question 8

Answer: b
Explanation: From Stoke’s theorem, we can calculate P = E X I = ∫ E. J ds
= 2∫ x2 dx as x = 0->1. We get P = 2/3 units.

Test: Stokes Theorem - Question 9

The conductivity of a material with current density 1 unit and electric field 200 μV is

Detailed Solution for Test: Stokes Theorem - Question 9

Answer: d
Explanation: The current density is given by, J = σE. To find conductivity, σ = J/E = 1/200 X 10-6 = 5000.

Test: Stokes Theorem - Question 10

The resistivity of a material with resistance 200 ohm, length 10m and area twice that of the length is

Detailed Solution for Test: Stokes Theorem - Question 10

Answer: c
Explanation: Resistance calculated from Ohm’s law and Stoke’s theorem will be R = ρL/A. To get resistivity, ρ = RA/L = 200 X 20/10 = 400.

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