Tin and lead compounds - Free MCQ Practice Test with solutions, JEE Chemistry

Ge(II) tends to acquire Ge (IV) state by loss of electrons. Hence it is reducing in nature. Pb(IV) tends to acquire Pb (II) O.S. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.

The melting points of group 13 elements follow the order:-
B > Al > Tl > In > Ga
This is due to strong crystalline structure of B and soft metallic nature of the rest of the metals.
Gallium has unusually low melting point due to very high electro positivity.

F and Cl are more oxidising in nature and can achieve Pb in (IV) O.S. but Br₂ and I₂ can not achieve Pb in (IV) O.S. secondly Pb⁴⁺ is strong in oxidising nature and in its presence, Br⁻ and I⁻ can not exist.

Here only statement in option C is incorrect as it combines with FeSO₄ and not it combines with Fe₂(SO₄)₃

paramagnetic, coloured gas

(II). is known but does not exist, this is because due to larger size of Cl atom as compared to F atom it is not possible to accommodate six atoms of Cl around Si atom. (III). Fullerens structure have carbon atoms both in sp² and sp³ hybridised system.
Correct option is (c).

SnCl₄ is colourless volatile liquid and SnCl₂ is colourless solid Sn conducts electricity and it belongs to 14 group

CCl₄ is tetrahedral in nature.

The thermal stability of tetrahalides decreases in order CX₄ > SiX₄ > GeX₄ > SnX₄ and in terms ofsame metal with different halides is in order of MF₄ > MCl₄ > MBr₄ > MI₄

Charcoal is a pure form of carbon, its reaction with hot conc. H₂SO₄ is as follows:

CO react with haemoglobin, forms carboxy haemoglobin and stopes the supply of O₂

Here 1, 3 and 4 are correct as Graphite has higher electrical and thermal conductivities than diamond.
All C- atoms in graphite are sp² hybridised so due to partial double bond character in graphite, bond order will be more than 1 but in diamond Bond order is one.
Here only statement 2 is incorrect as diamond is more hard than graphite.

Graphite and boron nitride have similar structure

Structures of CO,CO₂ and CO₃²⁻ are :

Bond order Hence, the decreasing bond length is:

Carbon dioxide is not a poisonous gas.

The elements present in organic compounds are C, H, S and their oxides are CO₂,H₂O,SO₂ respectively.
CO₂ turns lime water milky, water turns anhydrous copper sulphate blue and SO₂ being reducing agent can reduce K₂Cr₂O₇ into green coloured Cr³⁺ compound (CrCl₃) etc.

are present in Al₄C₃,CaC₂ and Mg₂C₃ are respectively

(I, II) In diamond, hybridisation of carbon is sp³ and graphite has planar hexagonal layer of C-atoms. The hybridisation of each C-atom in graphite is sp².
(III) Silicones are organo-silicon polymers formed from inorganic and organic monomer having chemical formula (R₂SiO)_n, due to non-polar alkyl group, silicones are water repelling in nature.
(IV) The catenation tendency in group 14 elements decreases due to decrease in element bond strength. Thus, the correct order is
C > Si > Ge ≈ Sn
Hence, statement (IV) is incorrect.
Thus, option (a) is correct.

Water gas is CO + H₂