UGEE REAP Mock Test- 1 Free Online Test 2026

The HR team looked at +15% individual output and −22% collaborative performance, then concluded remote work is "overall better."
For this conclusion to hold, they must be assuming that individual output matters MORE than collaborative performance — otherwise the −22% collaborative drop would offset or outweigh the +15% individual gain.
Option (A) directly captures this hidden assumption.
Option (B) is about skill — not addressed in conclusion.
Option (C) about burnout — possible but the conclusion was about productivity, not long-term trends.
Option (D) about project nature — this would strengthen but isn't the assumption behind the specific numbers comparison.
Option (E) about job satisfaction — satisfaction data wasn't used to draw the productivity conclusion.

To strengthen "remote work is overall better for productivity" we need to either:

• Show that the 15% individual gain outweighs the 22% collaborative loss, OR
• Show that the collaborative loss doesn't matter much

Option (C) does both simultaneously. If individual tasks = 80% of all work AND collaborative tasks are being outsourced anyway, then:

• The 15% gain covers the vast majority of work
• The 22% collaborative loss becomes irrelevant since those tasks are outsourced

This powerfully strengthens the conclusion.
Option (A) about burnout — helps long-term but doesn't directly address productivity comparison.
Option (B) about revenue — correlation, not causal proof of remote work productivity.
Option (D) about distractions — explains WHY remote workers do better individually but doesn't address the collaborative gap.
Option (E) actually WEAKENS the conclusion — it suggests office workers' collaborative performance was higher because of experience, not office setting.

For N to be divisible by 12, it must be divisible by both 4 and 3 (since 12 = 4 × 3, and gcd(4,3) = 1).
Testing Statement 1: N divisible by 4 and by 6.
6 = 2 × 3, so N is divisible by 2, 3, and 4. But does divisible by 4 and 6 guarantee divisible by 12?
12 = lcm(4,6) = 12. YES! lcm(4,6) = 12.
So N is divisible by 12. Statement 1 IS sufficient.
Wait — let me recheck: lcm(4,6): 4 = 2², 6 = 2×3 lcm = 2² × 3 = 12 ✓
Statement 1 IS sufficient.
Testing Statement 2: N divisible by 3 and by 8.
8 = 2³, 3 = 3 lcm(8,3) = 24
So N is divisible by 24, which means N is divisible by 12 as well (since 24 = 2×12).
Statement 2 IS also sufficient.
Therefore both statements alone are each sufficient → Answer (D)
Correction of question intent: Let me restate Statement 1 to make it more interesting pedagogically:
Revised Statement 1: N is divisible by 4 and N/3 is an integer when N = 36k for some integer k.
This makes Statement 1 insufficient alone. But for exam clarity:
Answer: (D) — Each statement alone is sufficient
This teaches an important lesson: always compute LCM when checking divisibility sufficiency.

A tangent parallel to x-axis means slope = 0.
Step 1: Find dy/dx y = x³ − 3x dy/dx = 3x² − 3
Step 2: Set dy/dx = 0 3x² − 3 = 0 x² = 1 x = 1 or x = −1
Step 3: Find y-coordinates
At x = 1: y = (1)³ − 3(1) = 1 − 3 = −2 → Point: (1, −2) At x = −1: y = (−1)³ − 3(−1) = −1 + 3 = 2 → Point: (−1, 2)
Both points: (1, −2) and (−1, 2)
Geometric interpretation: These are the local maximum and minimum points of the cubic curve — exactly where the tangent is horizontal.
Answer: (C)

This tests thin film interference through reasoning and observation — exactly the style of Q7 in UGEE 2025 paper (soap bubbles color shift).
The reasoning chain:
Soap bubble colors are caused by thin film interference — light reflecting from the outer and inner surfaces of the bubble wall interferes constructively or destructively for different wavelengths.
As the bubble wall gets thinner:

• The path difference between the two reflected rays changes
• Different wavelengths (colors) get cancelled or enhanced at different thicknesses
• As thickness approaches zero, the path difference approaches zero
• At near-zero thickness, all wavelengths interfere destructively (phase shift of π at one surface)
• The bubble appears black (dark film) just before bursting

The progression goes: multiple colors → fewer colors → red (longest wavelength, last to be cancelled) → black.
This matches Option (B) perfectly.

This tests biological reasoning from a scenario — no memorization needed, just careful thinking.
Key reasoning:
A red blood cell is approximately 6–8 micrometers in diameter.
A capillary is approximately 5–10 micrometers in diameter — roughly the same size as a red blood cell.
This means red blood cells literally squeeze and deform to pass through capillaries — they change from their normal biconcave disc shape to elongate and slip through single-file.
If you were the size of a red blood cell, passing through a capillary would require you to deform your shape — making it the most challenging aspect of the journey.
Eliminating other options:

• (A) Capillaries are actually the SAME size as RBCs — not too wide 
• (C) There IS pressure — blood is pumped by the heart 
• (D) Oxygen molecules are tiny — they pass easily through capillary walls  
• (E) Capillaries don't have valves — veins do 

Break the words properly:

zelph = bright
mur = dark
-orin = light
-antra / -thantra = noun with superlative (star/night + “-est”)

From given data:

We already know nouns like light, star, night have specific suffixes.
But “sky” is a NEW noun, so it must have a new suffix.

Now check options:

A (murorin) → dark light  (wrong, “orin” = light)
C (murthorin) → mixes known suffixes incorrectly 
D (zelphos) → bright sky  (wrong root)
E (murantra) → implies superlative form 

B (murphos) →

mur = dark
-phos = new noun (sky)
 Correct structure

Given:

• Speed of rider 1 = 20 km/h
• Speed of rider 2 = 5 km/h
• Initial distance = 100 km
• Speed of each bullet = 10 km/h
• Firing is instantaneous (no time lag)

Step 2: Motion of bullets

• A bullet is fired only when the previous bullet hits the shield.
• There is no time gap, so bullets are effectively in motion continuously for the entire duration (4 hours).
• At any instant, only one bullet is traveling.
• Speed of bullet = 10 km/h (with respect to ground)

Step 3: Total distance covered by all bullets

Problem Given:

• P(A and B) = 1/6

• P(neither A nor B) = 1/3

• A and B are independent events

• We need to find: P(A)

Step 1: Use independence

If A and B are independent:
P(A and B) = P(A) × P(B) = 1/6 → (Equation 1)

Also:
P(A') = 1 - P(A)
P(B') = 1 - P(B)
Since A and B are independent, their complements are also independent:
P(A' and B') = P(A') × P(B') = 1/3 → (Equation 2)

Step 2: Use union formula

We know:
P(A or B) = 1 - P(A' and B') = 1 - 1/3 = 2/3

Also:
P(A or B) = P(A) + P(B) - P(A and B)

Substitute known values:
2/3 = P(A) + P(B) - 1/6

Now add 1/6 to both sides:
2/3 + 1/6 = P(A) + P(B)
Convert to same denominator:
4/6 + 1/6 = 5/6

So:
P(A) + P(B) = 5/6 → (Equation 3)

Step 3: Solve equations

Let’s say:
x = P(A)
Then:
P(B) = 5/6 - x

Now plug into Equation 1:
x × (5/6 - x) = 1/6

Distribute:
(5/6)x - x² = 1/6

Now rearrange:
-x² + (5/6)x - 1/6 = 0

Multiply the entire equation by -1:
x² - (5/6)x + 1/6 = 0

Multiply through by 6 to get rid of fractions:
6x² - 5x + 1 = 0

Step 4: Solve the quadratic

Use the quadratic formula:

x = [5 ± √(25 - 24)] / 12
x = [5 ± √1] / 12
x = (5 ± 1) / 12

So two solutions:

• x = (5 + 1)/12 = 6/12 = 1/2

• x = (5 - 1)/12 = 4/12 = 1/3

Step 5: Check which one is P(A)

So either:
P(A) = 1/2 and P(B) = 1/3, or
P(A) = 1/3 and P(B) = 1/2

Both satisfy:

• P(A) × P(B) = 1/6

• (1 - P(A)) × (1 - P(B)) = 1/3

For quadratic ax² + bx + c = 0,
Harmonic mean (HM) of roots = 2αβ / (α + β)

Here:
a = (5 + √2), b = −(4 + √5), c = (8 + 2√5)

Sum of roots = −b/a = (4 + √5)/(5 + √2)
Product of roots = c/a = (8 + 2√5)/(5 + √2)

HM = 2 × (product)/(sum)

= 2 × [(8 + 2√5)/(5 + √2)] ÷ [(4 + √5)/(5 + √2)]

= 2(8 + 2√5)/(4 + √5)

= (16 + 4√5)/(4 + √5)

= 4

Let capacity of one of the first pumps = x m^3/h
Capacity of one additional pump = 1/60 tank per hour

Let total tank volume = V

Work done:

First 3 hours:
2x × 3 = 6x

Next 2 hours (all pumps):
(2x + 3/60)V × 2

Last 1 hour:
Same rate fills remaining 20 m^3

From last 1 hour:
(2x + 1/20)V = 20

Solving, we get:
x = 4 m^3/h

The line along which motorcycle A is running, is ​, which can be rewritten as
​
Thus, the required cartesian equation is ​

The line along which motorcycle B is running, is = which is parallel to the vector 
∴ D.R.'s of the required line are < 2, 1, 1 >.

Hence, shortest distance between the given lines is 0.

The alternate numbers form two different series. The missing number belongs to the one beginning with 260. in this subtract 4 and divide the difference by 2 to get the next number. So the missing number is 62 - 4 = 58/2 = 29

To decode the word PLAYING based on the pattern used for PROGRAM:

• In the given code, each letter is shifted by a certain number of positions in the alphabet.
• For PROGRAM to become RTQHTCO:
  • P (16) → R (18): +2
  • R (18) → T (20): +2
  • O (15) → Q (17): +2
  • G (7) → H (8): +1
  • R (18) → T (20): +2
  • A (1) → C (3): +2
  • M (13) → O (15): +2
• Apply this pattern to PLAYING:
  • P (16) → R (18): +2
  • L (12) → N (14): +2
  • A (1) → C (3): +2
  • Y (25) → Z (26): +1
  • I (9) → K (11): +2
  • N (14) → P (16): +2
  • G (7) → I (9): +2

The coded result for PLAYING is RNCZKPI.

S↔I → I,S
N↔G → G,N
L↔E → E,L The code is ISGNEL.
∴ ISGNEL is the code for SINGLE.

As we observe that the letters and their corresponding codes are given in the following order, i.e., the code for S is Ω, U is θ and so on. Hence, the code for SECTOR is 'Ω1©%$7'.

A + B means A is the mother of B; A - B means A is the brother of B; A % B means A is the father of B; A × B means A is the sister of B.

Maternal uncle means the brother of someone's mother. We therefore need relationships that make P the brother of Q's mother.

Consider option 3: P - M + N × Q.

P - M: P is the brother of M.

M + N: M is the mother of N.

N × Q: N is the sister of Q.

Since N is the sister of Q, N and Q are siblings and share the same mother; M is the mother of N, so M is also the mother of Q.

Because P is the brother of M, P is the brother of Q's mother; therefore P is the maternal uncle of Q.

• The correct answer is b) "Employees who chose to participate in the wellness program had higher productivity levels even before the program started."

  This statement weakens the conclusion by suggesting that the participants' higher productivity may be due to their pre-existing health-consciousness and motivation, rather than the wellness program itself.

• a) Strengthens the conclusion by providing a mechanism for the program's effectiveness.

• c) Strengthens the conclusion by ruling out other variables.

• d) Strengthens the conclusion by implying the program offers a unique benefit.

Thus, b is the only option that undermines the direct causal link between the program and productivity improvements.

• There is one row of Tulips.
• Two more rows of Orchids than Tulips, so there are three rows of Orchids.
• Two more rows of Rose than Orchids, so there are five rows of Rose.
• One less Marigold row than Rose, so there are four rows of Marigold.
• The sum of the rows of Orchids and Marigold is 3 + 4 = 7.

The question does not provide enough information to determine the exact number of rows planted. Without additional data such as:

• Total area
• Row dimensions

It's impossible to choose a specific numerical answer from the given options.

Let x = initial chocolates. Sam: x - 1, eats (x - 1)/3, leaves 2(x - 1)/3.
Mona: eats [2(x - 1)/3 - 1]/3, leaves 2[2(x - 1)/3 - 1]/3.
Tanya: eats {2[2(x - 1)/3 - 1]/3 - 1}/3, leaves 2{2[2(x - 1)/3 - 1]/3 - 1}/3.
Final: 2{2[2(x - 1)/3 - 1]/3 - 1}/3 - 1, divided by 3, is integer.
For x = 79: 78 → 52 → 34 → 22 → 21 → 7 per person.
Answer D (79).

We only consider Non-graduate employees (second number in each pair) with ≤ 10 years service.

Step 1: Extract data (Non-graduates)

0–5 years

• Shorthand = 35
• Typing = 40
• Both = 30

Only one =
(35 − 30) + (40 − 30) = 5 + 10 = 15

6–10 years

• Shorthand = 15
• Typing = 20
• Both = 10

Only one =
(15 − 10) + (20 − 10) = 5 + 10 = 15

Step 2: Totals

• Total knowing only one = 15 + 15 = 30
• Total Non-graduates (≤10 years) = 120 + 75 = 195

Step 3: Percentage

Hence, option(D) is correct

Graduate employees who know neither shorthand nor typing:

• For 0-5 years: The total number of employees is 80, and 40 know shorthand, 35 know typing, 35 know both. So, graduates who know neither:

  80−(40+35−35)=80−40=40

• For 6-10 years: The total number of employees is 150, and 60 know shorthand, 60 know typing, 40 know both. So, graduates who know neither:

  150−(60+60−40)=150−80=70

• For more than 10 years: The total number of employees is 90, and 40 know shorthand, 40 know typing, 15 know both. So, graduates who know neither:

  90−(40+40−15)=90−65=25

Total graduates who know neither shorthand nor typing:

40+70+25=135

Calculation:
0-5 years: 40 - 35 = 5
6-10 years: 60 - 40 = 20
10 years: 40 - 15 = 25
Total graduates knowing shorthand only = 5 + 20 + 25 = 50
The number of graduate employees who know only shorthand is 50, calculated as (40 - 35) + (60 - 40) + (40 - 15) = 5 + 20 + 25 = 50.

Note:  has not been seen in the data but if you realise there are only words for 1-5 because of the counting back system, it must be 1: we've seen 2, 3, 4, 5.

From the list in the image:

• àrun = 5

• ògórin shows up in:

  • ààdórin = 70

  • ẹ̀ẹ̀tàdilogórin = 77

  • ẹ̀tàdógórin = 83

So we can safely say:

• ògórin = 80

Because:

• ẹ̀tàdógórin = 83, and ẹ̀tà = 3, so 80 + 3 = 83 → ògórin = 80

So,

arundogorin = àrun (5) + ògórin (80) = 85

• Identify base: àárùn = 5.
• Analyze suffix: "dílógùn" resembles "dórìn" (70) from àádórìn = 70.
• Calculate: 5 + 70 = 75.
• Verify: Matches pattern of ètáadógún (77) and ètáadórìn (83) with 70-based increments.
• So 75 is the right one.

Correlation shows an association between variables, but it does not imply causation.

A high correlation coefficient (r) such as 0.85 indicates a strong relationship, but it cannot prove that one variable causes the other.

There may still be confounding factors affecting the relationship, which are not accounted for by correlation alone.