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VITEEE: Subject Wise and Full Length VITEEE Maths Test - 2 Free Online


MCQ Practice Test & Solutions: VITEEE Maths Test - 2 (40 Questions)

You can prepare effectively for JEE VITEEE: Subject Wise and Full Length MOCK Tests with this dedicated MCQ Practice Test (available with solutions) on the important topic of "VITEEE Maths Test - 2". These 40 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 40 minutes
  • - Number of Questions: 40

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VITEEE Maths Test - 2 - Question 1
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The radius of the circle in which the sphere x2 + y2 + z2 + 2x - 2y - 4z - 19 = 0 is cut by the plane x + 2y + 2z + 7 = 0, is

Detailed Solution: Question 1

Radius of sphere is=5 then perpen dicular dice Frome plane=4 now radius of circle r,sqr=25_16=9so r=3

VITEEE Maths Test - 2 - Question 2
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The pole of the line lx+my+n=0 w.r.t. the parabloa y2 =4ax

Detailed Solution: Question 2

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VITEEE Maths Test - 2 - Question 3
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The acute angle between the planes 2x-y+z=6 and x+y+2z=3 is

Detailed Solution: Question 3

VITEEE Maths Test - 2 - Question 4
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The difference of an integer and its cube is divisible by

Detailed Solution: Question 4

Correct answer: B

x - x3 = -x(x-1)(x+1)

The expression is the product of three consecutive integers (x-1), x, (x+1).

Among any three consecutive integers one is divisible by 3 and at least one is even, so the product is always divisible by 6.

Therefore the expression is divisible by 6 for every integer x, so option B is correct.

To show option A (4) is not always true, take x = 2. Then x - x3 = 2 - 8 = -6, which is not divisible by 4.

Options C (10) and D (9) also fail in general because factors 5 or 9 are not guaranteed in the product of three consecutive integers.

VITEEE Maths Test - 2 - Question 5
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If A+B+C=180o, then [(tanA+tanB+tanC)/(tanA tanB tanC)]=

Detailed Solution: Question 5

Given, A + B + C = 180
So, A + B = 180 - C
Taking tan on both sides we get,
⇒ tan(A+B) = tan(180-C)
⇒ 
⇒ tanA + tanB = -tanC(1 - tanA tanB)
⇒ tanA + tanB = - tanC + tanA tanB tanC
⇒ tanA + tanB + tanC = tanA tanB tanC

VITEEE Maths Test - 2 - Question 6
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The area (in square units) of the region enclosed by the curves y = x2 and y = x3 is

Detailed Solution: Question 6

By solving equations 1and 2 we can get 0,1as values for x which can be the limits and by subtracting y=x^2 from x^3 and integrating the result within the limits 0 to 1 we can get area = 1\12

VITEEE Maths Test - 2 - Question 7
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The latus rectum of the parabola y2 = 5x + 4y + 1 is

Detailed Solution: Question 7

y2 = 5x + 4y + 1
or y2 - 4y = 5x + 1
or y2 - 2.2.y + (2)2 - (2)2 = 5x + 1
or (y - 2)2 = 5x + 5
or (y - 2)2 = 5(x + 1)
Length of the latus rectum = 5

VITEEE Maths Test - 2 - Question 8
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In a Δ A B C , a = 1 and the perimeter is six times the AM of the sines of the angles. The measure of ∠ A is

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VITEEE Maths Test - 2 - Question 9
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if A is a 3 x 3 matrix and B is its adjoint matrix. If ∣B∣ = 64, then ∣A∣ =

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VITEEE Maths Test - 2 - Question 10
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The value of , is

Detailed Solution: Question 10

VITEEE Maths Test - 2 - Question 11
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If 0 ≤ x ≤ π and , then the value of x that satisfies the given conditions is

Detailed Solution: Question 11

VITEEE Maths Test - 2 - Question 12
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If f(x) = {2x - 3, x ≤ 2} then f(1) is equal to

Detailed Solution: Question 12

To find f(1) from the function f(x) = 2x - 3 when x ≤ 2, follow these steps:

  • Substitute x = 1 into the function: f(1) = 2(1) - 3.
  • Calculate the value: 2 - 3 = -1.

Now, calculate f(2):

  • Use the same function with x = 2: f(2) = 2(2) - 3.
  • Compute the result: 4 - 3 = 1.

We found f(1) = -1 and f(2) = 1.

Therefore, f(1) is equal to -f(2).

VITEEE Maths Test - 2 - Question 13
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If x dy = y(dx + y dy), y > 0 and y (1) = 1, then y (-3) is equal to

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VITEEE Maths Test - 2 - Question 14
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In the expansion of (y1/6 - y-1/3)9 the term independent of y is :

Detailed Solution: Question 14

VITEEE Maths Test - 2 - Question 15
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If then a and b are

VITEEE Maths Test - 2 - Question 16
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A single letter is selected at random from the word "PROBABILITY". The probability that it is a vowel is

Detailed Solution: Question 16

VITEEE Maths Test - 2 - Question 17
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The points with position vectors 10î + 3ĵ, 12î - 5ĵ and aî + 11ĵ are collinear if a =

Detailed Solution: Question 17

Given, A = (10i + 3j​)
B = (12i - 5j)​
C = (ai + 11j​)
AB = 2i - 8j​
AC = (a - 10)i + 8j​
AB and AC are collinear
⇒ 2/(a - 10) = -8/8
⇒ 2 = 10 - a
⇒ a = 8

VITEEE Maths Test - 2 - Question 18
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A polygon has 44 diagonals. The number of its sides is

Detailed Solution: Question 18

The number of diagonals for n sided polygon = [n(n-3)]/2 .therefore,=> 44 = [n(n-3)]/2 .=> n^2 - 3n - 88 = 0 .=> (n+8)(n-11) =0.=> n = -8 or 11.Neglect n = -8.Therefore,=> n = 11 .therefore, the no. of sides = 11Hence, correct answer is (B).

VITEEE Maths Test - 2 - Question 19
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Detailed Solution: Question 19

VITEEE Maths Test - 2 - Question 20
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A committee consists of 9 experts from three institutions A, B and C, of which 2 are from A, 3 from B and 4 from C. If three experts resign, then the probability that they belong to different institutions is

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VITEEE Maths Test - 2 - Question 21
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If then is

Detailed Solution: Question 21

Since for all i.
for all

VITEEE Maths Test - 2 - Question 22
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The sum of an infinite G.P. is 3. The sum of the series formed by squaring its terms is also 3. The series is

Detailed Solution: Question 22

VITEEE Maths Test - 2 - Question 23
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Which of the following is correct

Detailed Solution: Question 23

Explanation:


  • To compare two complex numbers, we first compare their real parts. If the real parts are equal, then we compare the imaginary parts.

  • In this case, the real parts are 5 and 6. Since 5 is less than 6, we can say that 5 + 3i is less than 6 + 4i.

  • Therefore, the correct answer is option D: 5 + 3i < 6 + 4i.

    •  

VITEEE Maths Test - 2 - Question 24
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If the two circles 2x2 + 2y2 -3x + 6y + k = 0 and x2 + y2 - 4x + 10y + 16 = 0 cut orthogonally, then the value of k is

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VITEEE Maths Test - 2 - Question 25
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The equation line passing through the point P(1,2) whose portion cut by axes is bisected at P, is

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VITEEE Maths Test - 2 - Question 26
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The strength of a beam varies as the product of its breadth b and square of its depth d. A beam cut out of a circular log of radius r would be strong when

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VITEEE Maths Test - 2 - Question 27
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If a matrix is such that
Then what is equal to?

Detailed Solution: Question 27

Let A be a matrix such that
Post multiply by on both the sides, we get

VITEEE Maths Test - 2 - Question 28
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If α, β are the roots of the equation x2- 2x + 2 = 0, then the value of α2 + β2 is

Detailed Solution: Question 28

α + β = 2
αβ = 2
(α + β)2 = 22
α2 + β2 +2αβ = 4
α2 + β2 +2(2) = 4
α2 + β2 + 4 = 4
α2 + β2 = 0

VITEEE Maths Test - 2 - Question 29
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How many total words can be formed from the letters of the word INSURANCE in which vowels are always together?

Detailed Solution: Question 29

VITEEE Maths Test - 2 - Question 30
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The 5th term of a G.P. is 2, then the product of its first 9 term is

Detailed Solution: Question 30

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This test contains 40 MCQs on VITEEE Maths Test - 2 with detailed solutions for each question. It is part of the VITEEE: Subject Wise and Full Length MOCK Tests course on EduRev, designed to align with the current JEE syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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