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VITEEE PCBE Mock Test - 11 - JEE MCQ


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30 Questions MCQ Test VITEEE: Subject Wise and Full Length MOCK Tests - VITEEE PCBE Mock Test - 11

VITEEE PCBE Mock Test - 11 for JEE 2024 is part of VITEEE: Subject Wise and Full Length MOCK Tests preparation. The VITEEE PCBE Mock Test - 11 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCBE Mock Test - 11 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCBE Mock Test - 11 below.
Solutions of VITEEE PCBE Mock Test - 11 questions in English are available as part of our VITEEE: Subject Wise and Full Length MOCK Tests for JEE & VITEEE PCBE Mock Test - 11 solutions in Hindi for VITEEE: Subject Wise and Full Length MOCK Tests course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt VITEEE PCBE Mock Test - 11 | 125 questions in 150 minutes | Mock test for JEE preparation | Free important questions MCQ to study VITEEE: Subject Wise and Full Length MOCK Tests for JEE Exam | Download free PDF with solutions
VITEEE PCBE Mock Test - 11 - Question 1
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Safranin stains

VITEEE PCBE Mock Test - 11 - Question 2
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Calcium gives rigidity to bones and teeth alongwith

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VITEEE PCBE Mock Test - 11 - Question 3
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Typical 'lubb-dupp' sounds heard in heart beat are due to

VITEEE PCBE Mock Test - 11 - Question 4
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Chitinous peritrophic membrane around food in cockroach is secreted by
VITEEE PCBE Mock Test - 11 - Question 5
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Mitochondria are absent in
VITEEE PCBE Mock Test - 11 - Question 6
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Which of the following is found in both prokaryotic and eukaryotic cells
VITEEE PCBE Mock Test - 11 - Question 7
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All bacterial cells get stained with
VITEEE PCBE Mock Test - 11 - Question 8
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A good example of an auxin herbicide is
VITEEE PCBE Mock Test - 11 - Question 9
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The part of the earth and atmosphere supporting life is
VITEEE PCBE Mock Test - 11 - Question 10
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Homologous organs have
VITEEE PCBE Mock Test - 11 - Question 11
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Half of radioactive uranium is... billion years
VITEEE PCBE Mock Test - 11 - Question 12
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The sequence in evolution of horse was
VITEEE PCBE Mock Test - 11 - Question 13
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Gene and cistron are sometimes used as synonyms because
VITEEE PCBE Mock Test - 11 - Question 14
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In DNA, when AGCT occur, their association is as per which of the following pair ?
VITEEE PCBE Mock Test - 11 - Question 15
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PCR was developed by
VITEEE PCBE Mock Test - 11 - Question 16
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Alleles represent
VITEEE PCBE Mock Test - 11 - Question 17
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If an organism is crossed with homozygous recessive individual, it is called :
VITEEE PCBE Mock Test - 11 - Question 18
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Gene for sickle cell anaemia is carried by
VITEEE PCBE Mock Test - 11 - Question 19
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Duchenne's muscular dystrophy is a
VITEEE PCBE Mock Test - 11 - Question 20
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Rh⁻ mother carries R⁺ foetus. The foetus is at a risk of disease called
VITEEE PCBE Mock Test - 11 - Question 21
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Directions: Read the table given below and answer the questions accordingly.

Shares traded in Chandigarh, Punjab, Haryana (In Rupees)

Q. The average for the high rates of Chandigarh for all the companies was
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 21

The average for all the high involved with the Chandigarh region was

(438 + 148 + 28 + 190.5 + 160)/5 which gives 192.9.

VITEEE PCBE Mock Test - 11 - Question 22
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Directions: Read the table given below and answer the questions accordingly.

Shares traded in Chandigarh, Punjab, Haryana (In Rupees)

Q. Total of low value of the Punjab region exceeds the total of the low value of the region of Haryana by how much?
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 22

Total value for the low of the Punjab region for the given companies is 395 + 180 + 23 + 177.5 + 140.5 = 916

whereas the total for the low of the Haryana region is 413.75 + 180 + 24.5 + 177.5 + 102.5 = 898.25.

So it exceeds by 916 – 898.25 = 17.75.

VITEEE PCBE Mock Test - 11 - Question 23
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Directions: Read the table given below and answer the questions accordingly.

Shares traded in Chandigarh, Punjab, Haryana (In Rupees)

Q. Low for RCOM for all the given states/UT form what percent of the low for ZARA for the same?
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 23

The total of lows for the RCOM for all the given states/ UT are given to be 532 and the ZARA has the total for their lows to be 500.

Thus ATQ (532/500)*100 = 106.4%

VITEEE PCBE Mock Test - 11 - Question 24
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Directions: Answer the given question based on the following line graph:
Calculate the increase in stock of cereal 1 for 1992
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 24

Within a year, increase/decrease in stock for any cereal cannot be determined from the given data.

VITEEE PCBE Mock Test - 11 - Question 25
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Directions: Study the given information carefully and answer the following question.

The graph below represents sales and net profit in Rs. crore of IVP Ltd. for five years from 1994-95 to 1998-99. During this period, the sales increased from Rs. 100 crore to Rs. 680 crore. Correspondingly, the net profit increased from Rs. 2.5 crore to Rs. 12 crore. Net profit is defined as the excess of sales over total costs.

Q. Defining profitability as the ratio of net profit to net sales, it can be concluded that
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 25

It can be seen that profitability did not follow a fixed pattern as the first three statements try to generalise it. Therefore, they are not applicable.

VITEEE PCBE Mock Test - 11 - Question 26
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Directions: Study the given information carefully and answer the following question.

The graph below represents sales and net profit in Rs. crore of IVP Ltd. for five years from 1994-95 to 1998-99. During this period, the sales increased from Rs. 100 crore to Rs. 680 crore. Correspondingly, the net profit increased from Rs. 2.5 crore to Rs. 12 crore. Net profit is defined as the excess of sales over total costs.

Q. The highest percentage growth in net profit as compared to the previous year was seen in
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 26

From the graph, we can calculate the growth in profits.

The highest percentage growth in net profit as compared to the previous year was seen in 1995-96.

VITEEE PCBE Mock Test - 11 - Question 27
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Directions: Study the given information carefully and answer the following question.

The graph below represents sales and net profit in Rs. crore of IVP Ltd. for five years from 1994-95 to 1998-99. During this period, the sales increased from Rs. 100 crore to Rs. 680 crore. Correspondingly, the net profit increased from Rs. 2.5 crore to Rs. 12 crore. Net profit is defined as the excess of sales over total costs.

Q. The highest percentage of growth in sales over the previous year occurred in
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 27

From the graph, we know that the percentage growth in sales were:

It is but obvious from the above table that the maximum percentage increase in sales as compared to the previous year occurred in 1995-96.

VITEEE PCBE Mock Test - 11 - Question 28
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Sheldon had to cover a distance of 60 km. However, he started 6 minutes later than his scheduled time and raced at a speed 1 km/h higher than his originally planned speed and reached the finish at the time he would reach it if he began to race strictly at the appointed time and raced with the assumed speed. Find the speed at which he travelled during the journey described.
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 28

Solve this question through options.
⇒  For instance, if he travelled at 25 km/h, his original speed would have been 24 km/h.
⇒ The time difference can be seen to be 6 minutes in this case = 60 / 24 – 60 / 25 = 0.1 hrs = 6 mins

Thus, 25 km/h is the correct answer. 

So Option A is correct

VITEEE PCBE Mock Test - 11 - Question 29
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Two sprinters run the same race of100 m One runs at a speed of 10 m/s and the other runs at 8 m/s. By what time will the first sprinter beat the other sprinter?
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 29

Correct option is C
Time taken by first sprinter 
= 100/10 = 10sec
Time taken by second sprinter 
= 100/80 = 12.5sec
Difference = 12.5 - 10 = 2.5 sec

VITEEE PCBE Mock Test - 11 - Question 30
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X can do a piece of work in 20 days. He worked at it for 5 days and then Y finished it in 15 days. In how many days can X and Y together finish the work?
Detailed Solution for VITEEE PCBE Mock Test - 11 - Question 30
  • X’s five day work = 5/20 = 1/4. Remaining work = 1 – 1/4 = 3/4.
  • This work was done by Y in 15 days. Y does 3/4th of the work in 15 days, he will finish the work in 15 × 4/3 = 20 days.  
  • X & Y together would take 1/20 + 1/20 = 2/20 = 1/10 i.e. 10 days to complete the work.

So Option C is correct

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