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VITEEE PCME Mock Test - 10 - JEE MCQ


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30 Questions MCQ Test VITEEE: Subject Wise and Full Length MOCK Tests - VITEEE PCME Mock Test - 10

VITEEE PCME Mock Test - 10 for JEE 2024 is part of VITEEE: Subject Wise and Full Length MOCK Tests preparation. The VITEEE PCME Mock Test - 10 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCME Mock Test - 10 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCME Mock Test - 10 below.
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VITEEE PCME Mock Test - 10 - Question 1

The maximum value of logx/x in (2, ∞) is

VITEEE PCME Mock Test - 10 - Question 2

The area in square units of the region bounded by the curves x2 = 4y, the line x = 2 and the x-axis is

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 2

The required area 

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VITEEE PCME Mock Test - 10 - Question 3

The polar form of the complex number (i25 )3 is

VITEEE PCME Mock Test - 10 - Question 4

If [(1+i)/(1-i)]m = 1, the least value of m is

VITEEE PCME Mock Test - 10 - Question 5

The area bounded by two curves y2=4ax and x2=4ay is

VITEEE PCME Mock Test - 10 - Question 6

VITEEE PCME Mock Test - 10 - Question 7

Let [ ] denote the greatest integer function and f(x) = [tan2x]. Then

VITEEE PCME Mock Test - 10 - Question 8

VITEEE PCME Mock Test - 10 - Question 9

Consider f (x)   = x2/| x | , x ≠ 0, f(x)   = 0, x = 0

VITEEE PCME Mock Test - 10 - Question 10

The differential equation of the family of curves y2=4a (x+a) is

VITEEE PCME Mock Test - 10 - Question 11

The solution of the equation (1+x2)(1+y)dy+(1+x)(1+y2)dx=0 is

VITEEE PCME Mock Test - 10 - Question 12

Which equation has the solution, y = 4sin3x?

VITEEE PCME Mock Test - 10 - Question 13

Let A = { x ∈ R : x ≠ 0, − 4 ≤ x ≤ 4 } and f : A → R is defined by f (x)   = | x |/x for x ∈ A . Then the range of f is

VITEEE PCME Mock Test - 10 - Question 14

The solution of (x + y + 1)  dy/dx = 1 is

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 14


⇒ z - log(z + 1) = x + c ⇒ x + y + 1 = log(x + y + 2) + x + c ⇒ y = log(x + y + 2) + log c
⇒ ey = (x + y + z)c ⇒ x + y + 2 = cey

VITEEE PCME Mock Test - 10 - Question 15

∫tan-1[(2x)/(1-x2)]dx=

VITEEE PCME Mock Test - 10 - Question 16

The derivative of 

VITEEE PCME Mock Test - 10 - Question 17

∫[(3x3-2√x)/(x)] dx =

VITEEE PCME Mock Test - 10 - Question 18

tan[(1/2)cos-1(√5/3)]=

VITEEE PCME Mock Test - 10 - Question 19

What is the value of 

VITEEE PCME Mock Test - 10 - Question 20

if f(m) = 3, f'(m) = 2, g(m) = - 1 and g'(m) = 2 is

VITEEE PCME Mock Test - 10 - Question 21

Directions: Study the following information and answer the question that follows.

The table below shows the percentage profit or loss of five different commodities based on the sum of cost price and shipping cost.

Q. What is the Percentage of the Selling price of vegatable oil and cost price of salt ?

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 21

Selling price of Vegetable oil = 200 + 50 + 25 = $275 million
Cost price of salt = Selling price + Loss = 80 + 30 = $110 million
Therefore, required percentage = 275/110 x 110 = 250%

VITEEE PCME Mock Test - 10 - Question 22

Directions: Study the following information and answer the question that follows.

The table below shows the percentage profit or loss of five different commodities based on the sum of cost price and shipping cost.

Q. What is the difference between the selling price of Wine and that of Vegetable oil?

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 22

Total cost price of Wine = 600 + 40 = $640 million
Selling price of Wine = 100 + Profit Percent/100 x CP
= 100 + 7/100 x 640 = $684.8 million
Selling price of Vegetable oil = 200 + 50 + 25 = $275 million
Therefore, required difference = 684.8 - 275 = $409.8 million

VITEEE PCME Mock Test - 10 - Question 23

Directions: Study the following information and answer the question that follows.

The table below shows the percentage profit or loss of five different commodities based on the sum of cost price and shipping cost.

Q. What is the ratio of the loss on Grains to that on Salt?

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 23

Cost price of Grains = 100/100 - Loss Percent x SP
= 100/100 -5 x 500 = 100/95 x 500 million
Loss on Grains = CP of Grains - SP of Grains = 50000/95 - 500 = 2500/95 million

Loss on Salt = $30 million

Therefore, required ratio = 2500/95 : 30 = 50 : 57

VITEEE PCME Mock Test - 10 - Question 24

Directions: Study the given information and answer the following question.
The table given below shows the estimated cost (in Rs. lakh) of a project of laying a railway line between two places, the project began in 1988 and was completed in 1991.

Q. How many times approximately was the total cost of materials to the total labour cost for all the years?

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 24

Total material cost = (95 + 80 + 75 + 70 + 45 + 60 + 15 + 12 + 16 + 25 + 18 + 21) = 532
Total labour cost = (2.1 + 25 + 20 + 18) = 65.1
Therefore, total material cost was approximately 8 times the total labour cost.

VITEEE PCME Mock Test - 10 - Question 25

Anil buys 12 toys and labels each with the same selling price. He sells 8 toys initially at 20% discount on the labeled price. Then he sells the remaining 4 toys at an additional 25% discount on the discounted price. Thus, he gets a total of Rs 2112, and makes a 10% profit. With no discounts, his percentage of profit would have been

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 25

Let the CP of the each toy be “x”. CP of 12 toys will be “12x”. Now the shopkeeper made a 10% profit on CP. This means that

12x(1.1)= 2112 or x=160 . Hence the CP of each toy is ₹160.

Now let the SP of each toy be “m”. Now he sold 8 toys at 20% discount. This means that 8m(0.8) or 6.4m

He sold 4 toys at an additional 25% discount. 4m(0.8)(0.75)=2.4m  Now 6.4m+2.4m=8.8m=2112 or m=240

Hence CP= 160 and SP=240. Hence profit percentage is 50%.

VITEEE PCME Mock Test - 10 - Question 26

A person who has a certain amount with him goes to market. He can buy 50 oranges or 40 mangoes. He retains 10% of the amount for taxi fares and buys 20 mangoes and of the balance, he purchases oranges. Number of oranges he can purchase is:

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 26

The person can buy 50 oranges or 40 mangoes.

Let the price of one orange be Rs. x

Total amount the person has = Rs. 50x

40 mangoes cost 50x, So one mango costs 1.25x

10% of the total amount is retained for taxi fare = 10% of 50x = 5x

20 mangoes bought for 20 x 1.25x = 25x

Money left with the person = 50x – (Taxi fare) – (Mangoes cost)

= 50x – 5x – 25= 20x

One Orange was for Rs. x, Therefore, 20 oranges can be bought with Rs. 20 x

Thus, the person bought 20 oranges.

VITEEE PCME Mock Test - 10 - Question 27

A report consists of 20 sheets each of 55 lines and each such line consists of 65 characters. This report is reduced onto sheets each of 65 lines such that each line consists of 70 characters. The percentage reduction in number of sheets is closest to:

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 27

No. of Characters in one line = 65

No. of characters in one sheet = No. of lines × No. of characters per line = 55 × 65

Total number of characters = No. of sheets × No. of characters in one sheet = 20 × 55 × 65 = 71500

If the report is retyped –

New sheets have 65 lines, with 70 characters per line

No. of characters in one sheet = 65 × 70

Number of pages required,

Hence, 16 pages will be required if report is retyped.

Hence, reduction of (20 – 16) = 4 pages

% reduction is = (4/20) x 100 = 20%

VITEEE PCME Mock Test - 10 - Question 28

Directions: Study the following graph carefully and answer the questions given below:

Production (in Lakhs) of  Widgets  & Percentage defect over the years in five factories A, B, C, D, E.

Q. The average number of widgets that were produced in the year 2002 formed what percent of the widgets that were produced in the year 2006?

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 28

The total of the widgets that were produced in the year 2002 was 263(Lakhs) and the ones produced in the year 2006 were 280(Lakhs).

The percentage value is (263/280) x 100 = 94 % (approx).

VITEEE PCME Mock Test - 10 - Question 29

Directions: Study the following graph carefully and answer the questions given below:

Production (in Lakhs) of  Widgets  & Percentage defect over the years in five factories A, B, C, D, E.

Q. What was the difference in the number of widgets of factory C which were free from any defect in the years 2004 and 2006?

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 29

Required difference = (87% of 42000) – (92% of 40000) = 36540 – 36800 = -260

So the difference is 260.

VITEEE PCME Mock Test - 10 - Question 30

Directions: Study the following table carefully and answer the questions given below.

Number of candidates appeared (App.) and percentage of candidates qualified (Qual.) under different disciplines over the years.

Q. Approximately, what was the percentage increase in the number of candidates who appeared under the German stream from 2013 to 2014(approx)?

Detailed Solution for VITEEE PCME Mock Test - 10 - Question 30

Number of students in the year 2013 were 985 and they increased to 1215,

so there was a net increase of 230.

Talking of percentage there was an increase of 230 in the initial value 985,

so the increase will be (230/985)*100 = 23.35

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