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Vector Calculus NAT Level - 2 - Free MCQ Test with solutions for Physics


MCQ Practice Test & Solutions: Vector Calculus NAT Level - 2 (10 Questions)

You can prepare effectively for Physics Topic wise Tests for IIT JAM Physics with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Vector Calculus NAT Level - 2". These 10 questions have been designed by the experts with the latest curriculum of Physics 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 45 minutes
  • - Number of Questions: 10

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*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 1

Evaluate  where   and S is the part of the plane 2x + 3y + 6z = 12 which is located in the first octant.


Detailed Solution: Question 1




= 24
The correct answer is: 24

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 2

Find the value of constant (a + b + c) so that the directional derivative of the function f = axy2 + byz + cz2x3 at the point (1, 2, –1) has maximum magnitude 64 in the direction  parallel to y axis :


Detailed Solution: Question 2


  lies along y axis
So, 4a + 3c = 0
2b – 2c = 0

The correct answer is: -20

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 3

Evaluate the    along the portion from path (1, 0, 1) to (3, 4, 5) of the curve C, which is the intersection of the surface z2 = x2 + y2 and z = y + 1.


Detailed Solution: Question 3

  can be expressed as gradient of scalar function 

written the common term once

The line integral  along the portion (1, 0, 1) to (3, 4, 5)

= (375 + 108 – 20) – (1)
= 463 – 1
= 462

The correct answer is: 462

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 4

The work done by the force   in moving a particle over circular path x2 + y2 = 1, z = 0 from (1, 0, 0) to (0, 1, 0) is :


Detailed Solution: Question 4

on the curve 

The correct answer is: -4.142

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 5

Evaluate  where C is the path shown in figure.


Detailed Solution: Question 5

Path AO
y
 = 1
dy = 0

Path OB
x
2 + y2 = 1



= –0.416
The correct answer is: -0.416

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 6

Let C be any curve x2 + y2 + z2 = 4, z > 0 and the vector field 

find out 

(Ans. upto three decimal places)


Detailed Solution: Question 6

Consider a closed surface  consisting of S and S' i.e 


The correct answer is: 25.132

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 7

The value of the  and C is the curve y2 = x joining (0, 0) to (1, 1) is (correct upto three decimal places)


Detailed Solution: Question 7

The correct answer is: 0.583

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 8

Find the value of 


Detailed Solution: Question 8

Let 

The correct answer is: 0

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 9

  along the curve x = sin θ cos θ, y sin2 θ, z = cos θ with θ  increasing from 0 to π/2. Find the value of α + β.


Detailed Solution: Question 9


xz dx + y dy + xdz
Along the given curve, we have

Putting values

The correct answer is: 43

*Answer can only contain numeric values
Vector Calculus NAT Level - 2 - Question 10

If f(x, y, z) = x2y + y2z + z2x for all (x, y, x) ∈ R3 and   then the value of  at (2, 2, 2) is :


Detailed Solution: Question 10


Hence, 

The correct answer is: 12

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