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Test: Motion & Time - UPSC MCQ


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10 Questions MCQ Test Science & Technology for UPSC CSE - Test: Motion & Time

Test: Motion & Time for UPSC 2024 is part of Science & Technology for UPSC CSE preparation. The Test: Motion & Time questions and answers have been prepared according to the UPSC exam syllabus.The Test: Motion & Time MCQs are made for UPSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Motion & Time below.
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Test: Motion & Time - Question 1

Change in position with respect to the surroundings is called

Detailed Solution for Test: Motion & Time - Question 1
  • Motion refers to the change in position of an object over time.
  • It occurs when an object moves from one location to another relative to a reference point or its surroundings.
  • Common examples include a car driving down a road, a person walking, or a bird flying.
  • Acceleration, momentum, and force are related concepts but do not specifically define the change in position itself.
Test: Motion & Time - Question 2

The earliest clocks for measuring time during day were

Detailed Solution for Test: Motion & Time - Question 2

Sundials were used for measuring time in earlier days on the basis of shadow position.

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Test: Motion & Time - Question 3

The speed of the vehicle is recorded by

Detailed Solution for Test: Motion & Time - Question 3

The speed of vehicle at particular point of time is recorded by speedometer fitted on the dashboard of vehicle.

Test: Motion & Time - Question 4

The basic unit of speed is:

Detailed Solution for Test: Motion & Time - Question 4

The basic unit of distance is metre (m). The basic unit of time is second (s). Since we know that s=d/t. Therefore, the basic unit of speed is m/s.

So option D is the correct answer. 

Test: Motion & Time - Question 5

Distance-time graph is straight line for

Detailed Solution for Test: Motion & Time - Question 5

- A distance-time graph represents how distance changes with time.
- A straight line on a distance-time graph indicates a constant rate of change of distance over time.
- Uniform motion means an object travels equal distances in equal intervals of time.
- Therefore, for uniform motion, a distance-time graph is a straight line.
- Non-uniform motion, discontinuous motion, and accelerated motion would result in curves or discontinuities, not straight lines.

Test: Motion & Time - Question 6

A car is moving with 72 km/hrs. The speed of the car in m/s is

Detailed Solution for Test: Motion & Time - Question 6

 We know , 
1 km=1000m , 1 hour=3600s
1km/h=1000/3600m/s=5/18m/s
72km/h=72×5/18m/s
=4×5m/s
=20m/s.

Test: Motion & Time - Question 7

A cyclist travels at a speed of 30 km/h for 20 minutes, and then increases their speed to 50 km/h for the next 10 minutes. What is the total distance covered by the cyclist?

Detailed Solution for Test: Motion & Time - Question 7

Test: Motion & Time - Question 8

Which instrument in a vehicle is used to measure the total distance traveled?

Detailed Solution for Test: Motion & Time - Question 8

- The correct instrument used to measure the total distance traveled by a vehicle is the odometer.

- An odometer records the cumulative distance that a vehicle has traveled over its lifetime, usually displayed in miles or kilometers.

- Other instruments mentioned:
- Speedometer: Measures the current speed of the vehicle.
- Thermometer: Measures temperature, not applicable for vehicle distance.
- Barometer: Measures atmospheric pressure, unrelated to vehicle travel.

Thus, option C: Odometer is correct.

Test: Motion & Time - Question 9
Which of the following motions is characterized by an object moving back and forth along the same path?
Detailed Solution for Test: Motion & Time - Question 9
Oscillatory motion involves an object moving to and fro about a fixed point, such as the motion of a pendulum or the hands while running.
Test: Motion & Time - Question 10

If a simple pendulum completes 20 oscillations in 32 seconds, what is its time period?

Detailed Solution for Test: Motion & Time - Question 10

Time period = Total time taken/Number of oscillations
= 32s/20
=1.6 s
Time period = 1.6 s

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