MCQ: Test: Direction Sense- 1 - SSC CGL MCQ

From the common explanation, we get the distance between H and F is HA + BG + CE = 6 cm + 6 cm + 6 cm = 18 cm.
Hence, Option C is correct.
Final Arrangement:

Common Explanation:
Reference:
Point B is 20cm north of point A.
Point A is 6cm east of point H.
Point B is 6cm west of point G.
Point C is 6cm west of point E.
Point C is the midpoint of points D and G.
Point E is 10cm north of point F.
Point D is 20cm south of point G.
Inference:
From the above statement, we get the final figure below:

From the common explanation, we can see that point H is in south west direction with respect to point G.
Hence, Option A is correct.
Final Arrangement:

Common Explanation:
Reference:
Point B is 20cm north of point A.
Point A is 6cm east of point H.
Point B is 6cm west of point G.
Point C is 6cm west of point E.
Point C is the midpoint of points D and G.
Point E is 10cm north of point F.
Point D is 20cm south of point G.
Inference:
From the above statement, we get the final figure below:

Using Pythagoras theorem, we get
EG² = CG² + CE²
EG² = 10² + 6² = 100 + 36 = 136
EG =2√34 cm
And the point E is in south east direction with respect to point G.
Hence, Option B is correct.
Final Arrangement:

Common Explanation:
Reference:
Point B is 20cm north of point A.
Point A is 6cm east of point H.
Point B is 6cm west of point G.
Point C is 6cm west of point E.
Point C is the midpoint of points D and G.
Point E is 10cm north of point F.
Point D is 20cm south of point G.
Inference:
From the above statement, we get the final figure below:

From the information given in the question we get the following arrangement:

We can see that point S is in south west direction with respect to point P.
Hence, Option A is correct.

From the information given in the question we get the following arrangement:

We can see that point P is in north direction with respect to point T.
Hence, Option B is correct.

Option D is correct.
Final Arrangement:

Common Explanation:
References:
Q is to the south of P.
A is to the west of B, which is to the west of C.
P is to the west of A.
Inferences:
From the above statement, we get the final figure below:

From the common explanation, we can see that A is to the north west of D.
Hence, Option A is correct.
Final Arrangement:

Common Explanation:
References:
Q is to the south of P.
A is to the west of B, which is to the west of C.
D is to the south of B.
P is to the west of A.
Inferences:
From the above statement, we get the final figure below:
​​​​​​​​​​​​​​

From the common explanation, we can see that point R is in north west direction with respect to point P.
Hence, Option B is correct.
Final Arrangement:

Common Explanation:
References:
Anurag is standing at point P, facing the north direction.
He starts walking towards west and reaches point Q after walking 12m.
He moves 12m to his right towards point R.
From point R, he again moves his right to reach point S, which is 8m apart from point R.
He again moves towards right to reach point T after covering a distance of 6m from point S.
Finally, he moves 12m to his left to reach point U.
Inferences:
From the above statement, we get the final figure below:

Using Pythagoras theorem, we get
PU² = 6² + 8² = 36 + 64 = 100
PU = 10m
Hence, Option C is correct.
Final Arrangement:

Common Explanation:
References:
Anurag is standing at point P, facing the north direction.
He starts walking towards west and reaches point Q after walking 12m.
He moves 12m to his right towards point R.
From point R, he again moves his right to reach point S, which is 8m apart from point R.
He again moves towards right to reach point T after covering a distance of 6m from point S.
Finally, he moves 12m to his left to reach point U.
Inferences:
From the above statement, we get the final figure below:
​​​​​​​

From the common explanation, we can see that point U is in south east direction of point S.
Hence, Option B is correct
Final Arrangement:

Common Explanation:
References:
Anurag is standing at point P, facing the north direction.
He starts walking towards west and reaches point Q after walking 12m.
He moves 12m to his right towards point R.
From point R, he again moves his right to reach point S, which is 8m apart from point R.
He again moves towards right to reach point T after covering a distance of 6m from point S.
Finally, he moves 12m to his left to reach point U.
Inferences:
From the above statement, we get the final figure below:
​​​​​​​

From the common explanation, we can see that house P is in south west direction with respect to house S.
Hence, Option D is correct.
Common Explanation:
References:
P is 8 km north of Q.
S is 10 km east of U, which is 12 km south of T.
S is 8 km north of R, which is 12 km east of P. 
Inferences:
From the above statement, we get the final figure below:

Using Pythagoras theorem, we get
AQ² = AP² + PQ²
AQ² = 6² + 8² = 36 + 64 = 100
AQ =10 km
Hence, Option B is correct.
Common Explanation:
References:
P is 8 km north of Q.
S is 10 km east of U, which is 12 km south of T.
S is 8 km north of R, which is 12 km east of P. 
Inferences:
From the above statement, we get the final figure below:

From the common explanation:

Using Pythagoras theorem, we get
VY² = YZ² + ZV²
VY² = 14² + 16² = 196 + 256 = 452
VY = 2√113 m
And V is in south east direction with respect to Y.
Hence, Option D is correct.
Common Explanation:
References:
W is 30m to the south of Y, which is 16m to the west of T.
S is 12m to the west of U, which is the west of Y.
V is 14m to the south of T.
V is 16m to the north of A.
Z is 28m to the east of X.
The distance between V and X is equal to the distance between T and U.
The distance between X and Z is double the distance between Y and Z, which is to the south of Y.
Inferences:
From the above statement, we get the final figure below:

From the common explanation, we can see that point S is in north west direction with respect to point A.
Hence, Option D is correct.
Common Explanation:
References:
W is 30m to the south of Y, which is 16m to the west of T.
S is 12m to the west of U, which is the west of Y.
V is 14m to the south of T.
V is 16m to the north of A.
Z is 28m to the east of X.
The distance between V and X is equal to the distance between T and U.
The distance between X and Z is double the distance between Y and Z, which is to the south of Y.
Inferences:
From the above statement, we get the final figure below:

From the common explanation, we can see that all makes straight line except SZ.
Hence, Option D is correct.
Common Explanation:
References:
W is 30m to the south of Y, which is 16m to the west of T.
S is 12m to the west of U, which is the west of Y.
V is 14m to the south of T.
V is 16m to the north of A.
Z is 28m to the east of X.
The distance between V and X is equal to the distance between T and U.
The distance between X and Z is double the distance between Y and Z, which is to the south of Y.
Inferences:
From the above statement, we get the final figure below: