MCQ: Fractions & Decimals - 3 - SSC CGL MCQ

4*A + 7/B + 2*C + 5/D + 6*E =47.2506
=> 4 * A + 7/B + 2 *C + 5/D + 6*E = 40 + 7 + 0.2 + 0.05 + 0.0006
Comparing the terms on both sides, we get:
4*A = 40, 7/B = 7, 2*C = 0.2, 5/D = 0.05, 6*E = 0.0006
A = 10,
B = 1,
C = 0.1,
D = 100,
E = 0.0001.
5*A + 3*B + 6*C + D + 3*E = (5*10) + (3*1) + (6*0.1) + 100 + (3*0.0001)
= 50 + 3 + 0.6 + 100 + 0.003 = 153.6003

= 72 + 9 = 81 cm

Required decimal:

= 1/60 x 60

= 1/3600 = .00027

Let numerator be x, then denominator = 11 – x.

⇒ 528 – 96x = 143 – 24x + x²

⇒ x² + 72x – 385 = 0

⇒ x² + 77x – 5x – 385 = 0

⇒ x(x + 77) − 5(x + 77) = 0

⇒ (x - 5) (x + 77) = 0 ⇒ x = 5

Denominator = 11 - 5 = 6

Difference = 6 - 5 = 1

Let the original fraction be 

x + 7 = 2x + 2

x = 7 − 2 = 5

Required sum = x + x + 3 = 2x + 3 = 10 + 3 = 13

Given expression:

= (a - b)
= (0.96 - 0.1)
= 0.86

Let the number be x.

x = 15 × 3 × 4 = 180

Now, required number

Required sum = 250 + 99 = 349

First take LCM of denominators.

Here it is 210.

Then multiply with multiplier that makes denominators 210.

By doing this.

First becomes 70/210, 84/210 and soon.

Hence ans d.

Let the number be x.

Suppose total income = Rs.x

x = 7560

Clearly, 0.8 lies between 0.75 and 0.833.