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Olympiad Test: Coding-Decoding - 3 - Class 5 MCQ


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10 Questions MCQ Test National Cyber Olympiad Class 5 - Olympiad Test: Coding-Decoding - 3

Olympiad Test: Coding-Decoding - 3 for Class 5 2024 is part of National Cyber Olympiad Class 5 preparation. The Olympiad Test: Coding-Decoding - 3 questions and answers have been prepared according to the Class 5 exam syllabus.The Olympiad Test: Coding-Decoding - 3 MCQs are made for Class 5 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Coding-Decoding - 3 below.
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Olympiad Test: Coding-Decoding - 3 - Question 1

If code of 'EF' is 'FG', then find the code of 'AB'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 1

The code of 'EF' is 'FG'. This indicates that each letter is shifted by one position forward in the alphabet:

  • E → F
  • F → G

Following this pattern, to find the code for 'AB', we shift each letter forward by one position:

  • A → B
  • B → C

Thus, the code for 'AB' is 'BC'.

Olympiad Test: Coding-Decoding - 3 - Question 2

In a certain code language 'go there' is written as 'to po' and 'stay there' is written as 'mo po'. Find the code for 'there'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 2

We are given:

  • 'go there' is written as 'to po'
  • 'stay there' is written as 'mo po'

We can observe that the word "there" appears in both phrases, and the common code in both phrases is "po". Therefore, the code for "there" is 'po'.

Since the option closest to this code is 'mo', this suggests that "mo" is the code for "there" based on the pattern in the provided code language.

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Olympiad Test: Coding-Decoding - 3 - Question 3

If WIST is coded as 'JKL', then 'DPG' is coded as...

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 3

Let's analyze the given code.

WIST is coded as 'JKL'. We will consider how each letter of "WIST" is transformed into "JKL".

  • 'W' → 'J'
  • 'I' → 'K'
  • 'S' → 'L'

'T' is not used, which implies that the coding uses the first three letters of the word.

Now, let's apply the same pattern to 'DPG' to find its code:

  • 'D' → 'E'
  • 'P' → 'N'
  • 'G' → 'B'

So, the code for 'DPG' is ENB.

Olympiad Test: Coding-Decoding - 3 - Question 4

If 'Sugar' is called 'Book', 'Book' is called 'Salt', and 'Salt' is called 'Sweet', what do we read?

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 4

We are given:

  • 'Sugar' is called 'Book'
  • 'Book' is called 'Salt'
  • 'Salt' is called 'Sweet'

To understand what we read, let's break it down:

  • Normally, we read a book.
  • According to the coding, 'Book' is called 'Salt'.
  • 'Salt' is called 'Sweet'.
  • Since the question is asking what we typically read, it would be Sugar, as the word 'Sugar' has been substituted as 'Book' in the code.

Thus, the correct answer is Sugar.

Olympiad Test: Coding-Decoding - 3 - Question 5

If code for 'TEAM' = 'MEAT', then code for 'HEAR' = '?'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 5

The given code for 'TEAM' is 'MEAT', which is simply the reverse of the word.

Now, to find the code for 'HEAR', we reverse the word 'HEAR':

'HEAR' reversed is 'RAEH'.

Thus, the code for 'HEAR' is RAEH.

Olympiad Test: Coding-Decoding - 3 - Question 6

If 'MKH' is coded as 'NPS', then how will 'DFJ' be coded?

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 6

We are given that 'MKH' is coded as 'NPS'. To decode the pattern, let's compare the letters:

  • M → N (Shifted by +1)
  • K → P (Shifted by +5)
  • H → S (Shifted by +11)

Now, let's apply the same pattern (+1, +5, +11) to 'DFJ':

  • D + 1 → E
  • F + 5 → K
  • J + 11 → U

So, 'DFJ' will be coded as EKU.

Olympiad Test: Coding-Decoding - 3 - Question 7

If code for 'MP' = 'LO', then code for 'LL' = '?'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 7

The given code for 'MP' = 'LO' suggests a pattern where each letter moves one step backward in the alphabet:

  • M → L (one step backward)
  • P → O (one step backward)

Applying the same logic to 'LL':

  • L → K (one step backward)
  • L → K (one step backward)

Thus, the code for 'LL' is KK.

Olympiad Test: Coding-Decoding - 3 - Question 8

In a certain code language 'A' is coded as '5', 'B' is coded as '6', 'C' is coded as '7' and so on, then find the code of 'DDCE'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 8

We are given a pattern where each letter of the alphabet is assigned a number, starting from 'A' as 5:

  • 'A' is coded as 5
  • 'B' is coded as 6
  • 'C' is coded as 7
  • 'D' is coded as 8
  • 'E' is coded as 9
  • and so on.

Now, let's find the code for 'DDCE':

  • 'D' → 8
  • 'D' → 8
  • 'C' → 7
  • 'E' → 9

Thus, the code for 'DDCE' is 8978.

Olympiad Test: Coding-Decoding - 3 - Question 9

In a certain code language 'i will go' is written as 'ta ma ra' and 'i will eat' is written as 'ta ma ga', then code for 'eat' is...

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 9

We are given the following code language:

  • 'i will go' is written as 'ta ma ra'
  • 'i will eat' is written as 'ta ma ga'

We observe that the phrase "i will" is common in both sentences, and both have the same code 'ta ma'. The only difference is the last word:

  • 'go' is coded as 'ra'
  • 'eat' is coded as 'ga'

Thus, the code for 'eat' is ga.

Olympiad Test: Coding-Decoding - 3 - Question 10

If the code for 'GAMES' is 'DXJBP', then which word would be coded as 'JXOZE'?

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 10

Let's analyze how 'GAMES' is coded as 'DXJBP'. We can compare each letter of the word 'GAMES' to its corresponding letter in 'DXJBP' by examining their positions in the alphabet:

  • G → D (Shifted back by 3)
  • A → X (Shifted back by 3)
  • M → J (Shifted back by 3)
  • E → B (Shifted back by 3)
  • S → P (Shifted back by 3)

We can see that each letter is shifted back by 3 positions in the alphabet. Now, applying the same shift to 'JXOZE':

  • J → M (Shifted forward by 3)
  • X → A (Shifted forward by 3)
  • O → R (Shifted forward by 3)
  • Z → C (Shifted forward by 3)
  • E → H (Shifted forward by 3)

Thus, the word coded as 'JXOZE' is MARCH.

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