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QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) - JEE MCQ


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5 Questions MCQ Test - QUIZ 1: Newton^s Laws Of Motion(#Free Test Series)

QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) for JEE 2024 is part of JEE preparation. The QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) questions and answers have been prepared according to the JEE exam syllabus.The QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) below.
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QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) - Question 1

A block of mass 2 Kg rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) - Question 2

A block of mass 0.1 Kg is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is 

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QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) - Question 3

 A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A plumb bob is suspended from the roof of the car by a light rigid rod. The angle made by the rod with the vertical is (Take g= 10 m/s²) 

QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) - Question 4

During paddling of a bicycle, the force of friction exerted by the ground on the two wheels is such that it acts

QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) - Question 5

 A ship of mass 3×107 kg initially at rest, is pulled by a force of 5×104 N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is 

Detailed Solution for QUIZ 1: Newton^s Laws Of Motion(#Free Test Series) - Question 5

Acceleration provided by the acting force, a = 50000N / 30000000kg = 5/3000 m/s2 
As the acceleration is only provided to a distance of 3m
Thus net velocity, v = √2as
=  (2 x 5/3000 x 3)1/2 m/s
=   1/10 m/s
= 0.1 m/s

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