JEE Exam > JEE Tests > Mathematics (Maths) for JEE Main & Advanced > Application of Integrals - 2 - JEE MCQ
Application of Integrals - 2 - JEE MCQ
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30 Questions MCQ Test Mathematics (Maths) for JEE Main & Advanced - Application of Integrals - 2
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Application of Integrals - 2 - Question 1
Area included between curves y = x2 – 3x + 2 and y = – x2 + 3x – 2 is -
Detailed Solution for Application of Integrals - 2 - Question 1
Application of Integrals - 2 - Question 2
The area bounded by the parabola y2 = x, the line y = 4 and y-axis -
Detailed Solution for Application of Integrals - 2 - Question 2
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Application of Integrals - 2 - Question 3
The area of the region bounded by the lines y = |x – 2|, x = 1,x = 3 and the x axis is
Detailed Solution for Application of Integrals - 2 - Question 3
Application of Integrals - 2 - Question 4
The area bounded by the curve xy –3x –2y –10 = 0, x-axis and straight lines x = 3, x = 4 is
Detailed Solution for Application of Integrals - 2 - Question 4
Application of Integrals - 2 - Question 5
The area bounded by y = x e|x| and the lines | x | = 1, y = 0 is -
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Application of Integrals - 2 - Question 6
The area between the parabola y2 = 4ax and its latus rectum is -
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Application of Integrals - 2 - Question 7
The area bounded by the graph y = |[x – 3]| the x-axis and the lines x = –2 and x = 3 is ([.] denotes the greatest integer function) -
Detailed Solution for Application of Integrals - 2 - Question 7
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Application of Integrals - 2 - Question 9
Area bounded by the curve y2 (2a – x) = x3 and the line x = 2a is -
Detailed Solution for Application of Integrals - 2 - Question 9
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Application of Integrals - 2 - Question 12
The area bounded by the curve | x | + y = 1 and axis of x is given by -
Detailed Solution for Application of Integrals - 2 - Question 12
Application of Integrals - 2 - Question 13
The area of the region bounded by y = |x – 1| and y = 1 is -
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Application of Integrals - 2 - Question 14
The area in the first quadrant between x2 + y2 = π2 and y = sin x is -
Detailed Solution for Application of Integrals - 2 - Question 14
Detailed Solution for Application of Integrals - 2 - Question 15
Application of Integrals - 2 - Question 16
The line y = mx bisects the area enclosed by the lines x = 0, y = 0, x =3/2 and the curve y = 1 + 4x – x2. The value of m is -
Detailed Solution for Application of Integrals - 2 - Question 16
Application of Integrals - 2 - Question 17
The area of the figure bounded by the curves y = |x – 1| and y = 3 – | x | is -
Detailed Solution for Application of Integrals - 2 - Question 17
Application of Integrals - 2 - Question 18
The area bounded by the curve y = x2 + 4x + 5 , the axes of co-ordinates & the minimum ordinate is
Detailed Solution for Application of Integrals - 2 - Question 18
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Application of Integrals - 2 - Question 20
The area of the region bounded by the curves y = | x – 2 | and y = 4 – | x | is -
Detailed Solution for Application of Integrals - 2 - Question 20
Application of Integrals - 2 - Question 21
The area bounded by y = x2 + 2 and y = 2|x| – cos πx is equal to -
Detailed Solution for Application of Integrals - 2 - Question 21
Detailed Solution for Application of Integrals - 2 - Question 22
Detailed Solution for Application of Integrals - 2 - Question 23
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Detailed Solution for Application of Integrals - 2 - Question 25
Application of Integrals - 2 - Question 26
The area of smaller portion bounded by |y| = – x + 1 and y2 = 4x is -
Detailed Solution for Application of Integrals - 2 - Question 26
Application of Integrals - 2 - Question 27
The area enclosed between the parabolas y2 = 4ax and x2 = 4by is -
Detailed Solution for Application of Integrals - 2 - Question 27
Detailed Solution for Application of Integrals - 2 - Question 28
Detailed Solution for Application of Integrals - 2 - Question 29
Detailed Solution for Application of Integrals - 2 - Question 30
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