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Test: Electrochemistry (November 16) - NEET MCQ


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15 Questions MCQ Test Daily Test for NEET Preparation - Test: Electrochemistry (November 16)

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Test: Electrochemistry (November 16) - Question 1

On electrolysis of dilute sulphuric acid using platinum electrodes, the product obtained at the anode will be [1992]

Detailed Solution for Test: Electrochemistry (November 16) - Question 1

 At anode :

Test: Electrochemistry (November 16) - Question 2

The standard reduction poten tials at 25°C of
Li+/ Li, Ba 2+ / Ba, Na+ / Na
and Mg 2+ / Mg are – 3.03, – 2.73, – 2.71 and – 2.37 volt respectively. Which one of the following is the strongest oxidising agent? [1994]

Detailed Solution for Test: Electrochemistry (November 16) - Question 2

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Test: Electrochemistry (November 16) - Question 3

The most durable metal plating on iron to protect against corrosion is [1994]

Detailed Solution for Test: Electrochemistry (November 16) - Question 3

This is because zinc has higher oxidation potential than Ni, Cu and Sn. The process of coating of iron surface with zinc is known as galvanization. Galvanized iron sheets maintain their lustrue due to the formation of protective layer of basic zinc carbonate.

Test: Electrochemistry (November 16) - Question 4

An electr och emical cell is set up as: Pt; H2 (1atm)|HCl(0.1 M) || CH3COOH (0.1 M)| H2 (1atm); Pt. The e.m.f of this cell will not be zero, because [1995]

Detailed Solution for Test: Electrochemistry (November 16) - Question 4

For a concentration cell having different concentrations of ions.

If all the concentrations are identical then obviously the cell voltage is zero. But as the pH of 0.1 M HCl (strong acid) & pH of 0.1M CH3 COOH is (weak acid) not same, therefore the cell voltage is not zero.

Test: Electrochemistry (November 16) - Question 5

If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of 0.4 cm–1, then its molar conductance in ohm–1 cm2 mol–1 is [1997]

Detailed Solution for Test: Electrochemistry (November 16) - Question 5

Given molarity = 0.01 M Resistance = 40 ohm;

Cell constant

Specific conductivity (k)

Molar conductance  

Test: Electrochemistry (November 16) - Question 6

 Standard potentials (Eº) for some half-reactions are given below :



 Eº = +1.45 V

Based on the above, which one of the following statements is correct ? [1997]

Detailed Solution for Test: Electrochemistry (November 16) - Question 6

In elctrochemical series, Sn is above hydrogen and Hg below hydrogen. Elements above hyrogen are reducing in nature while below hydrogen are oxidising in nature.

Test: Electrochemistry (November 16) - Question 7

Without losing its concentration ZnCl2 solution cannot be kept in contact with [1998]

Detailed Solution for Test: Electrochemistry (November 16) - Question 7

With out losing its concentrati on Zn Cl2 solution can not kept in contact with Al because Al is more reactive than Zn due to electrode (reduction) potential.

Test: Electrochemistry (November 16) - Question 8

What is the Eºcell for the reaction

at 25ºC if the equilibrium constant for the reaction is  1 × 106? [1999]

Detailed Solution for Test: Electrochemistry (November 16) - Question 8

Test: Electrochemistry (November 16) - Question 9

 Specific conductance of a 0.1 N KCl solution at 23ºC is 0.012 ohm–1 cm–1. Resistance of cell containing the solution at same temperature was found to be 55 ohm. The cell constant is [2000]

Detailed Solution for Test: Electrochemistry (November 16) - Question 9

Given specific conductance of the solution (k) = 0.012 ohm–1 cm–1 and resistance (R) = 55 ohm. We know that cell constant = Specific conductance × Observed resistance = 0.012 × 55= 0.66cm–1.

Test: Electrochemistry (November 16) - Question 10

The most convenient method to protect the bottom of ship made of iron is [2001]

Detailed Solution for Test: Electrochemistry (November 16) - Question 10

For bottom of ship to be protected it is connected with more reactive metal than iron like magnesium. This technique is called cathodic protection.

Test: Electrochemistry (November 16) - Question 11

Which reaction is not feasible? [2002]

Detailed Solution for Test: Electrochemistry (November 16) - Question 11

reaction is not possible because Br ion is not oxidised in Br2 with I2 due to higher electrode (oxidation) potential of I2 than bromine.

Test: Electrochemistry (November 16) - Question 12

In electrolysis of NaCl when Pt electrode is taken then H2 is liberated at cathode while with Hg cathode it forms sodium amalgam. This is because [2002]

Detailed Solution for Test: Electrochemistry (November 16) - Question 12

In electrolysis of NaCl when Pt electrode is taken then H2 liberated at cathode while with Hg cathode it forms sodium amalgam because more voltage is required to reduce H+ at Hg than Pt.z

Test: Electrochemistry (November 16) - Question 13

On the basis of the information available from the reaction

the minimum e.m.f required to carry out an electrolysis of Al2O3 is (F = 96500 C mol–1)

Detailed Solution for Test: Electrochemistry (November 16) - Question 13

ΔG = –nEF

For 1 mol of Al, n = 3

According to question, 827 x1000 = 4 x E x 96500

Test: Electrochemistry (November 16) - Question 14

If , the standard EMF of the reaction Fe + 2Fe3+ → 3Fe2+  will be [2006]

Detailed Solution for Test: Electrochemistry (November 16) - Question 14

Test: Electrochemistry (November 16) - Question 15

The efficiency of a fuel cell is given by [2007]

Detailed Solution for Test: Electrochemistry (November 16) - Question 15

Efficiency of a fuel cell 

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