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Test: SI & CI- 2 - SSC CGL MCQ


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15 Questions MCQ Test SSC CGL Tier 2 - Study Material, Online Tests, Previous Year - Test: SI & CI- 2

Test: SI & CI- 2 for SSC CGL 2024 is part of SSC CGL Tier 2 - Study Material, Online Tests, Previous Year preparation. The Test: SI & CI- 2 questions and answers have been prepared according to the SSC CGL exam syllabus.The Test: SI & CI- 2 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: SI & CI- 2 below.
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Test: SI & CI- 2 - Question 1

In how much time (in years) will Rs. 8000 amount to Rs. 9600 at simple interest at the rate of 5% per annum?

Detailed Solution for Test: SI & CI- 2 - Question 1

Simple interest = (P × t × r)/100

P = Principal

t = Time period

r = Rate of interest

Given,

P = Rs. 8000

r = 5%

Simple Interest = Rs. (9600 - 8000) = Rs. 1600

1600 = (8000 × t × 5)/100

⇒ 400 t = 1600

⇒ t = 4 years

Test: SI & CI- 2 - Question 2

A sum of money doubles itself in 5 years. In how many years will it become four fold (if interest is compounded)?

Detailed Solution for Test: SI & CI- 2 - Question 2

It would take another 5 years to double again. Thus, a total of 10 years to become four fold.

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Test: SI & CI- 2 - Question 3

A sum of money placed at compound interest doubles itself in 3 years. In how many years will it amount to 8 times itself?

Detailed Solution for Test: SI & CI- 2 - Question 3

If it doubles in 3 years, it would become 4 times in 6 year and 8 times in 9 years.

Test: SI & CI- 2 - Question 4

Divide Rs. 3903 between Amar and Akbar such that Amar’s share at the end of 7 years is equal to Akbar’s share at the end of 9 years at 4% p.a. rate of compound interest.

Detailed Solution for Test: SI & CI- 2 - Question 4

Akbars’ share should be such that at 4% p.a. compound interest it should become equal to Amar’s share in 2 years. Checking thorugh the options it is clear that option (a) fits perfectly as 1875 would become 2028 in 2 years @4% p.a. compound interest.

Test: SI & CI- 2 - Question 5

Sanjay borrowed Rs. 900 at 4% p.a. and Rs. 1100 at 5% p.a. for the same duration. He had to pay Rs. 364 in all as interest. What is the time period in years?

Detailed Solution for Test: SI & CI- 2 - Question 5

The interest he pays per year would be 36 + 55 = 91. Thus, in 4 years the interest would amount to Rs. 364.

Test: SI & CI- 2 - Question 6

If a certain sum of money becomes double at simple interest in 12 years, what would be the rate of interest per annum?

Detailed Solution for Test: SI & CI- 2 - Question 6

 100/12 = 8.33%

Test: SI & CI- 2 - Question 7

A sum of Rs. 600 amounts to Rs. 720 in 4 years at Simple Interest. What will it amount to if the rate of interest is increased by 2%?

Detailed Solution for Test: SI & CI- 2 - Question 7

600 becomes 720 in 4 years SI —> SI per year = Rs. 30 and hence the SI rate is 5%.
At 7% rate of interest the value of 600 would become 768 in 4 years. (600 + 28% of 600)

Test: SI & CI- 2 - Question 8

A sum of money invested at simple interest triples itself in 8 years at simple interest. Find in how many years will it become 8 times itself at the same rate?

Detailed Solution for Test: SI & CI- 2 - Question 8

In 8 years, the interest earned = 200% Thus, per year interest rate = 200/8 = 25% To become 8 times we need a 700% increase 700/25 = 28 years.

Test: SI & CI- 2 - Question 9

If Rs. 1100 is obtained after lending out Rs. x at 5% per annum for 2 years and Rs. 1800 is obtained after lending out Rs. y at 10% per annum for 2 years, find x + y.

Detailed Solution for Test: SI & CI- 2 - Question 9

x = Rs. 1000 (As 1000 @ 5% for 2 years = 1100).
Similarly y = Rs. 1500. x +y = 2500.

Test: SI & CI- 2 - Question 10

The population of a city is 200,000. If the annual birth rate and the annual death rate are 6% and 3% respectively, then calculate the population of the city after 3 years.

Detailed Solution for Test: SI & CI- 2 - Question 10

Test: SI & CI- 2 - Question 11

If the simple interest is 10.5% annual and compound interest is 10% annual, find the difference between the interests after 3 years on a sum of Rs. 1000.

Detailed Solution for Test: SI & CI- 2 - Question 11

At 10% compound interest the interest in 3 years would be 33.1% = Rs.331 At 10.5% simple interest the interest in 3 years would be 31.5% = Rs.315 Difference = Rs.16

Test: SI & CI- 2 - Question 12

Find the compound interest on Rs. 64,000 for 1 year at the rate of 10% per annum compounded quarterly (to the nearest integer).

Detailed Solution for Test: SI & CI- 2 - Question 12

64000 x (1.025)4 = 70644.025.
Interest 6644.025 Option (d). None of these is correct.

Test: SI & CI- 2 - Question 13

Find the compound interest at the rate of 10% for 3 years on that principal which in 3 years at the rate of 10% per annum gives Rs. 300 as simple interest.

Detailed Solution for Test: SI & CI- 2 - Question 13

At 10% per annum simple interest, the interest earned over 3 years would be 30% of the capital. Thus, 300 is 30% of the capital which means that the capital is 1000. In 3 years, the compound interest on the same amount would be 331.

Test: SI & CI- 2 - Question 14

The population of Mangalore was 1283575 on 1 January 2001 and the growth rate of population was 10% in the last year and 5% in the years prior to it, the only exception being 1999 when because of a huge exodus there was a decline of 20% in population. What was the population on January 1, 1995?

Detailed Solution for Test: SI & CI- 2 - Question 14

Solve through options to see that the value of 1200000 fits the given situation.

Test: SI & CI- 2 - Question 15

Mohit Anand borrows a certain sum of money from the AMS Bank at 10% per annum at compound interest. The entire debt is discharged in full by Mohit Anand on payment of two equal amounts of Rs. 1000 each, one at the end of the first year and the other at the end of the second year. What is the approximate value of the amount borrowed by him?

Detailed Solution for Test: SI & CI- 2 - Question 15

P + 2 years interest on P = 1000 + 1 years interest on 1000 + 1000 -+ 1.21P = 2100 → P = 1736 (approx).

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