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3 February AffairsCloud - Class 9 MCQ


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30 Questions MCQ Test - 3 February AffairsCloud

3 February AffairsCloud for Class 9 2024 is part of Class 9 preparation. The 3 February AffairsCloud questions and answers have been prepared according to the Class 9 exam syllabus.The 3 February AffairsCloud MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 3 February AffairsCloud below.
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3 February AffairsCloud - Question 1

What is the area under the curve y = |x| + | x - 1| between x = 0 and x = 1 ?

3 February AffairsCloud - Question 2

The greatest term in the expansion of (3 + 2x)9, when x = 1, is

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3 February AffairsCloud - Question 3

The coordinates of the pole of the line lx+my+n=0 with respect to the circle x�+y�=1 are

3 February AffairsCloud - Question 4
If the line 2x - y + k = 0 is a diameter of the circle x� + y� + 6x -6y + 5 =0, then k is equal to
3 February AffairsCloud - Question 5
If z = i log(2 - √3), then cos z =
3 February AffairsCloud - Question 6
The differential equation of the family of lines passing through the origin is
Detailed Solution for 3 February AffairsCloud - Question 6
The equation of line passing through the origin is y = mx , when m is constant
Diffrence w.r.t x
dy dx = m
The Differential equation is
y = dy dx x
or x dy dx - y = 0
3 February AffairsCloud - Question 7
Which of the following is a solution of the differential equation ( dy dx )2 - x dy dx + y = 0
Detailed Solution for 3 February AffairsCloud - Question 7
( dy dx )2 - x . dy dx + y = 0
y = 2x - 4
dy dx = 2
So, ( dy dx )2 - x . dy dx + y
= (2)2 - x � 2 + 2x - y
= 4 - 2x + 2x - y
= 0
3 February AffairsCloud - Question 8
If y' = x-y/x+y, then its solution is
3 February AffairsCloud - Question 9
d d x { cos x } =
Detailed Solution for 3 February AffairsCloud - Question 9
d dx {cos x�} = d dx {cos 180 } = - sin 180 d dx { 180 } = - π 180 sin x�.
3 February AffairsCloud - Question 10
(d/dx)[tan⁻�((sinx+cosx)/(cosx-sinx))]
3 February AffairsCloud - Question 11
Value of 1 + log x + (log x)�/2! + (log x)�/3! + ..... ∞ is
3 February AffairsCloud - Question 12
The angle of elevation of a cloud from a point h mt above the surface of a lake is θ and the angle of depression of its reflection in the lake is φ . The height of the cloud is
3 February AffairsCloud - Question 13
The eccentricity of the conjugate hyperbola of the hyperbola x� - 3y� = 1 is
3 February AffairsCloud - Question 14
Which of the following functions is a solution of the differential equation (dy/dx)� - x (dy/dx) + y = 0?
3 February AffairsCloud - Question 15
The solution of the differential equation (dy/dx) = (y/x) + (φ (y/x)/φ' (y/x)) is
3 February AffairsCloud - Question 16
tan⁻�(1/4)+ tan⁻�(2/9) is equal to
3 February AffairsCloud - Question 17
f(x) = ||x| - 1| is not differentiable at
3 February AffairsCloud - Question 18
For every n ∈ N, 23n-7n-1 is divisible by
3 February AffairsCloud - Question 19
If A, B are two square matrices such that AB = A and BA = B, then
3 February AffairsCloud - Question 20
For a square matrix A, it is given that AA' = I, then A is a
3 February AffairsCloud - Question 21
The maximum value of xy subject to x+y=8 is
3 February AffairsCloud - Question 22
The real value of α for which the expression 1-i sin α/1+2 i sin α is purely real is
3 February AffairsCloud - Question 23
The angle between lines xy=0 is
3 February AffairsCloud - Question 24
The focus of the parabola (y-2)�=20(x+3) is
3 February AffairsCloud - Question 25
The equation of the normal to the curve x2 = 4y at (1, 2) is
3 February AffairsCloud - Question 26
Two finite sets have m and n elements, the total number of subsets of the first set is 56 more than the total number of subsets of the second. The value of m and n are respectively
Detailed Solution for 3 February AffairsCloud - Question 26
Let A denote the first set and B denote the second set
We have, n(A) = 2m and n(B) = 2n
As per the question, we have
n(A) = 56 + n(B)
⇒ n(A) - n(B) = 56
⇒ 2m - 2n = 56
⇒ 2n (2m - n - 1)
⇒ 2n (2m - n - 1) = 8 � 7
⇒ 2n = 8 = 23 or (2m - n - 1) = 7
⇒ n = 3 or 2m - n = 8 = 23 = 26 - 3
⇒ n = 3 or m - n = 3
⇒ n = 3 or m = 6
Hence, the required values of m and n are 6 and 3 respectively
3 February AffairsCloud - Question 27
In how many ways can the letters of the word ARRANGE be arranged so that R's are never together?
Detailed Solution for 3 February AffairsCloud - Question 27
Reqd. ways = 7! 2! 2! - 6! 2! = 1260 - 360 = 900
3 February AffairsCloud - Question 28
A and B are events such that P(A ∪ B) = 3/4, P(A ∩ B) = 1/4, P(A̅)= 2/3, then P(A̅ ∩ B) is
3 February AffairsCloud - Question 29
The probability that a number selected at random from the set of numbers {1,2,3,....,100} is a cube is
3 February AffairsCloud - Question 30
In a equilateral triangle r : R : r 1 is
Detailed Solution for 3 February AffairsCloud - Question 30
A = B = C = 60�
r : R : r1 = 4R sin (A/2) sin (B/2) sin (C/2) : R : 4R sin (A/2) cos (B/2) cos (C/2)
= 4 (1/2) (1/2) (1/2) : 1 : 4 (1/2) ( 3 /2) ( 3 /2) = (1/2) : 1 : (3/2) = 1 : 2 : 3
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