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APSC JE CE Paper 2 Mock Test - 10 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test APSC JE CE Mock Test Series 2024 - APSC JE CE Paper 2 Mock Test - 10

APSC JE CE Paper 2 Mock Test - 10 for Civil Engineering (CE) 2024 is part of APSC JE CE Mock Test Series 2024 preparation. The APSC JE CE Paper 2 Mock Test - 10 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The APSC JE CE Paper 2 Mock Test - 10 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for APSC JE CE Paper 2 Mock Test - 10 below.
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APSC JE CE Paper 2 Mock Test - 10 - Question 1

Aneroid Barometer is a device used for measuring

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 1
An aneroid barometer is an instrument used for measuring pressure as a method that does not involve liquid. Invented in 1844 by French scientist Lucien Vidi, the aneroid barometer uses a small, flexible metal box called an aneroid cell (capsule), which is made from an alloy of beryllium and copper.
APSC JE CE Paper 2 Mock Test - 10 - Question 2

IRC has specified the maximum value of stripping value of bitumen not be exceeded

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 2

Bitumen adheres well to all normal types of road aggregates provided they are dry and free from dust. In the absence of water, there is practically no adhesion problem of bituminous construction. Adhesion problem occurs when the aggregate is wet and cold. This problem can be dealt with by removing moisture from the aggregate by drying and increasing the mixing temperature. Further, the presence of water causes stripping of binder from the coated aggregates. These problems occur when the bitumen mixture is permeable to water. 

IRC has specified the maximum value of stripping value of aggregate not to exceed 5%.

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APSC JE CE Paper 2 Mock Test - 10 - Question 3

The degree of workability is medium when the value of slump in mm is:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 3
Low workability –25–50, medium workability–50–100, High workability–100–75
APSC JE CE Paper 2 Mock Test - 10 - Question 4

The rate of consolidation.

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 4
Factors affecting the rate of consolidation

(→) The rate of consolidation increases with the temperature.

( → ) Decrease with the increase of liquid limit

( → ) Changes with the increase in effective stress etc.

APSC JE CE Paper 2 Mock Test - 10 - Question 5

A plate load test is used to determine -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 5
( → ) is used to determine the ultimate bearing capacity of soil as well as the probable settlement of the for a given loading and a given depth.

(→) It is a field test, which is generally performed on uniform sandy soil.

APSC JE CE Paper 2 Mock Test - 10 - Question 6

The coefficient of passive earth pressure for cohesionless granular soil is represented by

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 6

APSC JE CE Paper 2 Mock Test - 10 - Question 7

The strength based the classification of a brick is made on the basis of following

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 7

IS : 3101 — Aluminium collapsible tubes.
IS : 3102 — Classification of burnt clay brick.
IS : 3495 — Method of test of burnt clay brick.
IS : 3496 — Specification for dobby lags and pegs.

APSC JE CE Paper 2 Mock Test - 10 - Question 8

A footing is resting on fully saturated clayey strata. For checking the initial stability, shear parameters are used from-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 8
Pore pressure is not released, So an unconsolidated undrained test is used to determine footing stability.
APSC JE CE Paper 2 Mock Test - 10 - Question 9

The bending equation is written as:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 9
Bending equation

(M/I=σb/Y=E/R)

Hence the option A is correct.

APSC JE CE Paper 2 Mock Test - 10 - Question 10

The % of elongation of the piece under tension indicates its:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 10
Ductility is a solid material’s ability to deform under tensile stress; this is often characterized by the material’s ability to be stretched into a wire.

Hence the option D is correct.

APSC JE CE Paper 2 Mock Test - 10 - Question 11

If a column is effectively held in position and restrained against rotation at one end and the other restrained against rotation but not held in the position, then the recommended value of effective length is-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 11
If a column is effectively placed in position and restrained against rotation at one end and restrained against rotation at the other but not held in position, the recommended value of effective length is 1.2 (l).

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 10 - Question 12

Force in the member EF is:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 12
If at a joint, 3 members meet and two of them are collinear, and there is no external load or reaction at that joint, then the 3rd member (collinear) will always carry zero force. Hence force in member EF is zero.

Hence the correct answer is option d.

APSC JE CE Paper 2 Mock Test - 10 - Question 13

The reduced bearing of a line is N87W. Its whole circle bearing is

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 13
It is in the 4th quadrant to convert it from RB to WCB = 360°-Bearing of line.

360°-87° = 273°.

Hence, the correct option is (b).

APSC JE CE Paper 2 Mock Test - 10 - Question 14

Efficiency of pile group is always:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 14

In the case of driven piles in loose- to medium-dense sand, the efficiency of a pile group may be even greater than 1 due to the densification of the sand between the piles during the driving operation. In this case, the efficiency of the pile group is equal to 1 or 100%.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 10 - Question 15

Oil in water affects fish by affecting

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 15
Fishes show mortality because the fish gills get laden with oil after the slimy mucus of gills is affected. Oil disrupts the insulating capacity of feathers.

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 10 - Question 16

Maximum shear stress produced on a solid circular shaft under torque is

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 16

Hence correct answer is option B.

APSC JE CE Paper 2 Mock Test - 10 - Question 17

The maximum deflection of the cross-sectiontip of a cantilever beam with concentrated load P at the free end is

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 17

The maximum deflection of the tip of the cantilever beam with concentrated load P at the free end is Pl3/3EI

Hence the correct answer is option A.

APSC JE CE Paper 2 Mock Test - 10 - Question 18

The delayed flow that reaches the river mainly as groundwater is known as-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 18
Base Flow The delayed flow that reaches a stream essentially as groundwater flow is called base flow.
APSC JE CE Paper 2 Mock Test - 10 - Question 19

In concrete Cylinder strength-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 19
Cylinder strength = 0.8 Cube strength
APSC JE CE Paper 2 Mock Test - 10 - Question 20

The symmetry of the stress tensor at a point in a body when at equilibrium is obtained from-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 20
At the same time, according to the principle of conservation of angular momentum, equilibrium requires that the summation of moments with respect to an arbitrary point is zero, which leads to the conclusion that the stress tensor is symmetric, thus having only six independent stress components, instead of the original.
APSC JE CE Paper 2 Mock Test - 10 - Question 21

The effective length of a fillet weld is taken as the actual length-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 21
The effective length of a fillet weld is taken as the actual length minus twice the size of the weld.

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 10 - Question 22

The pitot tube is used to measure –

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 22
The Pitot tube (named after Henri Pitot in 1732) measures a fluid velocity by converting the flow’s kinetic energy into potential energy. The conversion takes place at the stagnation point, located at the Pitot tube entrance.
APSC JE CE Paper 2 Mock Test - 10 - Question 23

Directions: In this question, the second figure of the problem figures bears a certain relationship to the first figure. Similarly, one of the figures in the answer figures bears the same relationship to the third problem figure. You have to select the figure from the set of answer figures which would replace the sign of the question mark (?).

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 23
Problem figure (2) is the mirror image of problem figure (1), but with inverse operations. Hence, to get the missing figure, the operations in problem figure (3) will become opposite, that is, '÷' will become '×' and vice versa.

APSC JE CE Paper 2 Mock Test - 10 - Question 24

Consolidation settlement occurs due to-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 24
Consolidation is the process of reduction in volume due to the expulsion of water under an increased load. It is a time-related process occurring in saturated soil by draining water from the void.

Hence, the correct option is (B).

APSC JE CE Paper 2 Mock Test - 10 - Question 25

The rigid frame shown in the figure is-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 25
(Ds = 3mre – 3J)

(=3×23 – 3 × 3 = 0)

Hence it is determinate and stable.

In general: If The structure is number of unknowns < number of equations Unstable number of unknowns = number of equations

Stable & Determinate number of unknowns > number of equations Indeterminate The procedure outlined above does not always work with regard to stability. An alternate method (the displaced shape method) of determining whether a structure is stable or unstable, and determinate or indeterminate is the following

  • If the displaced shape of the structure can be drawn so that no members deform, the structure is unstable.

  • If the displaced shape cannot be drawn without causing a member to deform, the structure is stable.

If removal of one constraint (a support force or a member force) causes the structure to be unstable (i.e. the structure can be displaced without deforming a member), then the original structure is stable and determinate. o If two or more constraints need to be removed to cause the structure to be unstable, the original structure is stable and indeterminate.

Hence, the correct option is (A)

APSC JE CE Paper 2 Mock Test - 10 - Question 26

Purlin are :

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 26
Purlins are beams which are provided over roof trusses to support the roof coverings. Purlins span between the top chords of two adjacent roof trusses.

Hence, the correct option is (A)

APSC JE CE Paper 2 Mock Test - 10 - Question 27

Permeability of soil is affected by

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 27
All of the above factors affect the permeability of the soil
  • If grain size increases the permeability of soil will increase

  • The permeability will increase if the void ratio increases

  • The structural arrangement of the soil particle will influence the void ratio and thus permeability

APSC JE CE Paper 2 Mock Test - 10 - Question 28

Among the following, which is/are not pre-treatment units?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 28
A pre-treatment is necessary in order to protect raw water lifting systems and pipelines against blockages as well as other treatment equipment against abrasion and, more generally, to remove anything that might interfere with subsequent treatment.
  • bar screening;

  • straining;

  • comminution;

  • grit removal

  • Flow equalization chamber

  • Proportion tank

  • Neutralization for pH adjustment tank

Nutrient removal tank is the secondary treatment process.

APSC JE CE Paper 2 Mock Test - 10 - Question 29

The lower water-cement ratio in concrete produces:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 29
The water-cement ratio is the ratio of the weight of water to the weight of cement used in a concrete mix.

A lower ratio leads to higher strength and durability but may make the mix difficult to work with and form.

The water-cement ratio is inversely proportional to the strength of concrete, lower water-cement ratio leads to an increase in bonds between the aggregates, cement, and sand.

As w/c increases quantity of cement in concrete reduces hence the availability of paste in concrete reduces. Poorer the paste higher the creep. therefore we can say that strength of concrete is inversely proportional to the creep.

APSC JE CE Paper 2 Mock Test - 10 - Question 30

Which of the following statements is true?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 10 - Question 30
Shear Stress on the principal plane is zero as shown in the figure. In the figure shown below X-axis represent the normal stress and Y-axis represents the shear stress. Since the horizontal X-axis also represents the maximum principal plane, therefore, shear stress (Y-value) will be zero on this plane.

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