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Civil Engineering (CE) Exam  >  Civil Engineering (CE) Tests  >  APSC JE CE Mock Test Series 2024  >  APSC JE CE Paper 2 Mock Test - 9 - Civil Engineering (CE) MCQ

APSC JE CE Paper 2 Mock Test - 9 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test APSC JE CE Mock Test Series 2024 - APSC JE CE Paper 2 Mock Test - 9

APSC JE CE Paper 2 Mock Test - 9 for Civil Engineering (CE) 2024 is part of APSC JE CE Mock Test Series 2024 preparation. The APSC JE CE Paper 2 Mock Test - 9 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The APSC JE CE Paper 2 Mock Test - 9 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for APSC JE CE Paper 2 Mock Test - 9 below.
Solutions of APSC JE CE Paper 2 Mock Test - 9 questions in English are available as part of our APSC JE CE Mock Test Series 2024 for Civil Engineering (CE) & APSC JE CE Paper 2 Mock Test - 9 solutions in Hindi for APSC JE CE Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free. Attempt APSC JE CE Paper 2 Mock Test - 9 | 100 questions in 120 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study APSC JE CE Mock Test Series 2024 for Civil Engineering (CE) Exam | Download free PDF with solutions
APSC JE CE Paper 2 Mock Test - 9 - Question 1
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A column is a compression member, the effective length of which exceeds

Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 1

As per IS 456 : : 2000, clause 25.1.1

Column or strut is a compression member, the effective length of which exceeds three times the least lateral dimension.

APSC JE CE Paper 2 Mock Test - 9 - Question 2
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For unstiffened webs of girders, the thickness of the web shall not be less than

Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 2
For unstiffened webs of girders, the thickness of the web shall not be less than D1/85.
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APSC JE CE Paper 2 Mock Test - 9 - Question 3
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Outer projection of a "Tread " is called

Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 3
The outer projection of a tread is known as nosing. An edge part of the tread protrudes over the riser beneath.
APSC JE CE Paper 2 Mock Test - 9 - Question 4
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Permissible compressive strength of M 200 concrete grade is -
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 4
Characteristic compressive strength of M200 grade cement is 200 kg/cm2.

Permissible compressive strength of M200 grade concrete is (200 ÷ 1.5) = 133.3 kg/cm2.

Design strength of M200 grade concrete is (133.3 ÷ 1.5) = 88.8 kg/cm2.

APSC JE CE Paper 2 Mock Test - 9 - Question 5
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The line normal to the plumb line is known as -
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 5
The line normal to the plumb line is known as the level line. A level line is a line parallel to the mean spherical surface of the earth or a line lying on a level surface.
APSC JE CE Paper 2 Mock Test - 9 - Question 6
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Crushing strength of good building stone should be more than -
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 6
Requirements of a Good Building Stone

A good building stone should possess several characteristics such as high strength (i.e., crushing strength >1000kg/cm2 ) (100 Mpa)), high durability, sufficient hardness (i.e., coefficient of hardness >14 ), high resistance of wear, good fire resistance specific gravity more than 2.7, crystalline structure, high impact value (i.e., toughness index >13 ), low water absorption (i.e., Percentage absorption after 24 hours less than 0.6 ), facility for carving and dressing, weather resistance and better appearance. Generally, stones from igneous and metamorphic rocks are heavier and more durable than stones from sedimentary rocks.

APSC JE CE Paper 2 Mock Test - 9 - Question 7
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In the following question, select the related letters/number from the given alternatives.
GREAT : 25 : : NUMBER : ?
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 7

Here, GREAT is a five character word ⇒ 5 × 5 = 25
Therefore, NUMBER is a six character word ⇒ 6 × 6 = 36
Hence answer is 36.

APSC JE CE Paper 2 Mock Test - 9 - Question 8
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The moment of inertia of a circular area of radius r with respect to diameter axis is
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 8

The moment of inertia of a circular area of radius r with respect to diameter axis is πr4 ÷ 4 where R is the radius of the circle.

APSC JE CE Paper 2 Mock Test - 9 - Question 9
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What will be the cant deficiency (cm), if maximum safe speed on a 5 Degree curve of a broad gauge track is 110 km/h and average speed of train is 85 km/h?
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 9

given, dergee = 5
max. safe speed (Vmax) = 110km/hr
average speed(Vavg) = 85km/hr
For brouad gauge,
G= 1750 mm

= 486-284=192=19
But, max cant deficiency allowed (as per old IS code) is 10 cm.

APSC JE CE Paper 2 Mock Test - 9 - Question 10
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The age of trees can be understood by
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 10

Each year, trees from new cells, arranged in concentric circles called annual growth rings which are used to understand its age.

APSC JE CE Paper 2 Mock Test - 9 - Question 11
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If a uniform bar is supported at one end in a vertical direction and loaded at the bottom end by a load equal to the weight of the bar, the strain by a load equal to the weight of the bar, the strain energy as compared to that due to self-weight will be-
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 11
Strain energy (U)(=½(WΔ))

Now, axil deformation due to load W is given by (Δ1=WL/AE)axial deformation due to self-weight W is given by (Δ2=WL/2AE)

(NowΔ1=2Δ2)(and U∞Δ)

Hence strain energy due to load W is given by (U1=(1/2)WΔ1)

(U1=2U2)

Hence strain energy as compared to that due to self-weight will be double.

Hence the option C is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 12
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Which of the following statements with reference to an isogonic line are correct in magnetic declination?

(1) It is drawn through the points of the same declination

(2) It does not form a complete great circle

(3) It radiates from the north and south magnetic regions and follows irregular paths
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 12
ISOGONIC lines are lines joining the point of the same magnetic declination; they radiate from poles & follow an irregular pattern.

Hence the option B is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 13
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The length of the straight portion of a bar beyond the end of the hook should be at least-
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 13

The length of the straight portion of a bar beyond the end of the hook curve should be at least four times the diameter.

Hence the option C is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 14
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The minimum grade of reinforced concrete in seawater per IS 456: 2000 is-
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 14
Concrete in Sea-water

Concrete in sea-water of exposed directly along the sea-coast shall be at least M20 grade in the case of plain concrete and M30 in case of reinforced concrete. The use of slag or pozzolana cement is advantageous under such conditions.

Hence the option C is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 15
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Column may be made of plan concrete if their unsupported length does not exceed their least, lateral diameter by-
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 15

Column may be made of plain concrete if their unsupported length does not exceed their least lateral diameter by the slab.

Hence the option C is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 16
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Effective length of the fillet weld of length L and size S is given by -
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 16
Effective length of the fillet weld of length L and size S is given by L – 2s.

Hence, the correct option is (b).

APSC JE CE Paper 2 Mock Test - 9 - Question 17
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IS code for designing pile foundation is :
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 17
Following are the Indian Standard Codes on Pile Foundations: IS 2911: Part 1: Sec 1: 1979 Driven cast-in-situ concrete piles. IS 2911: Part 1: Sec 2: 1979 Bored cast-in-situ piles. IS 2911: Part 1: Sec 3: 1979 Driven precast concrete pile.

Hence the correct answer is option A.

APSC JE CE Paper 2 Mock Test - 9 - Question 18
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The ozonation in drinking water helps to remove
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 18
Because of its excellent disinfection and oxidation qualities, ozone is widely used for drinking water treatment. Ozone can be added at several points throughout the treatment system, such as during pre-oxidation, intermediate oxidation, or final disinfection. Usually, it is recommended to use ozone for pre-oxidation before a sand filter or an active carbon filter (GAC). After ozonization, these filters can remove the remaining organic matter (important for final disinfection).

Hence the correct answer is option D.

APSC JE CE Paper 2 Mock Test - 9 - Question 19
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The modulus of elasticity of steel is more than that of concrete. It indicates that steel is
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 19
The modulus of elasticity of steel is about 200 GPa or 29,000,000 psi, and the modulus of elasticity of concrete is around 30 GPa or 4,350,000 psi. The modulus of elasticity of aluminum is 69 GPa or 10,000,000 psi.

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 9 - Question 20
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Low workability of concrete conforms to a slump of

Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 20
Low workability of concrete conforms to a slump of 25-75 mm.

Hence the correct answer is option A.

APSC JE CE Paper 2 Mock Test - 9 - Question 21
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A flat slab is supported on
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 21
Flat slab is a reinforced concrete slab supported directly by concrete columns without beams. A flat slab is defined as a one-sided or two-sided support system with a sheer load of the slab being concentrated on the supporting columns and a square slab called drop panels.

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 9 - Question 22
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For an isotropic, homogeneous, and elastic material obeying Hooke's law, the number of independent elastic load (W) on a cantilever-
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 22
For an isotropic, homogeneous, and elastic material obeying Hooke's law,2 number of independent elastic loads (W) on a cantilever.
APSC JE CE Paper 2 Mock Test - 9 - Question 23
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The enlarged head of the supporting column of a flat slab is called-
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 23
Drop panels are rectangular, just supported above the Capital. Capital is the enlarged shape to support the drop panel.
APSC JE CE Paper 2 Mock Test - 9 - Question 24
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According to IS : 800-1962 the permissible bending stress in steel slab plates is-
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 24
Maximum permissible bending stress in Column is 0.75fy .

so that 0.75 × 250 = 1875 ~1890 Kg/cm2.

APSC JE CE Paper 2 Mock Test - 9 - Question 25
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The distribution system in water supplies is designed on the basis of:
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 25
The distribution system in water supplies is designed based on the gravitational pull, such as the purified water in the gravity system flow wholly under gravity.
APSC JE CE Paper 2 Mock Test - 9 - Question 26
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With storage, the strength of cement:
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 26

  • Due to the hygroscopic nature of cement, it easily absorbs moisture from the atmosphere

  • This moisture or dampness is the main hazard for cement which makes it hard like stone and it converts it to a useless material not suitable for construction.

  • Storage of cement requires more care as strength of cement decreases with time

  • Storage of cement should be done in such a manner that it is not exposed to the atmosphere which can be done by packing in airtight bags.

Hence, the correct option is (B)

APSC JE CE Paper 2 Mock Test - 9 - Question 27
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Direct shear test can be conducted for :
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 27
1. Unconsolidated Undrained Test (UU)

Drainage is not permitted throughout the test. In the case of direct shear test drainage is not permitted during the application of both normal stress and shear stress. In the case of triaxial compression test drainage is not permitted during the application of both cell pressure and deviator stress. Since the test is conducted fast allowing no time for either consolidation of sample initially or dissipation of pore pressure in later stage, the test is also called quick test.

2. Consolidated Undrained Test (CU)

In this type of shear test the soil specimen is allowed to consolidate fully under initially applied stress and then sheared quickly without allowing dissipation of pore pressure. In the case of direct shear test the specimen is allowed to consolidate fully under applied normal stress and then sheared at high rate of strain to prevent dissipation of pore pressure during shearing. In the case of triaxial compression test the specimen is allowed to consolidate fully under the applied cell pressure and then the pore water outlet is closed and the specimen is subjected to increasing deviator stress at higher rate of strain.

3. Consolidated Drained Test (CD)

In this type of shear test drainage is allowed throughout the test. The specimen is allowed to consolidate fully under the applied initial stress and then sheared at low rate of strain giving sufficient time for the pore water to drain out at all stages. The test may continue for several hours to several days.

Hence, the correct option is (D)

APSC JE CE Paper 2 Mock Test - 9 - Question 28
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Which one of the following is not a classification of stones?
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 28
The classifications of stones are physical (based on structure), chemical (based on chemical composition), practical (based on usage), and geological (based on the mode of origin). Mineralogical classification is not a means of classifying stones in general. It’s called chemical classification.

Hence, the correct option is (B).

APSC JE CE Paper 2 Mock Test - 9 - Question 29
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If W is the load in a circular slab of radius R, the maximum radial moment at the center of the slab is
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 29

Radial moment at the centre of the Circular slab is

Where MR = Radial moment

R = radius of slab

μ = Poisson’s ratio

r = any section at a distance r from centre of the slab

W = load on circular slab

For the maximum radial moment at centre

r = 0 and μ = 0

Therefore,

APSC JE CE Paper 2 Mock Test - 9 - Question 30
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Which of the following statement is wrong?
Detailed Solution for APSC JE CE Paper 2 Mock Test - 9 - Question 30
Support settlement does not cause any stress in a statically determinate structure.
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