Alcohol, Phenols And Ethers - Class 12 MCQ

neopentyl alcohol is a 1⁰ alcohol, so it gives red colour in Victor meyer’s test 

After protonation, 2⁰ carbocation is formed, followed by CH^-₃  shift, so, 3⁰ halide is obtained as final product

It is an example of electrophilic substitution, so, -R substituent decreases nucleophilic nature.

Alcohols act as nucleophiles during esterification, so reactivity decreases with increase in branching.

Acidic charcter of phenol is favoured by -R group

NO₂ is -R group while -CH₃ is +I group, so, NO₂ decreases charge density on oxygen in order to facilitate release of     H⁺ ion

Boiling point increases with increases in molecular mass & decreases with branching

Acid halides & ester react with Grignard reagent to give 3⁰ alcohols.

LiAℓH₄ initiates reaction by donating H^-ion. Nucleophilic group attacks on less alkylated carbon.

SeO₂ is a regioselective oxidising agent, it gives allyl alcohol on reaction with alkenes.

All acid derivatives on hydrolysis give carboxylic acid, so, A can be
(CH₃)₂CHCOZ, Grigrand reagent reacts
with carbonyl group of acid derivative give 3⁰ alcohol

Compound (a) and (b) contain active methylene group so, they will not give haloform reaction.

As the stability of cation increases, rate of reaction increases.

As the stability of cation increases, rate of dehydration increases.

A : Syn addition of hydroxy groups

B : CrO₃ - Jones reagent oxidises 2⁰ alcohol to ketone & it does not affect 3⁰ alcohol
 

Solution of Na₂CO₃ is basic, so, it ionises phenol but can not ionise alcohol

NaBH₄ can reduce aldehyde and ketone to alcohols but can not reduce ester

In case of ketone it give R & S form but in case of ester it reduces ∝-C of chiral carbon, so, configuration of chiral carbon remains unaffected.

On reaction with Cu, 1⁰ & 2⁰ alcohols are oxidised by using ∝-H  while 3⁰ alcohols give alkenes by using β-H compound (b) does not possess both of them.