BITSAT Chemistry Test - 10 - JEE MCQ

We know that,
From Freundlich's adsorption isotherm, we have

Where k is the amount of adsorbent and p is the amount of adsorbate, P is the pressure; c and n are the constant.
On comparing the options given, only option (B) satisfies the relation mentioned above.
Hence, this is the correct relation.
 

The elements having atomic number more than that of Uranium (92) are collectively termed as transuranic elements. Hence, this is the correct option.

-NH₂ is an electron donating and an ortho and para-directing group. It increases the charge localisation on ortho and para positions due to resonance of lone pairs with the benzene ring.
-CHO, -COR and -CN are electron withdrawing and meta directing groups due to the resonance of the pi electrons with the benzene ring.
Therefore, it is a correct option.

The Gattermann Koch Synthesis is,

All the above statements are true except statement III. This reaction is electrophilic substitution instead of nucleophilic substitution and HOC⁺ ion is used as electrophile. Hence, this is the correct answer.

We know that, Bosch process is the process for making water and graphite by reacting CO2 with H2 in the presence of Fe catalyst.
CO₂(g) + 2H₂(g) → C(s) + 2H₂O(g)
Therefore, CO₂ gas is removed during the Bosch process.
Hence, this is the correct option.

The correct configuration should be
Th₉₀ is [Rn]₈₆ 5f²6d⁰7s²
All the other configurations are correct.
Hence, this is the correct answer.

Benzene in the presence of chlorine and Fe, undergoes electrophilic substitution reaction and produces chlorobenzene.
Benzene in the presence of sulphuric acid, undergoes electrophilic substitution reaction and produces benzenesulphonic acid.

Therefore, it is a correct option.

CO₂, BeCl₂, I₃-, IF₂- : All have linear geometry

In, lone pair of nitrogen is taking part in aromaticity.
In, nitrogen is attached to electron withdrawing group.
In, lone pair of nitrogen is in resonance with benzene ring.

Nitrogen oxides and hydrocarbons (unburnt fuel) are primary pollutant that leads to photochemical smog.

Classical or London-type smog is formed by the combination of soot particles with oxides of sulphur while the climate is cool and humid.
Due to the presence of soot and oxides of sulphur, it is reducing in nature.
Photochemical smog or Los Angeles smog is obtained from nitrogen oxides when the climate is warm, dry and sunny. Due to the presence of O₃ and NO₂
 (strong oxidising agents), it is oxidising in nature.CO does not play any role in the formation of photochemical smog.

Particulate matter or pollutants are minute solid particles or liquid droplets in the air. Example: smoke and dust particles, ash, mists, etc.
In contrast, shedding of leaves is not due to minute solid particles. It is a natural process. 

Marble acts as sink to sulphuric acid, sulphur dioxide after coming in touch with water forms sulphuric acid. Which in turn effects the marble of Taj Mahal.

CO₂ shows the maximum extent of global warming because it traps the heat of the sun and results in heating the atmosphere.
Also, the molecules of carbon dioxide are transparent to sunlight, but not to heat radiation, hence, show mechanism like the natural greenhouse effect. 

A water supply with a BOD level of 3-5 ppm is considered moderately clean. In water with a BOD level of 6-9 ppm, the water is considered somewhat polluted because there is usually organic matter present and bacteria are decomposing this waste. Hence, Both A and B are not suitable for drinking. B with a higher value of BOD level is more polluted.

In automobiles, petrol, diesel and natural gas are generally used as fuels. These fuels on burning, provide energy to run automobiles.
Petrol, diesel and natural gases are some examples of fossil fuels. Fossil fuels are hydrocarbon containing substances formed by the decomposition of biological material.
Fossil fuels when burnt, generally release oxides of carbon, hydrogen, sulphur and nitrogen.
CO₂, NO, NO₂, SO₂ and CO are the common gaseous pollutants released by the burning of fossil fuels, which are released from automobile exhaust.
CO is formed due to incomplete combustion of carbon and it is harmful for humans, as it blocks the delivery of oxygen to organs and tissues as it combines with haemoglobin.
Oxides of nitrogen are harmful as it causes irritation in the lungs and it also decreases the rate of photosynthesis.

During thunderstorm, there is formation of NO that changes to NO₂ and ultimately to HNO₃ (acid rain).

Acid rain consist of acids like H₂SO₃ and HNO₃ thus pH is lower than 7.

Smog is classified into two types, classical smog and photochemical smog.
Classical smog is a mixture containing smoke, fog and sulphur dioxide.
It is a reducing mixture. Hence, it is known as reducing smog. It occurs in a cool, humid climate.

Rh(Z=42)=4d⁸ 5s¹
Oxidation states=+2 to +8

The atomic numbers of Zn, Fe, Ni, Cu are  30, 26, 28, 29 respectively.
Electronic configurations of their ions:

Number of unpaired d- electrons in Zn⁺, Fe²⁺, Ni⁺, Cu⁺ are 0, 4, 1, 0 respectively.
So, Fe²⁺ has the highest unpaired d - electrons.

According to given Electronic configuration, total number of electrons = 23
(Here [Ar]=1s² 2s² 2p⁶ 3s² 3p⁶
Fe⁺³ has total number of electrons as 23.
 Electronic configuration of 
After releasing three electrons.

Commercially potassium permanganate is prepared by the alkaline oxidative fusion of MnO₂  followed by disproportionation of MNO^2-₄ formed in the first step.

In neutral or faintly alkaline medium KMnO₄ Converts iodide to iodate.

26Fe =[Ar]3d⁵ 4s² Fe²⁺= [Ar] 3d⁶
Number of unpaired electrons, n =4

So, the approximate nearest value will be "5".

Wave length of orbit electron can be calculated as follows
2πr_n=nλ
Wave length of e− e - =3.33×n A∘ =3.33×3×10⁻⁸cm
=10⁻⁷cm=10⁻⁹m

The proof of quantization of energy states in an atom is obtained by the experiment performed by Franck and Hertz with the help of accelerated electron passing through mercury vapour. At certain accelerating voltage of electron, sudden drop in current occur due to observation energy of colliding electron with mercury atom to send it to exited state.
Since, it happens only at some certain voltage, this gives the proof of quantization of energy states.

₂₆Fe²⁺⇒18[Ar] 3d⁶ ; 6 d-electrons
₁₇Cl⇒1s² 2s² 2p⁶ 3s² 3p⁵ ; 11 p-electrons
Mg=1s²2s²2p⁶3s² ; 6 s-electrons
p-electrons in Fe= ₁₈Ar3d⁶=6
p-electrons in Ne=1s²2s²2p⁶=6

This species is aromatic because the compound is cyclic and the number of π electrons is 2, which is in accordance with the Huckel's rule, (4n + 2) π.
Taking n = 0, according to this rule, number of π electrons is 4 x 0 + 2 = 2.

In Clemmensen reduction, reagent Zn-Hg/conc. HCI is used.

This method is used to convert carbonyl compound into alkane.