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# BITSAT Physics Test - 1

## 40 Questions MCQ Test BITSAT Subject Wise & Full Length Mock Tests | BITSAT Physics Test - 1

Description
This mock test of BITSAT Physics Test - 1 for JEE helps you for every JEE entrance exam. This contains 40 Multiple Choice Questions for JEE BITSAT Physics Test - 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this BITSAT Physics Test - 1 quiz give you a good mix of easy questions and tough questions. JEE students definitely take this BITSAT Physics Test - 1 exercise for a better result in the exam. You can find other BITSAT Physics Test - 1 extra questions, long questions & short questions for JEE on EduRev as well by searching above.
QUESTION: 1

Solution:
QUESTION: 2

### The mass number of a nucleus is

Solution:

A = N + Z, where A is mass number and Z is atomic number and N is number of neutrons
So A > Z except for H-atom in which A = Z as N = 0

QUESTION: 3

### The radius of the first orbit of the hydrogen atom is a₀. The radius of the second orbit will be

Solution:
QUESTION: 4

Which one of the following is not correct statement?

Solution:
QUESTION: 5

Cathode rays are similar to visible light rays in that

Solution:
QUESTION: 6

The energy of a photon of wavelength (λ) is

Solution:
QUESTION: 7

By increasing the temperature, the specific resistance of a conductor and a semiconductor

Solution:
QUESTION: 8

The power factor of a series LCR circuit when at resonance is

Solution:

At resonance, power factor cos � = 1

QUESTION: 9

Minimum no. of 8 μF and 250 V capacitors, used to make a combination of 16 μF and 1000 V, is

Solution:
QUESTION: 10

A fireman of mass 60 kg slides down a pole. He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5, with what acceleration will the fireman slide down (g=10m/s�)

Solution:
QUESTION: 11

Orbit of a planet around a star is

Solution:
QUESTION: 12

A body takes T minutes to cool from 62 degree C to 61 degree C when the surrounding temperature is 30 degree C. The time taken by the body to cool from 46 degree C to 45.5 degree C is

Solution:

According to Newton's law of cooling, - dθ dt = k(θ - θ0)
or - dθ θ − θ 0 = kdt
− ∫ θ 1 θ 2 dθ θ − θ 0 = k ∫ 0 t dt
− |log e θ − θ 0 | θ 1 θ 2 = kt
or loge1 - θ0) - loge2 - θ0) = kt
or loge θ 1 − θ 0 θ 2 − θ 0 = kt
In the first case,
kt = loge 62 - 30 61 - 30 or kt = loge 32 31 .....(1)
In the second case,
kt' = loge 46 - 30 45.5 - 30
or kt' = loge 16 15.5 or kt' = loge 160 155
or kt' = loge 32 31 .....(2)
It follows from (1) and (2) that t = t'

QUESTION: 13

An ideal gas is heated from 27°C to 627°C at constant pressure. If initial volume was 4 m3, then the final volume of the gas will be

Solution:

Given: Initial temperature (T1) : 27°C = 300 K Final temperature (T2) = 621°C = 900 K

Initial volume (V1) = 4 m3. QUESTION: 14

The monoenergetic beams of electrons moving along + y direction enters a region of uniform electric and magnetic fields. If the beam goes straight through, then these simultaneously fields B̅ and E̅ are directed respectively

Solution:
QUESTION: 15

If a substance is to be paramagnetic, its atoms must have a

Solution:
QUESTION: 16

Horizontal tube of non-uniform cross-section has radii of 0.1m and 0.05m respectively at M and N. For a streamline flow of liquid the rate of liquid flow is

Solution: Equation of continuity A1V1=A2V2 from Bernoulli theorem both have height same so the equation became po+1/2 eV1^2=po+1/2eV2^2.
QUESTION: 17

The viscous drag on a spherical body moving with a speed ν in a viscous medium is directly proportional to

Solution:

Solution :- The viscous drag on a spherical body is given as F=6πηRV.

It is directly proportional to V. Here η is the coefficient of viscosity, R is the radius of the sphere and V is its velocity.

QUESTION: 18

The ratio of tangential stress to the shearing strain is called

Solution:
QUESTION: 19

A particle of charge -q and mass m moves in a circle of radius r around an infinitely long line charge of linear charge density + λ . Then time period will be:(Where )

Solution:
QUESTION: 20

The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s�. The distance covered by the body in the 5th second of its motion is

Solution:
QUESTION: 21

A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite point

Solution:
QUESTION: 22

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-k/r2), the total energy is

Solution:
QUESTION: 23

A body of mass 2 kg has an initial velocity of 3 metres per second along OE and it is subjected to a force of 4 N in a direction perpendicular to OE. The distance of the body from O after 4 seconds will be

Solution:
QUESTION: 24

An astronomical telescope has objective and eye-piece lens of powers 0.5 D and 20 D respectively. Its magnifying power will be

Solution:
QUESTION: 25

A simple pendulum executing simple harmonic motion is falling freely along with the support. Then

Solution:
QUESTION: 26

In the absence of damping, the amplitude of forced oscillation at resonance is

Solution:
QUESTION: 27

The moment of inertia of a cylinder of radius R, length l and mass M about an axis passing through its centre of mass and normal to its length, is

Solution:
QUESTION: 28

Two bodies of different masses of 2 kg and 4 kg are moving with velocities 2 m/s and 10 m/s towards each other due to mutual gravitational attraction. What is velocity of their centre of mass ?

Solution:  QUESTION: 29

The radius of curvature of a thin plno-convex lens is 10 cm (of curved surface) and the refractive index is 1.5. If the plane surface is silvered, then the focal length will be

Solution:
QUESTION: 30

A force of acts on O, the origin of the coordinate system. The torque about the point (1, -1) is Solution:

Torque = r x F

r = î - j

so torque = (i - j) x -Fk

= -F(-j - i)

= F( i + j)

QUESTION: 31

A bulb rated at (100W-200V) is used on a 100V line. The current in the bulb is

Solution:

We know that P = V2 / R
Thus as P = 100W and V = 200V we get R = 40000/100 = 400Ω
Now as we know V = IR
We get I = V / R
= 100 / 400
= ¼ A

QUESTION: 32

A monoatomic gas is suddenly compressed to 1/8 of its volume adiabatically. The pressure of the gas now to that of its original pressure is

Solution:
QUESTION: 33

5 mole of hydrogen gas is heated from 30oC to 60oC at constant pressure. Heat given to the gas is (given R = 2 cal/mole degree)

Solution:
QUESTION: 34

Unit of moment of inertia in MKS system

Solution:
QUESTION: 35

Wave optics is based on wave theory of light put forward by Huygen and modified later by

Solution:
QUESTION: 36

Huygen's wave theory allows us to know

Solution:
QUESTION: 37

If the equation of SHM is y = a sin (4 π t + φ) how much is its frequency?

Solution:
QUESTION: 38

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 90o. Then the velocity of wave will be

Solution:
QUESTION: 39

A solid disc of mass M is just held in air horizontally by throwing 40 stones per sec vertically upwards to strike the disc each with a velocity of 6 ms⁻1. If the mass of each stone os 0.05 kg what is the mass of the disc. (g = 10 ms⁻2)

Solution:
QUESTION: 40

A particle of mass m moving with velocity ν collides with a stationary particle of mass 2 m and sticks to it. The speed of the system, after collision, will be

Solution: