Bihar PGT/TGT/PRT Exam  >  Bihar PGT/TGT/PRT Tests  >  Bihar PGT Exam Mock Test Series 2024  >  Bihar PGT Physics Mock Test - 5 - Bihar PGT/TGT/PRT MCQ

Bihar PGT Physics Mock Test - 5 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar PGT Exam Mock Test Series 2024 - Bihar PGT Physics Mock Test - 5

Bihar PGT Physics Mock Test - 5 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT Exam Mock Test Series 2024 preparation. The Bihar PGT Physics Mock Test - 5 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Physics Mock Test - 5 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Physics Mock Test - 5 below.
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Bihar PGT Physics Mock Test - 5 - Question 1

In the following question, out of the four alternatives, select the alternative which is the best substitute for the phrase.In the following question, out of the four alternatives, select the alternative which is the best substitute for the phrase.

Q. A man who is courteous and gallant in his behavior.

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 1

'Chivalry' is the quality in a man of being highly courteous in his presentation. None of the other options means the same as that of the given phrase.
A preacher is a religious teacher, a savior is a person who protects people in times of need and a knight is a great warrior.
Example-Chivalrous men are difficult to be found in today's world.

Bihar PGT Physics Mock Test - 5 - Question 2

In the following question, a sentence has been given in Active/Passive voice. Out of four alternatives suggested, select the one which best expresses the same sentence in Passive/Active voice.

Q. When he left school, the textbooks were put aside by him and were never reopened.

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 2

The given sentence is in passive voice and the correct conversion to active voice is given in option 3. Rest of the options fail to convey the exact meaning of the given sentence. 

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Bihar PGT Physics Mock Test - 5 - Question 3

"युद्धभूमि" शब्द में कौन-सा समास है?

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 3

समास - दो या दो से अधिक शब्दों से मिलकर जो नया और छोटा शब्द बनता है उस शब्द को हिन्दी में समास कहते हैं।

युद्धभूमि शब्द का समास विग्रह - युद्ध के लिए भूमि (सम्प्रदान तत्पुरुष समास)

तत्पुरुष समास - वह समास है जिसमें बाद का अथवा उत्तर पद प्रधान होता है तथा दोनों पदों के बीच का कारक-चिह्न लुप्त हो जाता है। वह समास है जिसमें बाद का अथवा उत्तर पद प्रधान होता है तथा दोनों पदों के बीच का कारक-चिह्न लुप्त हो जाता है। 

विभक्तियों के नामों के अनुसार तत्पुरुष समास के छः भेद हैं-

कर्म तत्पुरुष - को 

करण तत्पुरुष - से और के द्वारा 

सम्प्रदान तत्पुरुष - के लिए और को 

अपादान तत्पुरुष - से 

सम्बन्ध तत्पुरुष - का, के, की

अधिकरण तत्पुरुष - में पर और पर

अत: विकल्प (B) सही है I

Bihar PGT Physics Mock Test - 5 - Question 4

निम्न में से "यण संधि" का उदाहरण नहीं है-

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 4

नाविक शब्द में अयादि संधि है, अन्य विकल्पों में यण संधि है। 

संधि - संधि (सम् + धि) शब्द का अर्थ है 'मेल' या जोड़। दो निकटवर्ती वर्णों के परस्पर मेल से जो विकार (परिवर्तन) होता है वह संधि कहलाता है। 

नाविक = नौ + इक (अयादि संधि) 

नियम - औ + इ = आव् + इ 

अयादि संधि - ए, ऐ और ओ औ से परे किसी भी स्वर के होने पर क्रमशः अय् आय्, अव् और आव् हो जाता है। इसे अयादि संधि कहते हैं। 

अन्य विकल्प -

स्वागत = सु + आगत (उ +आ = व् +आ)

अन्वेषण =अनु + एषण (उ व् ए)

देव्यागमन = देवी + आगमन ( ई + आ = य् + आ) यण संधि - इ, ई के आगे कोई विजातीय (असमान) स्वर होने पर इ, ई को 'य्' हो जाता है। उ, ऊ के आगे किसी विजातीय स्वर के आने पर उ, ऊ को 'व्' हो जाता है। 'ऋ' के आगे किसी विजातीय स्वर के आने पर ऋ को 'र्' हो जाता है। इन्हें यण-संधि कहते हैं।

अत: विकल्प (C) सही है I

Bihar PGT Physics Mock Test - 5 - Question 5

माला फेरत जुग भया, फिरा न मन का फेर कर का मनका डारि दे, मन का मनका फेर। उपर्युक्त पंक्ति में कौन सा अलंकार है?

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 5

यहां "मन का" शब्द की एक से अधिक बार आवृति हो रही है।

1. मन का - हमारे मन के बारे में बता रहा है 

2. मन का - माला के दाने का बोध हो रहा है। 

यमक अलंकार - जब शब्द की एक से ज़्यादा बार आवृति होती है एवं विभिन्न अर्थ निकलते हैं तो वहाँ यमक अलंकार होता है।

अत: विकल्प (B) सही है I

Bihar PGT Physics Mock Test - 5 - Question 6
_______ gave a slogan 'Freedom is our birth right and we must have it'.
Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 6

The correct answer is Bal Gangadhar Tilak.

Key Points

  • Bal Gangadhar Tilak gave a slogan 'Freedom is our birthright and we must have it.
  • Lokmanya Bal Gangadhar Tilak roused the Indian people and injected fresh life into our liberation cause with his electrifying phrase, "Swaraj is my birth-right and I shall have it."
  • Lokmanya Tilak was born in 1856, barely one year before the First War of Indian Independence, into a disappointed and sullen India, and following the defeat of the 1857 insurrection, into a swirl of sorrow and hopelessness.

Important Points

  • Bal Gangadhar Tilak worked valiantly to aid the country's independence from British domination.
  • Bal Gangadhar Tilak, a member of the Lal-Bal-Pal troika, was dubbed the "Father of Indian Unrest" by British colonial rulers.
  • Lokmanya Tilak founded and published two newspapers: the Marathi Kesari and the English The Mahratta. To criticize the colonial overlords, he used his pen as a weapon.
Bihar PGT Physics Mock Test - 5 - Question 7

Select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 7

The logic follows here is:

In a figure:

Middle number = (Top number × bottom number) - (left number × right number) 

In fig 1:

Middle number = (9 × 10) - (7 × 8)

= 90 - 56

= 34

In fig 2:

Middle number = (12 × 8) - (8 × 7)

= 96 - 56

= 40

Similarly,

In fig 3:

Middle number = (11 × 7) - (4 × 9) 

? = 77 - 36

? = 41

Hence, the correct answer is "41".

Bihar PGT Physics Mock Test - 5 - Question 8
Buddha attained enlightenment at
Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 8

The correct answer is Bodh Gaya.

Key Points

  • Buddha attained enlightenment at Bodh Gaya in Bihar.
  • He attained enlightenment under a peepal tree at Bodh Gaya where he meditated for days.
  • After attaining enlightenment, he came to be known as Buddha or the wise one.
  • Buddha was a Kshatriya and belonged to Sakya gana.

 Thus, we can say that Buddha attained enlightenment at Bodh Gaya.

Additional Information

  • He taught for the first time at Sarnath and passed away at Kusinara.
Bihar PGT Physics Mock Test - 5 - Question 9
Article 19 of the Indian Constitution includes which of the following right?
Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 9

The correct answer is the Right to freedom of speech and expression.

  • Article 19 of the Indian Constitution includes the Right to freedom of speech and expression.

Key Points

  • Article 19 deals with the six Fundamental Rights. They are:
    • Right to freedom of speech and expression.
    • Right to assemble peacefully and without arms.
    • Right to form association or unions or co-operatives.
    • Right to move freely throughout the territory of India.
    • Right to reside and settle in any part of the territory of India.
    • Right to practice any profession or to carry on any occupation, trade or business.
  • Fundamental Rights:
    • The Fundamental Rights have been described in Articles 12-35, Part III of the Indian Constitution.
    • The Right to Property (Article 31) was deleted from the list of Fundamental Rights.
      • By the 44th Amendment Act, 1978, it is made a normal constitutional right under Act 300A in Part XII of the Constitution

Additional Information

  • Right to Constitutional Remedies is enumerated in Articles 32-35.
  • Right against exploitation is enumerated in Articles 23 and 24.
  • The right to freedom of Religion is enumerated in Articles 25-28.
  • Fundamental Rights that are available to citizens only and not to foreigners: Article 15,16, 19, 29 and 30.
Bihar PGT Physics Mock Test - 5 - Question 10
Which of the following is formed from the combination of algae and fungi?
Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 10

The correct answer is Lichens.

Key Points

  • Lichens, are formed from the combination of algae and Fungi.
  • In this symbiotic relation- algae helps in the food and nutrient availability, and fungi in turn provides shelter to algae.
Bihar PGT Physics Mock Test - 5 - Question 11

In a certain code language, 1259 means 'box in the ring', 6941 means 'the square boxing ring' and 5713 means 'put the box out'. Find the code for 'ring'.

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 11

1) 6941 ⇒ the square boxing ring

2) 5713 ⇒ put the box out

In 1) and 2) one number is common i. e. ‘1’ and one word is common i. e. ‘the’.

Hence, in code language, 1 = the

3) 1259 ⇒ box in the ring

In 1) and 3) two number are common i. e. 1 and 9, and also two words are common i. e. ‘the’ and ‘ring’.

But we know 1 is the code number for ‘the’, implies 9 is the code number for ‘ring’.

Code for 1 is the.

Code for 5 is box.

Code for 9 is ring.

Hence, "9" is the correct answer.

Bihar PGT Physics Mock Test - 5 - Question 12

If a man is standing at a point C, how far and in which direction is point F w.r.t point C?

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 12

According to the information given in the question, we can draw the following diagram.

BC = 24 m
FC = ED = 12 m
FC = 12 m
Thus point F is in the west w.r.t to point C and 12 m from point C.
Hence, the correct answer is "12 m west".

Bihar PGT Physics Mock Test - 5 - Question 13

Farsighted or hypermetropic eye can be corrected by

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 13

Hypermetropia is corrected using converging lens.  In this defect the person is able to see far objects clearly but difficulty with near vision. The image is focused behind the retina rather than upon it. This occurs when eyeball is too short or the power of lens is too weak. By using a convex lens the defect is corrected.

Bihar PGT Physics Mock Test - 5 - Question 14

Sinusoidal peak potential is 200 volt with frequency 50Hz. It is represented by the equation

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 14

Given peak potential is 200v
so, amplitude is 200
and frequency is 50Hz
so angular frequency is 2.πx50 = 314/sec
so the value is
E = 200sin(314t)
Hence option B is the correct answer.

Bihar PGT Physics Mock Test - 5 - Question 15

The dimensions of angular momentum are

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 15

We know that angular momentum,
L = r x P
Thus its dimension is [r][P] = ML2T-1.

Bihar PGT Physics Mock Test - 5 - Question 16

Which of the following physical quantity has different dimension than others?

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 16

Dimension of work and energy are the same i.e. [ML²T⁻²].
 Power = Energy/Time,
 Energy = Power × Time (in terms of hour instead of second),
 Energy = Watt × Hour,
= [ML²T⁻³] [T],
= [ML²T⁻²].
But, Momentum(p) = Mass × Velocity,
 p = [M] [LT⁻¹],
 p = [MLT⁻¹].
Hence the Dimension of work, energy and watt-hour is the same i.e. [ML²T⁻²] but the dimension of momentum is different ([MLT⁻¹]).

Bihar PGT Physics Mock Test - 5 - Question 17

The work done in increasing the volume of a soap bubble of radius r to 27 times will be, if the surface tension of soap solution is T  

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 17

Bihar PGT Physics Mock Test - 5 - Question 18

Which of the following is not the unit of time

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 18

Parallactic second is the unit of distance because parallactic second is an abbreviation of parsec. Parsec = Parsec is the Unit for larger distances.It is the distance at which a star would make parallax of one Second of arc.

Bihar PGT Physics Mock Test - 5 - Question 19

In the diffraction of a single slit experiment, if the slit width is half then the width of the central maxima will be:

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 19

Fringe width is inversely proportional to the distance between slits so it will be doubled.

Bihar PGT Physics Mock Test - 5 - Question 20

When the distance between two charged particle is halved, the force between them becomes

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 20

Earlier force between two particles is 
F=kq1​q2​​/ r2
When distance is halved force becomes 
F′= kq1​q2/(r/2)2 ​​=4kq1​q2/r2​​=4F

Bihar PGT Physics Mock Test - 5 - Question 21

A compass needle free to turn in a horizontal plane is placed at the centre of circular coil of 30 turns and radius 12 cm. The coil is in a vertical plane making an angle of 450 with the magnetic meridian. When the current in the coil is 0.35 A, the needle points west to east. Determine the horizontal component of the earth’s magnetic field at the location

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 21

The needle will point along W-E if the result of the earth’s magnetic field and magnetic field due to the coil have a resultant in the W-E direction. This happens if B cos 45o=Earth's field
⟹ (μ0​nI​/2r) cos45o=(4π×10−7×30×0.35​)/(2×0.12) ×(1/√2)​​=0.39G=Earth's magnetic field.

Bihar PGT Physics Mock Test - 5 - Question 22

The force between two charges is 120 N. If the distance between the charges is doubled, the force will be

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 22

Coulombs law states the force between two charged particles is directly proportional to the product of charges and inversely proportional to the square of distance between them.
So if the distance is doubled then the force would decrease 4 times.
So the new force would be 120/4=30 Newton.

Bihar PGT Physics Mock Test - 5 - Question 23

Arrange the following in the increasing order of magnetic susceptibility.

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 23

Diamagnetic materials have a small and negative value of magnetic susceptibility. Paramagnetic materials have a small and positive value of magnetic susceptibility and ferromagnetic materials have a large and positive value of magnetic susceptibility.

Bihar PGT Physics Mock Test - 5 - Question 24

Identify the expression for horizontal component from the following.

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 24

Horizontal component is a component of Earth’s magnetic field along the horizontal direction in the magnetic meridian. It is denoted by BH. If B is the intensity of Earth’s total magnetic field, then the horizontal component of Earth’s magnetic field is given by:
BH=Bcosδ

*Multiple options can be correct
Bihar PGT Physics Mock Test - 5 - Question 25

In the circuit shown E, F, G and H are cells of e.m.f. 2V, 1V, 3V and 1V respectively and their internal resistances are 2W, 1W, 3W and 1W respectively.

                 

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 25

Bihar PGT Physics Mock Test - 5 - Question 26

When a satellite moves around the earth in a certain orbit, the quantity which remains constant is

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 26

Bihar PGT Physics Mock Test - 5 - Question 27

A rod of length L fixed at the origin at one end is placed along the x-axis at t = 0. It starts rotating about the z-axis in the x-y plane anti-clockwise as seen from the positive z-axis. The angular displacement is given by θ = 2t2. The angular acceleration of the rod is

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 27

Kinematic equations of rotational motion about a fixed axis,

where ω is the instantaneous angular velocity, α is the instantaneous angular acceleration, θ is the angular displacement, and t is time.

EXPLANATION:

Given: Length of the rod = L, and angular displacement θ = 2t2

  • Using the first equation,

  • Using the second equation, 


Therefore option 4 is correct.

Bihar PGT Physics Mock Test - 5 - Question 28

Light is confined within the core of a simple optical fiber by:

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 28

Light remains confined within the core of simple optical fibre because of Total internal reflection from core cladding boundary.
Light is confined within the core of a simple optical fiber by. If light hits a boundary of a material of lower refractive index at a steep enough angle, it cannot get out and it's reflected back into the high index medium, as in the figure below.
An optical fibre is a thin rod of high-quality glass. Very little light is absorbed by the glass.Optical fibres can carry more information than an ordinary cable of the same thickness. The signals in optical fibres do not weaken as much over long distances as the signals in ordinary cables.
Total internal reflection. When light traveling in an optically dense medium hits a boundary at a steep angle (larger than the critical angle for the boundary), the light is completely reflected. This effect is used in optical fibers to confine light in the core.
The light in a fiber-optic cable travels through the core (hallway) by constantly bouncing from the cladding (mirror-lined walls), a principle called total internal reflection. Because the cladding does not absorb any light from the core, the light wave can travel great distances.
 

Bihar PGT Physics Mock Test - 5 - Question 29

In a young’s double slit experiment, the central bright fringe can be identified by

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 29

When we use white light, the central bright will have light from all wavelengths as none of them cancel out. Hence the central bright fringe appears white.
For other bright fringes, depending on the wavelength of light constructive interference will not take place for certain wavelengths. Hence they will not be white, rather will be coloured, hence differentiated from central fringe.

Bihar PGT Physics Mock Test - 5 - Question 30

A long metal bar of 30 cm length is aligned along a north south line and moves eastward at a speed of 10 ms-1. A uniform magnetic field of 4.0 T points vertically downwards. If the south end of the bar has a potential of 0V, the induced potential at the north end of the bar is

Detailed Solution for Bihar PGT Physics Mock Test - 5 - Question 30

Induced emf =Blv=12V. It is induced in the northward direction by right hand rule (emf=)
therefore if the south end of the pole has potential of 0V, the north end will have a potential of 12V.

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