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Bihar PGT Physics Mock Test - 6 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar PGT Exam Mock Test Series 2024 - Bihar PGT Physics Mock Test - 6

Bihar PGT Physics Mock Test - 6 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT Exam Mock Test Series 2024 preparation. The Bihar PGT Physics Mock Test - 6 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Physics Mock Test - 6 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Physics Mock Test - 6 below.
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Bihar PGT Physics Mock Test - 6 - Question 1

The question below consists of a set of labelled sentences. Out of the four options given, select the most logical order of the sentences to form a coherent paragraph.

P: In February 2010 the medical council of India announced a major change in the regulation governing the establishment of medical colleges.
Q: The new regulation also carried the following warning: "permission shall be withdrawn if the colleges resort to commercialization". 
R: With this change, corporate entities were permitted to open medical colleges.
S: Since the regulation does not elaborate on what constitutes "resorting to commercialization", this will probably be a matter left to the discretion of the government. 

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 1

The passage seems to be about a regulation passed by the government regarding medical colleges. The first sentence of the passage is Psince it introduces the fact that a regulation was passed.

The second sentence would be R, which tells us about the content of the regulation.

The third sentence should be Q. Q also gives us information about the content of the regulation but it contains the word 'also', which makes it obvious that it will come after R.

The last sentence is S, which tells us what is not mentioned in the regulation. Therefore, the correct sequence is PRQS.

Bihar PGT Physics Mock Test - 6 - Question 2

In the following question, a sentence has been given in Active/Passive Voice. Out of the four alternatives suggested, select the one which best expresses the same sentence in Passive/Active Voice.

I have seen him.

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 2

Rule- The object in the active voice becomes the subject in the passive voice and the subject in the active voice becomes the object in the passive voice.This is valid in both ways (Active to passive and vice-versa). Further, the verb is changed to the past participle form

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Bihar PGT Physics Mock Test - 6 - Question 3

कालिदास का खण्डकाव्य कौन सा है?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 3

कालिदास संस्कृत भाषा के महान कवि ओर नाटककार थे। उन्होंने भारत की पौराणिक कथाओं को आधार बनाकर रचनाएं की, जिसमें भारतीय जीवन और दर्शन के विविध रूप और मूल तत्त्व निरूपित हैं। कालिदास अपनी इन्हीं विशेषताओं के कारण राष्ट्र की समग्र राष्ट्रीय चेतना को स्वर देने वाले कवि माने जाते हैं संसृत साहित्य में ही नहीं अपितु समग्र साहित्यिक संसार में उन्हें कविकुलश्रेष्ठ तथा कविशिरोमणि माना जाता है।

प्रस्तुत विकल्पों में से 'मेघदूतम्' यह कालिदास का खण्डकाव्य है।

Bihar PGT Physics Mock Test - 6 - Question 4

बघेली बोली किस क्षेत्र में बोली जाती है?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 4

बघेली बोली जबलपुर में बोली जाती है। बघेली या बाघेली बोली, हिन्दी की एक बोली है जो भारत के बघेलखण्ड क्षेत्र में बोली जाती है। बघेले राजपूतों के आधार पर रीवा तथा आसपास का क्षेत्र बघेलखंड कहलाता है और वहाँ की बोली को बघेलखंडी या बघेली कहलाती हैं। इसके अन्य नाम मन्नाडी, रिवाई, गंगाई, मंडल, केवोत, केवाती बोली, केवानी और नागपुरी हैं। 

Bihar PGT Physics Mock Test - 6 - Question 5

कुजगह फोड़ा और ससुर वैद्य - कहावत का अर्थ है:

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 5

कुजगह फोड़ा और ससुर वैद्य - कहावत का अर्थ है: धर्म संकट की स्थिति। 

वाक्य प्रयोग - एक ओर मेरा सारा काम पड़ा है, दूसरी ओर मुझे जल्दी निकलना है।

Bihar PGT Physics Mock Test - 6 - Question 6

नीचे दिए गए प्रश्न में एक शब्द के चार विलोम शब्द दिए गए हैं। सही विलोम शब्द का चयन कीजिए।

आदि

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 6

आदि का अर्थ है: आरंभ, शुरू। और इसका विलोम शब्द अंत है।

Bihar PGT Physics Mock Test - 6 - Question 7

How does Archaebacteria differ from the other Bacteria 

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 7

Bacteria are the sole members of the Kingdom Monera. They are the most abundant micro-organisms.
On the basis of origin, bacteria can be divided into two types - Archaebacteria & Eubacteria

Archaebacteria:

  • These bacteria are special since they live in some of the harshest habitats such as extreme salty areas (halophiles), hot springs (thermoacidophiles) and marshy areas (methanogens).
  • Archaebacteria differ from other bacteria in having a different cell wall structure and this feature is responsible for their survival in extreme conditions.
  • For example - Methanogens are present in the gut of several ruminant animals such as cows and buffaloes and they are responsible for the production of methane (biogas) from the dung of these animals.

Additional Information

Eubacteria:

  • There are thousands of different eubacteria or ‘true bacteria’.
  • They are characterised by the presence of a rigid cell wall, and if motile, a flagellum.
  • The Eubacteria can be both autotrophic & heterotrophic.
Bihar PGT Physics Mock Test - 6 - Question 8

The splitting of white light into its component colours is called:

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 8

The correct answer is Dispersion.

Key Points

  • When a beam of white light is made to fall on one refracting face of the prism, it splits into seven colours i.e. violet, indigo, blue, green, yellow, orange and red (VIBGYOR) from the base.
  • The phenomenon of the splitting of white light into its constituent colours is called dispersion of light.
  • The pattern of colour components of light is called the spectrum of light.
  • The red light bends the least, while the violet light bends the most
  • The rainbow is an example of the dispersion of sunlight by the water drops in the atmosphere. 

Bihar PGT Physics Mock Test - 6 - Question 9

Which of the following is NOT an example of a biomass energy source?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 9

The correct answer is Atomic Energy.

Key Points

  • A biomass energy source is one that is derived from organic matter.
  • The source of atomic energy is radioactive metals which are of non-organic nature and thus cannot be classified as a biomass energy source.
Bihar PGT Physics Mock Test - 6 - Question 10
What is the full form of ITCZ?
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 10

The full form of ITCZ is The Intertropical Convergence Zone.

  • It is the area encircling Earth near the Equator, where there is a convergence of the northeast and southeast trade winds takes place.
  • The ITCZ was originally identified from the 1920s to the 1940s as the "Intertropical Front" but after the recognition in the 1940s and 1950s of the significance of wind field convergence in tropical weather production.
Bihar PGT Physics Mock Test - 6 - Question 11
Fullerene is an allotrope of __________.
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 11

The correct answer is carbon.

Key Points

  • A fullerene is an allotrope of carbon whose molecule consists of carbon atoms connected by single and double bonds so as to form a closed or partially closed mesh, with fused rings of five to seven atoms.
    • The molecule may be a hollow sphere, ellipsoid, tube, or many other shapes and sizes.
  • Various allotropes of carbon are diamond, graphite, lonsdaleite, fullerene, C-540, C-70, amorphous carbon, carbon nanotube.
  • Diamond and crystalline silicon are isomorphous because they both have a three-dimensional tetrahedral structure.
  • Allotropy, the existence of a chemical element in two or more forms, which may differ in the arrangement of atoms in crystalline solids or in the occurrence of molecules that contain different numbers of atoms.

Additional Information

  • When an element exists in more than one crystalline form, those forms are called allotropes; the two most common allotropes of carbon are diamond and graphite.
    • One of the allotropic form of a carbon is a fullerene in which “carbon atoms” are “arranged in a sphere”.
    • Each sphere has 60 carbon atoms and each carbon atom is linked by a single covalent.
    • The fullerene is considered as purest allotrope of “carbon” because they have “smooth structure” without having dangling bonds.
Bihar PGT Physics Mock Test - 6 - Question 12
When is National Youth Day celebrated in India?
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 12

The correct answer is 12 January.

  • On 12 January, National Youth Day is celebrated in India.

Key Points

  • National Youth Day is celebrated on 12 January and is also known as Rashtriya Yuva Diwas.
    • The day is observed to commemorate the birth anniversary of Swami Vivekananda, one of the greatest philosophers and spiritual leaders.
    • In 1984, the Indian Government first declared to celebrate the birthday of Swami Vivekananda i.e. 12 January as National Youth Day. Since then the day has been celebrated as National Youth Day all over the country.
    • The main aim of the Government is to make a better future for the country by motivating the youths through the way of their life and ideas of the Swami Vivekananda.

Additional Information

  • Swami Vivekananda was born on 12 January 1863 was an Indian Hindu monk. He was a chief disciple of the 19th-century Indian mystic Ramakrishna
    • When Swami Ji became a monk from Narendra, his name was Swami Vividishanand, but before moving to Chicago, he changed his name to Vivekananda.
    • Swami Vivekananda books are:
      • Karma Yoga (1896).
      • Raj Yoga (1896).
      • Vedanta Shastra (1896).
      • Speeches from Colombo to Almora (1897).
Bihar PGT Physics Mock Test - 6 - Question 13

A is father of C and D is son of B. E is brother of A. If C is sister of D, then how is B related to E?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 13

The family chart is as follows:

i) A is father of C and D is son of B.

ii) E is brother of A.

iii) If C is sister of D

Drawing the family tree as per the given information:

Thus we can see B is the wife of A.

E is the brother of A.

Thus we can conclude B is the sister-in-law of E.

Hence, the correct answer is "Sister-in-law".

Bihar PGT Physics Mock Test - 6 - Question 14

A convex mirror has a focal length f. A real object, placed at a distance f in front of it from the pole, produces an image at

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 14

Here F=f
U=-f(-because it is present in front of a convex lens)
It is given that both focal length and object distance is f .
So according to lens formula 1/F=1/v+1/u
So 1/f=(1/v)+(-1/f)
=>1/f=(1/v)-(1/f)
So (1/f)+(1/f)=1/f
=>1+(1/f)=(1/v)
=>2/f=1/v
So from here we can say that v= f/2
Hence option B is correct.
 

*Multiple options can be correct
Bihar PGT Physics Mock Test - 6 - Question 15

A block of mass m slides down a plane inclined at an angle q. Which of the following will NOT increase the energy lost by the block due to friction ?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 15

Bihar PGT Physics Mock Test - 6 - Question 16

Which of the following statements about bar magnets is correct ?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 16

Explanation:As magnetic monopole does not exist. If we split the bar magnet into two pieces  each part will have its own north and south pole.

Bihar PGT Physics Mock Test - 6 - Question 17

Magnetic flux φ in Weber in closed circuit of resistance 15 ohm varies with time t sec as φ = 2t² – 3t + 1. The magnitude of induced emf at t = 0.25 sec is 

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 17


= 4t-3
At t = 0.25s
e= 2V

*Multiple options can be correct
Bihar PGT Physics Mock Test - 6 - Question 18

A conducting rod PQ of length L = 1.0 m is moving with a uniform speed v = 20 m/s in a uniform magnetic field B = 4.0 T directed into the paper. A capacitor of capacity C = 10 mF is connected as shown in figure. Then

            

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 18

According to Fleming’s right-hand rule induced current flows from Q to P.
Hence P is at higher potential and Q is at lower potential. 
Therefore, A is positively charged and B is negatively charged.
Hence:
qA​=+800μC and qb​=−800μC

Bihar PGT Physics Mock Test - 6 - Question 19

A resistance of 5 ohm and an inductance of 50 mH are connected in series with an a. c. I = 100 sin (100 t). What is the phase difference between the instantaneous current and voltage?​

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 19

Cosφ=R/Z=R/√R2/ ω2L2=5/√(25+(50)2x (0.1)2)
=5/√(25+25)=1/√2
⇒φ=π/4

Bihar PGT Physics Mock Test - 6 - Question 20

Which of the given statements are correct for a conservative force field

(p) The total mechanical energy is conserved.
(q) The work done around a closed path is zero.
(r) Gain in kinetic energy = Loss in potential energy.

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 20

CONCEPT:

  • Conservative force: A force is conservative if the work done by the force in displacing an object from one point to another point is independent of the path followed by the object and depends only on the endpoints.
  • Electrostatic forces, gravitational forces, elastic forces, magnetic forces, etc and are examples of conservative forces.
  • Non-conservative forces: A force is said to be non-conservative if work done by or against the force in moving a body from one position to another, depends on the path followed between these two positions.
  • Examples:  Frictional force, Viscous force, Airdrag, etc.

EXPLANATION:

  • Suppose a particle starts at A and a force Fext is acting on it. The particle is moved around the loop using the same force, Fext
  • Suppose the particle eventually ends up at A itself then the entire displacement of the particle is zero which means the total work done is zero.
  • A total work of one zero means there is no expenditure of energy which means the total energy is conserved. Hence statement p is correct
  • The total displacement of a particle in a closed loop is zero, which means the total work done is zero. Hence statement q is correct.
  • The total mechanical energy of a system is given by 

⇒ Total energy = Potential Energy + Kinetic energy

  • From the statement p, it is clear that if the total work done is zero it means the energy is conserved.
  • Which means Gain in kinetic energy = Loss in Potential Energy. Hence option r is correct.
Bihar PGT Physics Mock Test - 6 - Question 21

The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 21

The result of an addition or subtraction in the number having different precisions should be reported to the same number of decimal places as present in the number having the least number of decimal places.

The final result should, therefore, be rounded off to one decimal place, i.e. 663.8

Bihar PGT Physics Mock Test - 6 - Question 22

The north pole of a magnet is brought near a coil. The induced current in the coil as seen by an observer on the side of magnet will be

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 22

The direction of the current will be anticlockwise.
 
According to Lenz's law, the current in the coil will be induced in the direction that'll oppose the external magnetic field .
As the flux due to the external magnet is increasing ( as the N-pole is brought close ) , the coil will have to induce current in the anticlockwise direction to oppose this increase in flux and not in clockwise direction as that'll end up supporting the external flux.

Bihar PGT Physics Mock Test - 6 - Question 23

Given that v is the speed, r is radius and g is acceleration due to gravity. Which of the following is dimension less

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 23

v2r/g= (L1T-1)2L1/LT-2=L2
v2/rg= (LT-1)2 L1(L1 T-2) ​=M0L0T0
v2g/r​=(LT-1)2 LT-2/L​=L2T-4
v2rg=(LT-1)2(L1) (LT-1) =L4T-3
So, option D is correct.

Bihar PGT Physics Mock Test - 6 - Question 24

RMS value of ac i = i1 cos wt + i2 sin wt will be

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 24

I=(I1)cosωt+(I2)sinωt
(I2)mean=I12cos2ωt+I22sin2ωt+I1I2cosωtsinωt
I12×(1/2)×i22×(1/2)+2I1I2×0
Irms=√(i2)mean=√(I12+I22/2)=(1/√2)( I12+I22)1/2

Bihar PGT Physics Mock Test - 6 - Question 25

Zener diodes are used as

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 25

Zener Diodes can be used to produce a stabilised voltage output with low ripple under varying load current conditions. By passing a small current through the diode from a voltage source, via a suitable current limiting resistor (RS), the zener diode will conduct sufficient current to maintain a voltage drop of Vout.

Bihar PGT Physics Mock Test - 6 - Question 26

If we have two coherent sources S1andS2 vibrating in phase, then for an arbitrary point P constructive interference is observed whenever the path difference is

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 26

Constructive interference occurs when the path differences (S1​P−S2​P) is an integral multiple of λ or (S1​P−S2​P)=nλ
Where n=0,1 ,2 3,….

Bihar PGT Physics Mock Test - 6 - Question 27

The diagram shows the electric field lines in a region of space containing two small charged spheres, Y and Z then which statement is true?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 27

A small negatively charged body placed at X would be pushed to the right

 

The negative charge feels a force opposite to the direction of field.

 Other cases are not possible from properties of electric lines of force.

Bihar PGT Physics Mock Test - 6 - Question 28

As per the given figure, two blocks each of mass 250 g are connected to a spring of spring constant 2 Nm-1. If both are given velocity v in opposite directions, then maximum elongation of the spring is:

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 28


Using energy conservation,

Bihar PGT Physics Mock Test - 6 - Question 29

An observer looks at a tree of height 15 metre with a telescope of magnifying power 10. To him, the tree appears

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 29

Magnification of a telescope is given by:
M= θio​ ​​
10= (h/di)/(h/do​) ​​
10= do​​/di​
Distance of image, di​=do​​/10

Bihar PGT Physics Mock Test - 6 - Question 30

Motion of hole is a convenient way of describing

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 30

Explanation:The holes are just the abscence of a electron in a energy band. But its easier to describe the abscence of a electron as a single moving positive charge than it is to describe the motion of all the other electrons in the band.In a band you have N electrons. Remove one of those electrons(by for instance p-doping) and you have N-1 electrons left. Now you can either choose to describe this with the behavior of those N-1 electrons. Or you can choose to describe it as if there is one single hole moving around in the band.So mathematicly the holes behave just like a positivly charged electron.

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