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Bihar STET Paper 2 Chemistry Mock Test - 6 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar STET Mock Test Series 2024 - Bihar STET Paper 2 Chemistry Mock Test - 6

Bihar STET Paper 2 Chemistry Mock Test - 6 for Bihar PGT/TGT/PRT 2024 is part of Bihar STET Mock Test Series 2024 preparation. The Bihar STET Paper 2 Chemistry Mock Test - 6 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 2 Chemistry Mock Test - 6 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 2 Chemistry Mock Test - 6 below.
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Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 1

Direction (Q. Nos. 11-14) This section contains  a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

Passage I

Solid ammonium chloride is in equilibrium with ammonia and hydrogen chloride gases

0.980 g of solid NH4CI is taken in a closed vessel of 1 L capacity and heated to 275° C.

Q. Partial pressure of NH3(g) or HCI (g) at equilibrium is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 1

The reaction is as follow:-
NH4Cl(s)  ⇋  NH3(g) + HCl(g)
Kp = (pNH3)(pHCl)
1×10-2 = p2   (SInce reactant dissociates into same ratio, so the partial pressure will be same for both)
100×10-4 = p2
Or p = 10×10-2 = 0.10
So,  the partial pressure of NH3 and HCl are 0.10 atm.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 2

The correct order of thermal stability of the hydrides of group 16 elements is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 2



Thermal stability ∝ bond dissociation energy 
(where, E = group 16 elements)
On moving down the group, bond dissociation energy decreases due to increase in bond length. Thus, the order of bond dissociation energy or thermal stability is 
H2O > H2S > H2Se > H2Te > H2PO

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Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 3

As you move from left to right across the periodic table:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 3

Even though each atom has more electrons as you move from left to right across the periodic table, the atomic radius decreases. The reason is that you're also adding more protons, which exert a stronger attractive force on the electrons, drawing them in a tiny bit closer. Ionic radius also decreases, although not for the exact same reason.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 4

Which among the following is an example of pseudo first order reaction?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 4

In acid catalysed hydrolysis of ethylacetate the water is in excess so it is pseudo 1st order reaction.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 5

For the reaction system: 2NO(g) + O2(g) → 2NO2(g) volume is suddenly reduced to half its value by increasing the pressure on it. If the reaction is of first order with respect to O2 and second order with repect to NO, the rate of reaction will – 

  [AIEEE-2003]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 5

The correct answer is option A
rate=k[NO]2[O2]
As, C = n/V
On making the volume half, concentration doubles and rate of reaction becomes eight times.
 

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 6

Given, 

Q. Thus, ΔfH° of (C6H6) (l) is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 6

C6H6(l) + 15/2O2(g) → 6CO2(g) + 3H2O(l)
∆Hr = (∆Hc)C6H6 ⇒-3261  = ∑Hproduct - ∑Hreactant = 6(-393.5) -3(-283.83) - ∆fHC6H6
∆Hf = 48 kJ mol-1

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 7

Thermal decomposition of a compound is of first order. If 50% of a sample of a compound is decomposed in 120 min, the time taken for 90% completion is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 7

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 8

[Ti (H2O)6]3+ absorbs green and yellow region part of visible light. Then the transmitted colour of the compound is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 8

We know that white light is composed of many different colours. When white light is allowed to fall on [Ti(H2O)6]3+ ion, this ion absorbs the light of green and yellow colour and transmits is almost purple colour.The purple colour of the transmitted light is called complimentary colour of that of absorbed light.

*Multiple options can be correct
Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 9

In the electrolysis of aqueous sodium chloride solution, two types of reactions can take place at anode :

I. 2Cl- (aq) → Cl2(g) +2e-

II. 2H2O(l)g → O2 (g) + 4H+(aq) + 4e-

Select the correct statement(s) about these.

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 9

 

(c) Experrnent indicates that the applied voltage required is always greater than the voltage calculated from the standard E0ox or E0red. The additional voltage required is called overvoltage. Due to this, Cl2 and not O2 s formed. This, (c) 6 correct. 

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 10

Among the following the element with highest first ionization energy is:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 10

Carbon has the highest first ionisation energy because ionisation energy decreases down the group and increases from left to right in a period.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 11

Which of the following equation depicts reducing nature of H2O2?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 11

I2 gets reduce to I while  H2Oget oxidize to O2

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 12

Noble gases are inert and do not form compounds like other elements because of their:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 12

The correct answer is Option C. 

Noble gases have completely filled the outer shell/valence shell. Due to this reason they are very stable and do not react with other elements. Hence noble gases are called inert gases means they do not react with other elements to form chemical compounds.
 

*Multiple options can be correct
Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 13

One or More than One Options Correct Type
This section contains 3 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q.

Following solutions have been provided at temperature T K.
I. 1M aqueous glucose solution.
II. 1M aqueous sodium chloride solution.
III. 1M aqueous ammonium phosphate solution.
IV. 1M benzoic acid in benzene.
Select correct statements for the above solutions.

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 13

In benzene, benzoic acid forms dimer by intermolecular H-bonding.

Thus, osmotic pressure

Thus, solutions are not isotonic, (a) is incorrect.
III has maximum osmotic pressure, thus hypertonic of l, II and IV, (b) is correct.
IV has minimum osmotic pressure, thus hypotonic of I, II and III. Thus, (c) is correct.
II is hypotonic of III but hypertonic of I and IV, thus (d) Is correct.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 14

Number of atoms is 560 g of Fe (atomic mass = 56 g mol-1)

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 14

Fe atom= 560/56 =10 mole
= 10 x NA atom
option(A) = 5 mol
5 x NA 
option (B) = 20/1 = 20
20 x NA

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 15

How many atoms of hydrogen are in 67.2 L of H2 at STP?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 15

Standard temperature and pressure (STP) is defined as 0 degrees Celsius and 1 atmosphere of pressure. At STP, 1 mole of any gas occupies 22.4 liters.
First, calculate the number of moles of hydrogen gas (H2) in 67.2 liters:
67.2 L / 22.4 L/mole = 3 moles of H2
Each molecule of H2 contains 2 atoms of hydrogen. Therefore, 3 moles of H2 contains:
3 moles * (6.022 x 10^23 molecules/mole) * 2 atoms/molecule = 3.6132 x 10^24 atoms of hydrogen.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 16

The minimum number of C atoms required for a hydrocarbon to exhibit optical isomerism:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 16

The minimum number of C atoms required for a hydrocarbon to exhibit optical isomerism = 7

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 17

A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 K. The vapour pressure of propyl alcohol is 200 mm. If the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be -  

[AIEEE 2007]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 17

The correct answer is Option A.

Total pressure =290 mm
Vapour pressure of propyl alcohol =200 mm
Mole fraction of ethyl alcohol = 0.6
Mol fraction of propyl alcohol =1− 0.6 = 0.4
 
PT = P0A × χA + P0B × (1−χA)
290 = 200 × 0.4 + PoB × 0.6
0.6 × P0B = 290 − 80
P0B = 350 mm

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 18

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is

[JEE Main 2013]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 18

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 19

The complex [Co(NH3)6[Cr(C2O4)3] and [Cr(NH3)6[Co(C2O4)3] exhibit

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 19

Coordination isomerism is possible when both positive and negative ions of a salt are complex ions and two isomers differ in distribution of ligands in the cation and the anion.

*Answer can only contain numeric values
Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 20

Direction:

This section contains 5 questions. When worked out will result in an integer from 0 to 9 {both inclusive).

Q.

Relative decrease in vapour pressure of an aqueous NaCI solution is 0.167. Thus, number of moles of NaCI present in 180 g of H20 is ... .


Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 20

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 21

 For an aqueous solution, freezing point is _0.186ºC . Boiling point of the same solution is

(Kƒ = 1.86º K mol-1 kg) and Kb = 0.512º K mol-1 kg)

[AIEEE-2002]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 21

ΔTb/Kb = ΔTf/Kf
0.186/18.6 = ΔTb/0.512
ΔTb = 0.1x0.512
= 0.0512.
Boiling point = boiling point (of water) + ΔTb
=> 100 + 0.0512
= 100.0512

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 22

Which one of the following aqueous solutions will exhibit highest boiling point ?  

[AIEEE-2004]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 22

The correct answer is Option A.
Greater the number of solute particles in the solution, higher the elevation in boiling point. Among the given alternatives, Na2SO4 will exhibit the highest boiling point since it will dissociate into 3 ions when dissolved in the solution.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 23

In which of the following compounds the carbon marked with asterisk is expected to have greatest positive charge?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 23

In CH3 - CH- Cl, the carbon marked with asterisk has the greatest positive charge due to high electronegativity of Cl.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 24

What is/are the advantages of Play-way method of teaching in a classroom?

I. Learning becomes natural, joyful and energizing experience

II. It provides scope to the children to fulfil their physical, emotional and cognitive needs

III. It helps to build healthy student-teacher and student-student relationships

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 24

All children love to play. Play is a natural instinct of children. It is the natural expression of their needs. It develops the physical, cognitive, social, and emotional growth of a child. Friederich Froebel, the pioneer in childhood education, was of the view that the education of young children should be based on play. He believed that creative play had to be designed so that it could be transformed into creative work.

Advantages of the Play-way method of teaching in a classroom are as follows:

  • Playing games is a natural instinct with young children. They not only participate in the games spontaneously, but they can also organize the game effectively.
  • Children can create a new game; they devise the rules for playing the game and observe strictly the self-created discipline.
  • This helps to nurture the creative skills of children along with the development of several life skills like problem-solving, leadership, rational thinking, self-expression, communication skills, cooperative learning, group living, etc.
  • Learning becomes a natural, joyful, and energizing experience. As play is a natural activity, instinctive and joyful, children do not feel learning as a burden and stressful but participate in it voluntarily.
  • It provides sufficient scope to the children to fulfil their physical, emotional, and cognitive needs.
    • Physical development and acquisition of motor skills depend upon the maturation of the parts of the body and the opportunities available to the child to practice these skills. Play provides the child with opportunities to practice.
    • Play situations provide opportunities to handle and examine objects and explore the surroundings which help children to find answers to the questions in their minds and to understand the reason why things happen the way they do. By allowing children to play as they like, will help them in learning.
    • Play allows children to discover and learn for themselves. To discover means to find out about things and events for oneself
  • It helps to build healthy student-teacher and student-student relationships
  • In a play-way method, learning takes place through activities and learners remain active, not passive.

From the above, it is clear that all the statements mentioned in the question regarding the advantages of the play-way method are true.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 25
In which method, the teacher is active and the child is inactive?
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 25

Major objective of nursing education is to help students learn better and retain maximum. Teaching essentially helps students to acquire knowledge and understanding, develop skills, attitudes, values and appreciation leading to change in behavior. The methods of teaching commonly in use can be grouped as teaching methods at the classroom setting.

Key PointsStory telling Method:

  • Listening and telling stories helps children in learning language in primary classes.
  • Listening to stories is of interest to children and also enhances their creativity.
  • This helps the children in developing their ability to express themselves.
  • In story telling method the teacher is active and the child is inactive.
  • While telling story teacher express their thought in active way and students listen story in inactive way.
  • In the story telling we keep incorporating our life experiences in them.

Hence, we can conclude that in story telling method the teacher is active and the child is inactive.

Additional Information

  • Observation method: Observation method is one of the most important and authentic method used for data collection. The observer uses his sensory organs and observes the behavior / attitude of the people or a group.
  • Question answer method: Question answer method is an instrument of data collection. The researchers most commonly use this method for collecting data.
Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 26
A good teacher is one who –
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 26

Teachers are the most important resources in educational settings. They are the key figures for any changes required in the educational field.

A good teacher is one who teaches in an interesting manner so that children enjoy learning because when a teacher makes learning interesting and enjoyable, it helps learners in the:

  • participating willingly and happily.
  • retaining information for a longer period.
  • assimilating concepts easily and effectively.
  • nurturing their curiosity in the learning process.
  • enhancing skills and understanding of the concept.

Hence, it could be concluded that a good teacher is one who teaches in an interesting manner so that children enjoy learning.

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 27

To make assessment 'a useful and interesting process', one should be careful about:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 27

The Assessment process should not be boring, or it should be on the basis of only one aspect. The teacher should be careful about using a variety of ways to collect information, about the students learning across scholastic and co-scholastic boundaries. Only scholastic areas should not be focused on assessment. It should also include co-scholastic areas.
Hence, the correct answer is, 'Using a variety of ways to collect information about the students learning across scholastic and co-scholastic boundaries.'

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 28
Buddha attained enlightenment at
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 28

The correct answer is Bodh Gaya.

Key Points

  • Buddha attained enlightenment at Bodh Gaya in Bihar.
  • He attained enlightenment under a peepal tree at Bodh Gaya where he meditated for days.
  • After attaining enlightenment, he came to be known as Buddha or the wise one.
  • Buddha was a Kshatriya and belonged to Sakya gana.

 Thus, we can say that Buddha attained enlightenment at Bodh Gaya.

Additional Information

  • He taught for the first time at Sarnath and passed away at Kusinara.
Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 29

In the villages of Bihar, many farmers do bee-keeping and collect honey to earn extra money. The best time to start bee-keeping is:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 29

The tradition of bee-keeping in Bihar is very old. The period of October to December is considered as the best to start bee-keeping because at that time number of flowering and crop plants is more. So bees will get nectar and pollen easily to increase the production of honey. There was a setback to the bee-keeping industry in the 1980s due to the disease caused by the Thai sacbrood virus.
Hence, the correct answer is, 'October to December.'

Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 30

Find the value of 

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 6 - Question 30

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