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*Answer can only contain numeric values

QUESTION: 1

Calculate V_{CE} in the figure (in volts).

Solution:

First check to see if R_{in (Base)} can be neglected.

=150 x kΩ = 150kΩ

Since 150kΩ is more than 10 times R_{2}. The condition is met and R_{in(base)} can be neglected.

= 6.88 V

Then, V_{E} = V_{B} + VBE

= 6.88 + 0.7

V_{E} = 7.58V

l_{E} = 2.42 mA

From I_{E} we can determine l_{c} and V_{CE
}

and V_{C} = I_{C}R_{C} = 2.42 mA x 2.2kΩ

= 5.32

= 2.26V

The correct answer is: 2.26

*Answer can only contain numeric values

QUESTION: 2

Calculate the minimum value of C_{2} (in μF) if the amplifier operate over a frequency range of 2kHz to 10kHz?

Solution:

R_{E} = 560Ω

X_{C} of the bypass capacitor C_{2} should be

The capacitive value, at the minimum frequency of 2**kHz
**

The correct answer is: 1.42

*Answer can only contain numeric values

QUESTION: 3

If the Q-point is 2 Vand 1 mA with the help of a feedback resistor R_{B}. β = 100, then what is the value of R_{B} in? (Take V_{BE} = 0.7V).

Solution:

The correct answer is: 130

*Answer can only contain numeric values

QUESTION: 4

Calculate the value of V_{CE} (in Volts) for the circuit shown below. (β = 100 and V_{BE }=0.7V).

Solution:

Let us use Thevenin’s theorem

Now, applying **KVL** to Base circuit

= 9.45 μ**A**

l_{C} = 0.945**mA
Now, V _{cc} = I_{c}R_{c} **-

The correct answer is: 6.22

*Answer can only contain numeric values

QUESTION: 5

A npn transistor circuit has ∝ = 0.985. If I_{C} = 2mA then the value of l_{B} (in mA) is?

Solution:

= 0.03 **mA**

The correct answer is: 0.03

*Answer can only contain numeric values

QUESTION: 6

Calculate the collector voltage V_{C} of the transistor circuit should be in the figure :

(given = 0.96, l_{CBO} = 20μA , V_{BE} = 0.3V, R_{B} = 100/kΩ)

Solution:

**Similarly,**

The correct answer is: 4.72

*Answer can only contain numeric values

QUESTION: 7

In the below figure, the minimum value of l_{B} (in mA) required to saturate this transistor if [Neglect V_{CE(sat})].

Solution:

Since,V_{CE(Sat)} is neglected (assume to 0V)

The correct answer is: 50

*Answer can only contain numeric values

QUESTION: 8

In a certain oscillator, A_{v} = 50. The attenuation of the feedback circuit must be?

Solution:

*Answer can only contain numeric values

QUESTION: 9

An amplifier of gain 1000 is made into a feedback amplifier by feeding 9.9% of its output voltage in series with the input opposing. If f_{l} = 20Hz and f_{h} = 200kHz for the amplifier without feedback then due to the feedback what is the new frequency (in kHz)?

Solution:

The correct answer is: 20000

*Answer can only contain numeric values

QUESTION: 10

In the transistor below, base current is 35 μA, V_{BE} = 0.7V, what is the value of R_{B} in kΩ?

Solution:

Using **KVL,**

The correct answer is: 237.1

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