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Co-ordination Compounds - 1 - JEE MCQ


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30 Questions MCQ Test Chemistry for JEE Main & Advanced - Co-ordination Compounds - 1

Co-ordination Compounds - 1 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Co-ordination Compounds - 1 questions and answers have been prepared according to the JEE exam syllabus.The Co-ordination Compounds - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Co-ordination Compounds - 1 below.
Solutions of Co-ordination Compounds - 1 questions in English are available as part of our Chemistry for JEE Main & Advanced for JEE & Co-ordination Compounds - 1 solutions in Hindi for Chemistry for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Co-ordination Compounds - 1 | 30 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Chemistry for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
Co-ordination Compounds - 1 - Question 1
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In the complexes [Fe(H2O)6]3+, [Fe(CN)6]3+, [Fe(C2O4)3]3_ and [FeCl6]3_, more stability is shown by -

Detailed Solution for Co-ordination Compounds - 1 - Question 1

The correct answer is Option C.

More basic and chelate forming ligand stabilises the complex to more extent C2O42- is a bidentate chelating ligand thus stabilises the complex [Fe(C2O4)3]3- to a high extent.

Co-ordination Compounds - 1 - Question 2
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Among the properties (a) reducing (b) oxidising (c) complexing, the set of properties shown by CN_ ion towards metal species is –  

[AIEEE-2004]

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Thus correct option is A

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Co-ordination Compounds - 1 - Question 3
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The value of the 'spin only' magnetic moment for one of the following configurations is 2.84 BM . The correct one is –

[AIEEE-2005]

Detailed Solution for Co-ordination Compounds - 1 - Question 3

Spin only magnetic moment = √(n(n+2)) B.M.

Where n = number of unpaired electron

Given, √(n(n+2)) = 2.84

n(n + 2) = 8.0656

n = 2

In an octahedral complex, for a d4 configuration in a strong field ligand, number of unpaired electrons = 2

Hence A is correct.

Co-ordination Compounds - 1 - Question 4
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In which of the following octahedral complexes of Co (at. no. 27), will the magnitude of D0 be the highest ?
Detailed Solution for Co-ordination Compounds - 1 - Question 4

The correct answer is Option A.
∆о is the magnitude of splitting of d-orbitals in the octahedral field. Strong field ligands cause large splitting of d-orbitals into t2g and eg orbitals where t2g has lower energy than d-orbitals and eg has higher energy than d-orbitals.
Spectrochemical series is the series in which ligands are arranged in the order of their increasing splitting ability. The CN- ligands are at the right most end indicating the high splitting power.

Co-ordination Compounds - 1 - Question 5
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 Which of the following pairs represents linkage isomers ?

[AIEEE-2009]
Detailed Solution for Co-ordination Compounds - 1 - Question 5

The correct answer is Option A
Linkage isomerism is shown by ambidentate ligands like NCS and SCN.
It can  be linked through N( or ) S
∴[Pd(PPh3)(NCS2)] and [Pd(PPh3)2(SCN)2] 

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