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Complete Physics Test - SA II - Class 9 MCQ


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25 Questions MCQ Test - Complete Physics Test - SA II

Complete Physics Test - SA II for Class 9 2024 is part of Class 9 preparation. The Complete Physics Test - SA II questions and answers have been prepared according to the Class 9 exam syllabus.The Complete Physics Test - SA II MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Complete Physics Test - SA II below.
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Complete Physics Test - SA II - Question 1

Work done by centripetal force is

Detailed Solution for Complete Physics Test - SA II - Question 1

When a body moves on a circular path. The force that acts on the revolving body towards the center is called centripetal force. As the force acts as right angle to the direction of motion, so work done is 0.

Complete Physics Test - SA II - Question 2

Crests and troughs are formed in

Detailed Solution for Complete Physics Test - SA II - Question 2

Crests and troughs are formed in transverse wave. The upward movement from mean position is called crest and downward movement is called troughs.

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Complete Physics Test - SA II - Question 3

For what value of ? is work done maximum?

Detailed Solution for Complete Physics Test - SA II - Question 3

Work done when a body moves at an angle to the direction of force is W = Fcos? × s. The value of Cos is maximum for 00. So, work done will be maximum for this angel.

Complete Physics Test - SA II - Question 4

Which wave property determines loudness?

Detailed Solution for Complete Physics Test - SA II - Question 4

Loudness of sound depends upon amplitude. Amplitude is the maximum displacement from mean position.

Complete Physics Test - SA II - Question 5

1k w h =?

Detailed Solution for Complete Physics Test - SA II - Question 5

1 kwH =1000 W × 60 × 60 s= 3600000 J = 3.6 × 106  J. one watt is equal to one joule per second.

Complete Physics Test - SA II - Question 6

A source produces 20 crests and 20 troughs in 0.2 second. Find the frequency of the wave.

Detailed Solution for Complete Physics Test - SA II - Question 6

Time–period = 0.2/20 = 0.01 second. Frequency = 1/time–period = 1/0.01 = 100Hz.

Complete Physics Test - SA II - Question 7

A certain household has consumed 250 units of energy during a month. How much energy is this in joules?

Detailed Solution for Complete Physics Test - SA II - Question 7

1 unit (Kw-H) = 3.6×106 joule. Therefore, 250 units = 250 × 3.6 × 106 joule = 9 × 108 Joule.

Complete Physics Test - SA II - Question 8

“Wave motion shifts mass from one region to another” The above statement is

Detailed Solution for Complete Physics Test - SA II - Question 8

Wave motion shifts wave energy from one region to another region. Mass is not transferred during wave motion.

Complete Physics Test - SA II - Question 9

9800 joule of energy was spent to raise a mass of 50kg, the mass was raised to a height of

Detailed Solution for Complete Physics Test - SA II - Question 9

Potential energy = mgh, here, P.E = 9800 j. mass = 50kg, g=9.8m/s2. Therefore, 9800= 50×9.8×h, h= 9800/50×9.8= 20m.

Complete Physics Test - SA II - Question 10

Match the following with correct response.

(1) A moving disturbance
(2) Propagation require material medium
(3) Particles vibrates perpendicular to the
(4) Back and forth motion

(A) Mechanical waves
(B) Oscillatory motion
(C) Transverse waves direction of wave propagation
(D) Wave

Complete Physics Test - SA II - Question 11

1 W. S = ________?

Detailed Solution for Complete Physics Test - SA II - Question 11

1 watt second (W.S) = 1 J/s×s joule.

Complete Physics Test - SA II - Question 12

X – rays, light rays are electromagnetic waves is a

Detailed Solution for Complete Physics Test - SA II - Question 12

X-rays, light rays are electrostatic waves. These waves do not require material medium for its propagation.

Complete Physics Test - SA II - Question 13

1 meV (mega electron volt) is equal to

Detailed Solution for Complete Physics Test - SA II - Question 13

Electron volt is an unit of energy. One electron volt is equal to 1.6 × 10−19 joule.

One mega electron = 1.6×10−19 joule × 100000 = 1.6×10−13 joules.

Complete Physics Test - SA II - Question 14

Sound wave is a

Complete Physics Test - SA II - Question 15

9800 joule of energy was spent to raise a mass of 50kg, the mass was raised to a height of

Detailed Solution for Complete Physics Test - SA II - Question 15

Potential energy = mgh, here, P.E = 9800 j. mass = 50kg, g=9.8m/s.

Therefore, 9800=50×9.8×h, h= 9800/50×9.8 = 20m.

Complete Physics Test - SA II - Question 16

The maximum displacement of the particle of the mean from its mean position is called the

Detailed Solution for Complete Physics Test - SA II - Question 16
Amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. For a longitudinal wave, such as a sound wave, amplitude is measured by the maximum displacement of a particle from its position of equilibrium.
Complete Physics Test - SA II - Question 17

A machine does 2000 joule of work in 400 seconds. What is the power of machine?

Detailed Solution for Complete Physics Test - SA II - Question 17

Power = work done / time taken, here, work done = 2000 joule, time = 400 s. power = 2000j/400s = 5 j/s or 5w.

Complete Physics Test - SA II - Question 18

Calculate the wavelength of a sound wave whose frequency is 820Hz and speed is 440m/s in a given medium.

Detailed Solution for Complete Physics Test - SA II - Question 18

Wavelength= wave speed / frequency,

wavelength=440ms−1 /840Hz = 0.53m.

Complete Physics Test - SA II - Question 19

Calculate the time taken by a 150 w bulb of consuming 3000 joule of energy

Complete Physics Test - SA II - Question 20

A boat at anchor is rocked by waves whose consecutive crests are 100m apart. The wave velocity of the moving crests is 20m|s. What is the frequency of rocking of the boat?

Detailed Solution for Complete Physics Test - SA II - Question 20

Distance between two consecutive crests is called wavelength. Here, wavelength= 100 m, wave velocity = 20m/s. frequency = wave velocity/ wavelength. Frequency= 20/100 = 0.2Hz

Complete Physics Test - SA II - Question 21

What is the work done to be done to increase the velocity of a car from 30kmh−1 to 60 kmh−1 . if the mass of the car is 1500kg?

Detailed Solution for Complete Physics Test - SA II - Question 21

Initial velocity (u) = 30 km/h = 30×5/18  = 25/3 m/s. final velocity (v) =60 = 50/3 m/s.

mass = 1500 kg. work done = change in kinetic energy 

Complete Physics Test - SA II - Question 22

A boat at anchor is rocked by waves whose consecutive crests are 100m apart. The wave velocity of the moving crests is 20m|s. What is the frequency of rocking of the boat?

Detailed Solution for Complete Physics Test - SA II - Question 22

Distance between two consecutive crests is called wavelength. Here, wavelength= 100 m, wave velocity = 20m/s.

frequency = wave velocity/ wavelength. Frequency= 20/100 = 0.2Hz.

Complete Physics Test - SA II - Question 23

What is the force required to lift a block of mass 2m?

Detailed Solution for Complete Physics Test - SA II - Question 23

Force is the product of mass and acceleration due to gravity. Mass = 2m and acceleration due to gravity =g m/s2.

Force = 2m ×g = 2mg.

Complete Physics Test - SA II - Question 24

In which of the following speed of sound is maximum?

Detailed Solution for Complete Physics Test - SA II - Question 24

The speed of sound is faster in solid medium in comparison to liquid and gaseous medium. Aluminium is solid and metal, so, the speed of sound will be maximum in it.

Complete Physics Test - SA II - Question 25

A body of mass 20kg climbs up 20 steps of the stairs in 20 seconds. If each step is 20cm high. What is the power used in climbing the stairs (g=10m/s2)

Detailed Solution for Complete Physics Test - SA II - Question 25

Mass = 20 kg, height = 20×20/100 m = 4m, time taken = 20 s. power = work done/ time, power = mgh/t. = 20×10×4/20  watt = 40 w.

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