Crystals NAT Level – 2

10 Questions MCQ Test Solid State Physics, Devices & Electronics | Crystals NAT Level – 2

This mock test of Crystals NAT Level – 2 for IIT JAM helps you for every IIT JAM entrance exam. This contains 10 Multiple Choice Questions for IIT JAM Crystals NAT Level – 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Crystals NAT Level – 2 quiz give you a good mix of easy questions and tough questions. IIT JAM students definitely take this Crystals NAT Level – 2 exercise for a better result in the exam. You can find other Crystals NAT Level – 2 extra questions, long questions & short questions for IIT JAM on EduRev as well by searching above.
*Answer can only contain numeric values

The probability that a state which is 0.2eV above the fermi energy in a metal atom at 700K is?


E - Ef = 0.2 eV
kB = 8.62 x 10-5 eVK-1
T = 700K

P = 0.036
The correct answer is: 0.036

*Answer can only contain numeric values

Be has hexagonal closed packed structure with smaller lattice parameter equal to 2.29. Concentration of electron in Be crystal is in terms of 1029 m-3 .


Here a = 2.29 
for hexagonal close packing

There are two atoms in primitive cell and each atom carries 4 electrons.

The correct answer is: 8.15

*Answer can only contain numeric values

A copper wire of uniform cross-sectional area 10 x 10-6 m-2 carries a current of 1 Assuming that each copper atom contributes one electron to the electron gas, the drift velocity of free electron in units of µm/sec is :
 of copper is 8.94 x 103 kg/m3 and its atomic mass is 1.05 x 10-25 kg).


The correct answer is: 74

*Answer can only contain numeric values

Consider a crystal of fee structure. The density of the crystal is 8.96 glcm3 and atomic weight is 63.5. Then what is the lattice constant for the crystal (in )?


Lattice constant 

The correct answer is: 3.61

*Answer can only contain numeric values

The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. The smallest angle of Bragg scattering for 0.03 nm X -ray is (in degrees)


- For constructive interference, we must have                 



=1×0.3×10−10 / 2×0.3×10-9



=0.05×180/π = 2.86degree

*Answer can only contain numeric values

Sodium contains 2.54 x1022   free electrons per cm3 ( given = 6.63 x 10 -34 J-s, m= 9 .11 x 10-31 kg , kB = 1.38 x 10-23 JIK and 1eV = 1.6 x 10-19 J ) , then Fermi D 4 temperature is given in terms of 104 K as?


We know that 


The correct answer is: 3.6

*Answer can only contain numeric values

In a powder diffraction pattern recorded from a face-centred cubic sample using X- rays. The first peak appears at 30°. The second peak will appear at what angle (degrees)


For 2nd peak [2 0 0],

The correct answer is: 35.3

*Answer can only contain numeric values

Masses of ionic radii of Na+ and CI– in NaCI crystals are 22.99 amu, 0.98A and 35.45 amu, 1.82A respectively. What is the packing fraction of NaCI?


Lattice parameter a = 
a = 2 [0.98 + 1.82] 
a = 5.6A
Each unit cell contains 4 atoms.
Packing fraction = 
Packing fraction = 
Packing fraction = 0.66
The correct answer is: 0.66

*Answer can only contain numeric values

Given that density of sodium is 0.971 g/cm3 and atomic weight is 23. If h = 6.63 * 10¯34 Js, mass of electron = 9.11 x 10-31 kg and Avogadro’s number is 6.02 x 1023 atoms/mol. Assuming each sodium atom contribute one electron to the electron gas. What is the electron density in units of 1028 Im3 ?


Electron density of sodium  

The correct answer is: 2.54

*Answer can only contain numeric values

Packing fraction of diamond cubic crystal structure is ____ % ?


Number of atoms in diamond crystal
Packing fraction 

= 0.34
= 34%
The correct answer is: 34

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