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Current Electricity MCQ Level - 1 - Physics MCQ


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10 Questions MCQ Test Topic wise Tests for IIT JAM Physics - Current Electricity MCQ Level - 1

Current Electricity MCQ Level - 1 for Physics 2024 is part of Topic wise Tests for IIT JAM Physics preparation. The Current Electricity MCQ Level - 1 questions and answers have been prepared according to the Physics exam syllabus.The Current Electricity MCQ Level - 1 MCQs are made for Physics 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Current Electricity MCQ Level - 1 below.
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Current Electricity MCQ Level - 1 - Question 1

The electric cell does 5 Joule of work in carrying 10 C of charge around a close electric circuit. The electromotive force of the cell is :

Detailed Solution for Current Electricity MCQ Level - 1 - Question 1

We know, E = W/Q where W = 5 joule, Q = 10 C

The correct answer is: 0.5V

Current Electricity MCQ Level - 1 - Question 2

An energy source will supply a constant current into the load if its internal resistance is

Detailed Solution for Current Electricity MCQ Level - 1 - Question 2

In case of an ideal battery, the internal resistance is zero.
The correct answer is: zero

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Current Electricity MCQ Level - 1 - Question 3

When current is passed through a wire heat is produced due to

Detailed Solution for Current Electricity MCQ Level - 1 - Question 3

The correct answer is: collision of conduction electron with atoms.

Current Electricity MCQ Level - 1 - Question 4

If a good conductor is connected between a point of an electric circuit and the ground.

Detailed Solution for Current Electricity MCQ Level - 1 - Question 4

The correct answers are: the potential of the point is the same as that of the earth., current flows through the conductor only if one more point of the same circuit with some resistance between the two is connected to the ground

Current Electricity MCQ Level - 1 - Question 5

When a wire of uniform cross-section a, length l and resistance is bent into a complete circle, resistance between any two of diametrically opposite points will be :

Detailed Solution for Current Electricity MCQ Level - 1 - Question 5

The two half of the circle behave like two resistance

Both resistance  R1  and  R2  are in parallel combination

The correct answer is: R/4

Current Electricity MCQ Level - 1 - Question 6

A heater coil is cut into two equals parts and only one part is now used in the heater. The heat generated will now be :

Detailed Solution for Current Electricity MCQ Level - 1 - Question 6

We know, the relation


When R  is halved, then

The correct answer is: doubled

Current Electricity MCQ Level - 1 - Question 7

A steady current flows in a metallic conductor of non-uniform cross-section. The quantity/quantities constant along the length of the conductor is/are

Detailed Solution for Current Electricity MCQ Level - 1 - Question 7

Drift speed  

Since A  is not constant therefore vd  is not constant.
The correct answer is: current only

Current Electricity MCQ Level - 1 - Question 8

The electric resistance of a certain wire of iron is  R. If its length and radius are both doubled then

Detailed Solution for Current Electricity MCQ Level - 1 - Question 8

The correct answer is: the resistance will be halved and the specific resistance will remain unchanged

Current Electricity MCQ Level - 1 - Question 9

We are able to obtain fairly large current in a conductor because.

Detailed Solution for Current Electricity MCQ Level - 1 - Question 9

The correct answer is: the number density of free electron is very high and this can compensate for the low values of the electron drift speed and the very small magnitude of the electron charge

Current Electricity MCQ Level - 1 - Question 10

N  identical cells each of emf E  and internal resistance r, are joined in series to from a closed circuit. One cell A  is joined with reverse polarity. The potential difference across each cell except A  is

Detailed Solution for Current Electricity MCQ Level - 1 - Question 10

Number of cells = n
EMF of each cell = ε
and Internal resistance of each cell =r
One cell is joined in reverse.
∴ Total EMF = n⋅ε − 2⋅ε
Current in the circuit, I = (n⋅ε − 2⋅ε)/n⋅r
Potential difference V = ε - I⋅r
ε -[ε⋅(n-2)/n⋅r]⋅r
= ε -[ε⋅(n-2)/n]
= [n⋅ε - n⋅ε + 2⋅ε]/n
= 2⋅ε/n

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